Question Number 134074 by EDWIN88 last updated on 27/Feb/21 | ||
![]() | ||
Commented by EDWIN88 last updated on 27/Feb/21 | ||
![]() | ||
$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{r}\:=\:\mathrm{10}\:\mathrm{cm} \\ $$ | ||
Answered by bramlexs22 last updated on 27/Feb/21 | ||
![]() | ||
$$\mathrm{blue}\:\mathrm{area}\:=\:\mathrm{2}\left(\frac{\pi.\mathrm{5}^{\mathrm{2}} }{\mathrm{4}}−\frac{\mathrm{5}^{\mathrm{2}} }{\mathrm{2}}\right) \\ $$$$\:=\:\frac{\mathrm{25}\pi}{\mathrm{2}}−\:\mathrm{25}\:\approx\:\mathrm{14}.\mathrm{2699} \\ $$ | ||