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Question Number 13983 by wodus103 last updated on 26/May/17
Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 26/May/17
$${x}={y}=\mathrm{1} \\ $$
Commented by ajfour last updated on 26/May/17
$$\mathrm{3}\left({x}^{\mathrm{2}} −\mathrm{1}\right)+\mathrm{7}\left({x}−{y}\right)=\mathrm{0} \\ $$$$\mathrm{5}\left({x}^{\mathrm{3}} −\mathrm{1}\right)+\left({x}^{\mathrm{2}} −{y}\right)+\mathrm{4}\left({x}^{\mathrm{2}} −{y}^{\mathrm{2}} \right)=\mathrm{0} \\ $$$$\mathrm{9}\left({x}^{\mathrm{4}} −\mathrm{1}\right)+\mathrm{9}\left({x}^{\mathrm{3}} −{y}\right)+\mathrm{8}\left({x}−{y}^{\mathrm{3}} \right)=\mathrm{0} \\ $$$${x}={y}=\mathrm{1},\:{i}\:{understand} \\ $$$${any}\:{other}\:{values}..? \\ $$