Question Number 152439 by fotosy2k last updated on 28/Aug/21 | ||
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Commented by fotosy2k last updated on 28/Aug/21 | ||
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$${help}\:{me} \\ $$ | ||
Commented by alisiao last updated on 29/Aug/21 | ||
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$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{\:\sqrt{{n}^{\mathrm{5}} }}=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{{n}^{\frac{\mathrm{5}}{\mathrm{2}}} }\:\Rightarrow\:{p}=\frac{\mathrm{5}}{\mathrm{2}}>\mathrm{1} \\ $$$${is}\:{Divergent}\:{by}\:{p}−{series} \\ $$$$ \\ $$ | ||
Commented by fotosy2k last updated on 30/Aug/21 | ||
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$${thank}\:{you} \\ $$ | ||