Question Number 13349 by tawa tawa last updated on 19/May/17
Answered by ajfour last updated on 19/May/17
$${for}\:{x}\neq\frac{\mathrm{2}}{{a}}\:,{we}\:{have} \\ $$$$\mathrm{24}{x}^{\mathrm{2}} +\mathrm{25}{x}−\mathrm{47}=−\left({ax}−\mathrm{2}\right)\left(\mathrm{8}{x}+\mathrm{3}\right)−\mathrm{53} \\ $$$$\mathrm{24}{x}^{\mathrm{2}} +\mathrm{25}{x}−\mathrm{47}=−\mathrm{8}{ax}^{\mathrm{2}} +\left(\mathrm{16}−\mathrm{3}{a}\right){x}+\mathrm{6}−\mathrm{53} \\ $$$${comparing}\:{coefficients}\:{of}\:{x}^{\mathrm{2}} \: \\ $$$${or}\:{x}\:{we}\:{see}\:\:\:\boldsymbol{{a}}=−\mathrm{3} \\ $$$$\left.{answer}\:{is}\:\:\:{B}\right)\:\:−\mathrm{3}\:\:\:. \\ $$
Commented by tawa tawa last updated on 19/May/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$