Question Number 143993 by cherokeesay last updated on 20/Jun/21
Answered by mr W last updated on 20/Jun/21
Commented by mr W last updated on 20/Jun/21
$$\left(\mathrm{5}−{r}\right)^{\mathrm{2}} −{r}^{\mathrm{2}} =\mathrm{3}^{\mathrm{2}} \\ $$$$\Rightarrow{r}=\frac{\mathrm{8}}{\mathrm{5}} \\ $$$${x}^{\mathrm{2}} =\mathrm{2}{r}^{\mathrm{2}} +\mathrm{2}{r}^{\mathrm{2}} ×\frac{{r}}{\mathrm{5}−{r}}=\mathrm{2}×\frac{\mathrm{8}^{\mathrm{2}} }{\mathrm{17}} \\ $$$${x}=\frac{\mathrm{8}\sqrt{\mathrm{34}}}{\mathrm{17}} \\ $$
Commented by cherokeesay last updated on 20/Jun/21
$${thank}\:{you}\:{sir}. \\ $$$${great}\:{work}\:! \\ $$