Question Number 122055 by I want to learn more last updated on 13/Nov/20
Answered by mr W last updated on 13/Nov/20
$${AB}=\frac{\mathrm{2}×\mathrm{10}\pi}{\mathrm{4}}=\mathrm{5}\pi \\ $$$${PR}=\mathrm{10} \\ $$$${AP}={AO}−{OP} \\ $$$${BR}={BO}−{OR} \\ $$$${AP}+{BR}=\mathrm{2}×\mathrm{10}−\left({OP}+{OR}\right) \\ $$$$=\mathrm{20}−\frac{\mathrm{26}}{\mathrm{2}}=\mathrm{7} \\ $$$${AB}+{BR}+{RP}+{PA}=\mathrm{5}\pi+\mathrm{10}+\mathrm{7}=\mathrm{17}+\mathrm{5}\pi \\ $$$$\Rightarrow\left({C}\right) \\ $$
Commented by I want to learn more last updated on 13/Nov/20
$$\mathrm{Thanks}\:\mathrm{sir}. \\ $$
Commented by TANMAY PANACEA last updated on 13/Nov/20
$${sir}\:{why}\:{PR}=\mathrm{10} \\ $$
Commented by mr W last updated on 13/Nov/20
$${PR}={OQ}={radius}=\mathrm{10} \\ $$