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Question Number 132265 by Salman_Abir last updated on 12/Feb/21 | ||
Answered by physicstutes last updated on 12/Feb/21 | ||
$$\mathrm{m}\:=\:\mathrm{4}\:\mathrm{kg},\:{k}\:=\:\mathrm{100}\:\mathrm{Nm}^{−\mathrm{1}} \\ $$$$\:{T}\:=\:\mathrm{2}\pi\sqrt{\frac{{m}}{{k}}}\:=\:\mathrm{2}\pi\sqrt{\frac{\mathrm{4}}{\mathrm{100}}}\: \\ $$$$\Rightarrow\:{T}\:=\:\frac{\mathrm{4}\pi}{\mathrm{25}}\:\mathrm{s} \\ $$$${f}\:=\:\frac{\mathrm{1}}{{T}}\:=\:\frac{\mathrm{25}}{\mathrm{4}\pi}\:\mathrm{Hz} \\ $$$${T}\:=\:\frac{\mathrm{2}\pi}{\omega}\:\Rightarrow\:\omega\:=\:\frac{\mathrm{2}\pi}{{T}}\:\:=\:\mathrm{2}\pi\:.\:\frac{\mathrm{25}}{\mathrm{4}\pi}\:=\:\frac{\mathrm{25}}{\mathrm{2}}\:\mathrm{rad}/\mathrm{s} \\ $$ | ||