Question Number 123922 by help last updated on 29/Nov/20
Answered by liberty last updated on 29/Nov/20
$${y}={p}\left({x}−\mathrm{3}\right)^{\mathrm{2}} +\mathrm{1}\:=\:{px}^{\mathrm{2}} −\mathrm{6}{px}+\mathrm{9}{p}+\mathrm{1} \\ $$$$\begin{cases}{{p}=−{a}}\\{{b}=−\mathrm{6}{p}\:}\\{{c}=\mathrm{9}{p}+\mathrm{1}}\end{cases} \\ $$
Commented by help last updated on 29/Nov/20
$${value}\:{of}\:{p}? \\ $$
Commented by help last updated on 29/Nov/20
$${from}\:{here}\:{we}\:{can}\:{say}\:{option}\:{A} \\ $$$${is}\:{valid}...{i}\:{solve}\:{with}\:{graph}\:{tho} \\ $$$${thanks} \\ $$