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Question Number 59675    Answers: 0   Comments: 0

you are welcome sir ali.

$${you}\:{are}\:{welcome}\:{sir}\:{ali}. \\ $$

Question Number 59655    Answers: 1   Comments: 3

Question Number 59639    Answers: 0   Comments: 3

Question Number 59588    Answers: 1   Comments: 1

find x,y in R (x+yi)^3 =((1+(√(15)) i)/((√5) − (√3) i))

$${find}\:{x},{y}\:{in}\:{R} \\ $$$$\left({x}+{yi}\right)^{\mathrm{3}} =\frac{\mathrm{1}+\sqrt{\mathrm{15}}\:{i}}{\sqrt{\mathrm{5}}\:−\:\sqrt{\mathrm{3}}\:{i}} \\ $$

Question Number 59505    Answers: 2   Comments: 0

Two particles P and Q move towards each other along a straight line MN, 51 meters long. P starts fromM with velocity 5 ms^(−1) and constant acceleration of 1 ms^(−2) . Q starts from N at the same time with velocity 6 ms^(−1) and at a constant acceleration of 3 ms^(−2) . Find the time when the: (a) particles are 30 metres apart; (b) particles meet; (c) velocity of P is (3/4) os the velocity of Q.

$$\mathrm{Two}\:\mathrm{particles}\:\mathrm{P}\:\mathrm{and}\:\mathrm{Q}\:\mathrm{move}\:\mathrm{towards}\:\mathrm{each} \\ $$$$\mathrm{other}\:\mathrm{along}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{line}\:{MN},\:\mathrm{51}\:\mathrm{meters} \\ $$$$\mathrm{long}.\:\mathrm{P}\:\mathrm{starts}\:\mathrm{from}{M}\:\mathrm{with}\:\mathrm{velocity}\:\mathrm{5}\:\mathrm{ms}^{−\mathrm{1}} \\ $$$$\mathrm{and}\:\mathrm{constant}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{1}\:\mathrm{ms}^{−\mathrm{2}} .\:\mathrm{Q}\:\mathrm{starts} \\ $$$$\mathrm{from}\:\mathrm{N}\:\mathrm{at}\:\mathrm{the}\:\mathrm{same}\:\mathrm{time}\:\mathrm{with}\:\mathrm{velocity}\:\mathrm{6}\:\mathrm{ms}^{−\mathrm{1}} \\ $$$$\mathrm{and}\:\mathrm{at}\:\mathrm{a}\:\mathrm{constant}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{3}\:\mathrm{ms}^{−\mathrm{2}} . \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{time}\:\mathrm{when}\:\mathrm{the}: \\ $$$$\left(\mathrm{a}\right)\:\mathrm{particles}\:\mathrm{are}\:\mathrm{30}\:\mathrm{metres}\:\mathrm{apart}; \\ $$$$\left(\mathrm{b}\right)\:\mathrm{particles}\:\mathrm{meet}; \\ $$$$\left(\mathrm{c}\right)\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{P}\:\mathrm{is}\:\frac{\mathrm{3}}{\mathrm{4}}\:\mathrm{os}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{Q}. \\ $$

Question Number 59478    Answers: 2   Comments: 0

x^4 +x^2 +16=0

$$\mathrm{x}^{\mathrm{4}} +\mathrm{x}^{\mathrm{2}} +\mathrm{16}=\mathrm{0} \\ $$

Question Number 59442    Answers: 1   Comments: 2

Solve the system xy + 3x + 2y = − 6 ..... (i) yx + y + 3z = − 3 ..... (ii) zx + 2z + x = 2 ..... (iii)

$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{system} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{xy}\:+\:\mathrm{3x}\:+\:\mathrm{2y}\:\:=\:−\:\mathrm{6}\:\:\:\:\:\:\:.....\:\left(\mathrm{i}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{yx}\:+\:\mathrm{y}\:+\:\mathrm{3z}\:\:\:=\:−\:\mathrm{3}\:\:\:\:\:\:\:\:\:\:.....\:\left(\mathrm{ii}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{zx}\:+\:\mathrm{2z}\:+\:\mathrm{x}\:\:\:=\:\:\mathrm{2}\:\:\:\:\:\:\:\:\:\:.....\:\left(\mathrm{iii}\right) \\ $$

Question Number 59397    Answers: 0   Comments: 1

6^4 ×6^3

$$\mathrm{6}^{\mathrm{4}} ×\mathrm{6}^{\mathrm{3}} \\ $$

Question Number 59323    Answers: 1   Comments: 0

Question Number 59214    Answers: 0   Comments: 0

Question Number 59103    Answers: 0   Comments: 0

Question Number 59079    Answers: 0   Comments: 0

Question Number 59023    Answers: 0   Comments: 0

please solve my quens

$${please}\:{solve}\:{my}\:{quens} \\ $$

Question Number 58974    Answers: 1   Comments: 0

Question Number 58965    Answers: 0   Comments: 0

if a,b ∈C ∣ ∣a∣<1,∣b∣<1 ⇒∣((a−b)/(1−a^ b))∣<1^

$$\mathrm{if}\:{a},{b}\:\in\mathbb{C}\:\mid\:\mid{a}\mid<\mathrm{1},\mid{b}\mid<\mathrm{1} \\ $$$$\Rightarrow\mid\frac{{a}−{b}}{\mathrm{1}−\bar {{a}b}}\mid<\overset{} {\mathrm{1}} \\ $$

Question Number 58962    Answers: 0   Comments: 0

you are welcome sir.

$${you}\:{are}\:{welcome}\:{sir}. \\ $$

Question Number 58928    Answers: 0   Comments: 2

Question Number 58880    Answers: 0   Comments: 1

t=(1/(1−4^(1/4) )) find the value of t

$${t}=\frac{\mathrm{1}}{\mathrm{1}−\mathrm{4}^{\frac{\mathrm{1}}{\mathrm{4}}} }\:\:\:\:\:\:{find}\:{the}\:{value}\:{of}\:{t} \\ $$

Question Number 58750    Answers: 0   Comments: 2

Question Number 58675    Answers: 0   Comments: 5

Question Number 58584    Answers: 0   Comments: 0

((X−λ)/(√(λ/n)))

$$\frac{{X}−\lambda}{\sqrt{\frac{\lambda}{{n}}}} \\ $$

Question Number 58519    Answers: 1   Comments: 1

Question Number 58454    Answers: 0   Comments: 0

Question Number 58447    Answers: 2   Comments: 1

Question Number 58526    Answers: 0   Comments: 1

Question Number 58358    Answers: 0   Comments: 0

knowing that: cos(x)=Σ_(n=1) ^∞ (((−1)^n x^(2n) )/((2n)!)) sin(x)=Σ_(n=1) ^∞ (((−1)^n x^(2n+1) )/((2n +1)!)) prof that: cos(x+y)= cos(x)cos(y)−sin(x)sin(y)

$${knowing}\:{that}:\: \\ $$$${cos}\left({x}\right)=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} {x}^{\mathrm{2}{n}} }{\left(\mathrm{2}{n}\right)!}\:\:\:\: \\ $$$${sin}\left({x}\right)=\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} {x}^{\mathrm{2}{n}+\mathrm{1}} }{\left(\mathrm{2}{n}\:+\mathrm{1}\right)!} \\ $$$${prof}\:{that}:\:{cos}\left({x}+{y}\right)=\:{cos}\left({x}\right){cos}\left({y}\right)−{sin}\left({x}\right){sin}\left({y}\right) \\ $$

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