Question Number 142341 by mohammad17 last updated on 30/May/21 | ||
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Commented by mohammad17 last updated on 30/May/21 | ||
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$${how}\:{can}\:{solve}\:{this} \\ $$ | ||
Answered by Dwaipayan Shikari last updated on 30/May/21 | ||
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$${A}.{A}={A}^{\mathrm{2}} {cos}\mathrm{0}°=\mid{A}\mid^{\mathrm{2}} \:\: \\ $$$$\:\:\left(\:\:{A}\:{and}\:{A}\:{are}\:{parallel}\:{because}\:{they}\:{are}\:{same}\right) \\ $$ | ||