Question Number 145436 by mathdanisur last updated on 04/Jul/21 | ||
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Commented by justtry last updated on 05/Jul/21 | ||
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Commented by mathdanisur last updated on 05/Jul/21 | ||
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$${thanks}\:{Ser},\:{but}\:{wrong} \\ $$$$\left(\mathrm{1}+{a}\right)^{{k}} <=\mathrm{1}+{ka}\:\:{if}\:\:{k}\in\left[\mathrm{0};\mathrm{1}\right] \\ $$ | ||