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Question Number 140143 by I want to learn more last updated on 04/May/21

Commented by mr W last updated on 04/May/21

(a)  F_W =12×tan 30°≈6.9 N  (b)  μ=((12)/(40))=0.3

$$\left({a}\right) \\ $$$${F}_{{W}} =\mathrm{12}×\mathrm{tan}\:\mathrm{30}°\approx\mathrm{6}.\mathrm{9}\:{N} \\ $$$$\left({b}\right) \\ $$$$\mu=\frac{\mathrm{12}}{\mathrm{40}}=\mathrm{0}.\mathrm{3} \\ $$

Commented by I want to learn more last updated on 04/May/21

I really appreciate sir. God bless you

$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you} \\ $$

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