Question Number 126722 by 0731619177 last updated on 23/Dec/20 | ||
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Answered by mahdipoor last updated on 23/Dec/20 | ||
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$${x}=\mathrm{5\begin{cases}{{x}!!!−\mathrm{10}>\mathrm{0}}\\{\mathrm{2}{x}−\mathrm{10}=\mathrm{0}}\end{cases}} \\ $$$${l}\underset{{x}\rightarrow\mathrm{5}^{−} } {{i}m}\:\frac{{x}!!!−\mathrm{10}}{\mathrm{2}{x}−\mathrm{10}}=−\infty \\ $$$${l}\underset{{x}\rightarrow\mathrm{5}^{+} } {{i}m}\:\frac{{x}!!!−\mathrm{10}}{\mathrm{2}{x}−\mathrm{10}}=+\infty \\ $$$$ \\ $$$$ \\ $$ | ||
Commented by 0731619177 last updated on 23/Dec/20 | ||
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$${thanks}\:{sir} \\ $$ | ||