Question Number 129159 by gowsalya last updated on 13/Jan/21
Answered by TheSupreme last updated on 13/Jan/21
$$\int\left({e}^{{i}\theta} +{e}^{−{i}\theta} \right){e}^{{i}\theta} /\mathrm{2}=\frac{{e}^{{i}\theta} }{\mathrm{4}{i}}+\frac{\theta}{\mathrm{2}}+{c} \\ $$$$\int_{\mathrm{0}} ^{\mathrm{2}\pi} ...=\pi \\ $$