Question Number 148189 by abdurehime last updated on 25/Jul/21 | ||
![]() | ||
Commented by abdurehime last updated on 25/Jul/21 | ||
![]() | ||
$$\mathrm{help}\:\mathrm{me} \\ $$ | ||
Answered by Olaf_Thorendsen last updated on 26/Jul/21 | ||
![]() | ||
$$\left(\mathrm{a}\right)\:\mathrm{is}\:\mathrm{false}. \\ $$$$\mathrm{For}\:{n}\:=\:\mathrm{1}\:\mathrm{for}\:\mathrm{example},\:{P}\left(\mathrm{1}\right)\:=\:−\frac{\mathrm{1}}{\mathrm{3}}\:\notin\mathbb{Z} \\ $$$$\left(\mathrm{b}\right)\:\mathrm{is}\:\mathrm{true} \\ $$$$\mathrm{For}\:{n}\:=\:\mathrm{3}\:\mathrm{for}\:\mathrm{example},\:{P}\left(\mathrm{3}\right)\:=\:\mathrm{3}\:\in\mathbb{Z} \\ $$$$ \\ $$ | ||
Commented by abdurehime last updated on 26/Jul/21 | ||
![]() | ||
$$\mathrm{how}\:\mathrm{does}\:\mathrm{p}\left(\mathrm{0}\right)=−\frac{\mathrm{1}}{\mathrm{3}}??\:\:\mathrm{but}\:\mathrm{it}\:\mathrm{is}\:−\mathrm{2} \\ $$ | ||
Commented by Olaf_Thorendsen last updated on 26/Jul/21 | ||
![]() | ||
$$\mathrm{Sorry}\:\mathrm{sir}.\:\mathrm{It}'\mathrm{s}\:{P}\left(\mathrm{1}\right). \\ $$ | ||