Question Number 103393 by otchereabdullai@gmail.com last updated on 14/Jul/20 | ||
Answered by som(math1967) last updated on 14/Jul/20 | ||
$$\mathrm{x}+\mathrm{y}+\mathrm{r}=\mathrm{110}° \\ $$$$\mathrm{x}+\mathrm{2x}+\mathrm{2x}=\mathrm{110}\:\:\bigstar \\ $$$$\mathrm{5x}=\mathrm{110} \\ $$$$\mathrm{x}=\mathrm{22}°\:\mathrm{ans} \\ $$$$\bigstar\:\because\mathrm{2x}=\mathrm{r}=\mathrm{y} \\ $$ | ||
Commented by otchereabdullai@gmail.com last updated on 14/Jul/20 | ||
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}! \\ $$ | ||
Answered by bramlex last updated on 15/Jul/20 | ||
Commented by bramlex last updated on 15/Jul/20 | ||
$$\Leftrightarrow\mathrm{x}+\mathrm{r}+\mathrm{y}+\mathrm{70}^{\mathrm{o}} \:=\mathrm{180}^{\mathrm{o}} \\ $$$$\Leftrightarrow\mathrm{x}+\mathrm{2x}+\mathrm{2x}\:=\:\mathrm{110}^{\mathrm{o}} \\ $$$$\Rightarrow\:\mathrm{5x}\:=\:\mathrm{110}^{\mathrm{o}} \:\Rightarrow\mathrm{x}\:=\:\frac{\mathrm{110}^{\mathrm{o}} }{\mathrm{5}}=\:\mathrm{22}^{\mathrm{o}} \:\blacksquare \\ $$ | ||