Question Number 140915 by mathdanisur last updated on 14/May/21 | ||
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Commented by mr W last updated on 14/May/21 | ||
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$${question}\:{is}\:{wrong}! \\ $$$$\mathrm{12}+\mathrm{18}+\mathrm{144}+\mathrm{12}=\mathrm{186}>\mathrm{180}! \\ $$ | ||
Commented by mathdanisur last updated on 14/May/21 | ||
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$${Sorry}\:{dear}\:{Sir},\:\mathrm{144}°\:{no},\:\mathrm{114}° \\ $$ | ||
Answered by mr W last updated on 14/May/21 | ||
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$$\frac{{CB}}{{x}}=\frac{\mathrm{sin}\:\left(\mathrm{18}+\mathrm{114}\right)}{\mathrm{sin}\:\mathrm{114}}=\frac{\mathrm{sin}\:\mathrm{48}}{\mathrm{sin}\:\mathrm{66}}=\frac{\mathrm{sin}\:\mathrm{48}}{\mathrm{cos}\:\mathrm{24}}=\mathrm{2}\:\mathrm{sin}\:\mathrm{24} \\ $$$$\frac{{y}}{{CB}}=\frac{\mathrm{sin}\:\left(\mathrm{18}+\mathrm{12}\right)}{\mathrm{sin}\:\left(\mathrm{18}+\mathrm{12}+\mathrm{114}+\mathrm{12}\right)}=\frac{\mathrm{sin}\:\mathrm{30}}{\mathrm{sin}\:\mathrm{24}} \\ $$$$\frac{{y}}{{x}}=\frac{\mathrm{2}\:\mathrm{sin}\:\mathrm{24}×\mathrm{sin}\:\mathrm{30}}{\mathrm{sin}\:\mathrm{24}}=\mathrm{1} \\ $$ | ||
Commented by mathdanisur last updated on 15/May/21 | ||
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$${cool}\:{dear}\:{Sir}\:{thakyou} \\ $$ | ||