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Question Number 106508 by Learner-123 last updated on 05/Aug/20 | ||
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Commented by JDamian last updated on 05/Aug/20 | ||
The 5 A current flows through the 30 Ohm resistor. Then the voltage at P is the sum of the voltage at that resistor (5×30=150) and the 5V from the DC voltage source. | ||
Commented by Learner-123 last updated on 05/Aug/20 | ||
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$${Could}\:{someone}\:{help}\:{me}\:{in}\:{finding} \\ $$$${V}_{{TH}} \:?\:\left(\:{I}\:{didn}'{t}\:{understand}\:{the}\:{sol}^{{n}} !\right) \\ $$ | ||
Commented by Learner-123 last updated on 05/Aug/20 | ||
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$${sorry},{it}\:{was}\:{a}\:{typo}... \\ $$$${what}\:{if}\:{I}\:{do}\:{V}_{{th}} =\mathrm{20}×\mathrm{5}=\mathrm{100}{V}\:{then} \\ $$$${why}\:{it}'{s}\:{wrong}? \\ $$ | ||
Commented by JDamian last updated on 05/Aug/20 | ||
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$${Where}\:{do}\:{you}\:{get}\:{that}\:\mathrm{200}\:{from}? \\ $$$${The}\:{current}\:{from}\:{the}\:{voltage}\:{source}\:{is} \\ $$$${forced}\:{by}\:{the}\:{current}\:{source}\:\left(\mathrm{5}{A}\right). \\ $$$${Do}\:{you}\:{know}\:{what}\:{a}\:{current}\:{source}\:{is}? \\ $$ | ||
Commented by JDamian last updated on 05/Aug/20 | ||
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$$\left.{Because}:\:\mathrm{1}{st}\right)\:{it}\:{is}\:{incomplete}.\:{V}_{{th}} \:{is}\:{the} \\ $$$${sum}\:{of}\:{the}\:{voltage}\:{of}\:{the}\:{resistor}\:{and}\:\boldsymbol{{the}} \\ $$$$\left.\boldsymbol{{voltage}}\:\boldsymbol{{of}}\:\boldsymbol{{the}}\:\boldsymbol{{current}}\:\boldsymbol{{source}}.\:\mathrm{2}{nd}\right) \\ $$$${those}\:\mathrm{100}{V}\:{you}\:{mention}\:{are}\:{actually}\: \\ $$$$−\mathrm{100}{V}. \\ $$ | ||
Commented by Learner-123 last updated on 05/Aug/20 | ||
thank you sir!☺️ | ||