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Question Number 214293 by muallimRiyoziyot last updated on 04/Dec/24

P(x) ⋮(x^2 +3) mod(5x−1) P(x) ⋮(x−2) mod(16) P(x) ⋮(x^2 +3)(x−2) mod(?)

$${P}\left({x}\right)\:\:\:\:\:\:\vdots\left({x}^{\mathrm{2}} +\mathrm{3}\right)\:\:\:\:\:{mod}\left(\mathrm{5}{x}−\mathrm{1}\right) \\ $$$${P}\left({x}\right)\:\:\:\:\:\:\vdots\left({x}−\mathrm{2}\right)\:\:\:\:\:\:\:\:\:{mod}\left(\mathrm{16}\right) \\ $$$${P}\left({x}\right)\:\:\:\:\:\:\vdots\left({x}^{\mathrm{2}} +\mathrm{3}\right)\left({x}−\mathrm{2}\right)\:\:\:{mod}\left(?\right) \\ $$

Answered by MrGaster last updated on 24/Dec/24

(P(x)⋮(x^2 +3)(x−2)mod((5x−1)∙16))

$$\left({P}\left({x}\right)\vdots\left({x}^{\mathrm{2}} +\mathrm{3}\right)\left({x}−\mathrm{2}\right)\mathrm{mod}\left(\left(\mathrm{5}{x}−\mathrm{1}\right)\centerdot\mathrm{16}\right)\right) \\ $$

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