Question Number 152365 by mathdanisur last updated on 27/Aug/21
Answered by ghimisi last updated on 28/Aug/21
$${a}={x}+{y};{b}={y}+{z};{c}={x}+{z} \\ $$$${p}={x}+{y}+{z};{q}={ab}+{bc}+{ac};{r}={abc} \\ $$$$\Leftrightarrow....\Leftrightarrow{p}^{\mathrm{3}} +\mathrm{9}{r}\geqslant\mathrm{4}{pq}\Leftrightarrow{schur} \\ $$
Commented by mathdanisur last updated on 28/Aug/21
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{Ser}\:\mathrm{nice} \\ $$