Question Number 121612 by Khalmohmmad last updated on 10/Nov/20 | ||
Commented by MJS_new last updated on 10/Nov/20 | ||
$$\mathrm{the}\:\mathrm{problem}\:\mathrm{why}\:\mathrm{you}\:\mathrm{got}\:\mathrm{no}\:\mathrm{answer}\:\mathrm{might} \\ $$$$\mathrm{be}\:\mathrm{that}\:\mathrm{nobody}\:\mathrm{knows}\:\mathrm{what}\:``\mathrm{the}\:\left({a}_{\mathrm{4}} =?\right)'' \\ $$$$\mathrm{means}.\:\mathrm{your}\:\mathrm{question}\:\mathrm{is}\:\mathrm{like}\:\mathrm{this}\:\mathrm{one}: \\ $$$${the}\:{ship}\:{is}\:\mathrm{25}{m}\:{long}.\:{how}\:{old}\:{is}\:{Peter}? \\ $$ | ||
Commented by Study last updated on 10/Nov/20 | ||
$${for}\:{example}\:\:{p}\left({x}\right)=\mathrm{3}{x}^{\mathrm{2}} +\mathrm{4}{x}^{\mathrm{3}} −\mathrm{2} \\ $$$${a}_{\mathrm{2}} =\mathrm{2}\:\:,\:\:{a}_{\mathrm{3}} =\mathrm{4}\:,\:\:\:{a}_{\mathrm{0}} =−\mathrm{2}\: \\ $$ | ||
Commented by MJS_new last updated on 10/Nov/20 | ||
$$\mathrm{no}.\:\mathrm{you}'\mathrm{d}\:\mathrm{have}\:\mathrm{to}\:\mathrm{define}\:{a}_{{n}} \:\mathrm{first}.\:\mathrm{i}.\mathrm{e}. \\ $$$${a}_{{n}} ={p}\left({n}\right)\:\mathrm{with}\:{p}\left({x}\right)=\mathrm{3}{x}^{\mathrm{2}} +\mathrm{4}{x}^{\mathrm{3}} −\mathrm{2} \\ $$$$\mathrm{then}\:\mathrm{it}'\mathrm{s}\:\mathrm{clear}. \\ $$$$\mathrm{but}\:{a}_{{n}} ={p}\left({x},\:{y}\right)\:??? \\ $$ | ||