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Question Number 121829 by bemath last updated on 12/Nov/20 | ||
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Answered by mr W last updated on 12/Nov/20 | ||
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$${no}\:{empty}:\:\mathrm{3}!=\mathrm{6} \\ $$$${one}\:{empty}:\:\mathrm{3}×\mathrm{2}×\mathrm{3}=\mathrm{18} \\ $$$$\Rightarrow{totally}\:\mathrm{24} \\ $$ | ||
Commented by bemath last updated on 12/Nov/20 | ||
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$${why}\:{sir}? \\ $$ | ||
Commented by mr W last updated on 12/Nov/20 | ||
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$${no}\:{box}\:{empty}: \\ $$$${to}\:{arrange}\:{three}\:{balls}\:{there}\:{are}\:\mathrm{3}!\:{ways}. \\ $$$$ \\ $$$${one}\:{box}\:{empty}: \\ $$$${to}\:{select}\:{the}\:{empty}\:{box}\:{there}\:{are}\:\mathrm{3} \\ $$$${ways}.\:{to}\:{select}\:{the}\:{remaining}\:{box} \\ $$$${which}\:{contains}\:{one}\:{ball}\:{there}\:{are}\:\mathrm{2} \\ $$$${ways}.\:{to}\:{select}\:{one}\:{ball}\:{to}\:{put}\:{it}\:{into} \\ $$$${this}\:{box}\:{there}\:{are}\:\mathrm{3}\:{ways}. \\ $$$$\Rightarrow\mathrm{3}×\mathrm{2}×\mathrm{3}=\mathrm{18}\:{ways}. \\ $$ | ||
Commented by bemath last updated on 12/Nov/20 | ||
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$${thank}\:{you}\:{sir}\: \\ $$ | ||