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Question Number 83604 Answers: 0 Comments: 7

need help. When typing with microsoft word i face some difficulties like when typing lim_(x→0) f(x) it turns to lim_(x→0) f(x) and Σ_(r=0) ^n a_n turns to Σ_(r=0) ^n a_n please how do i rectify this problem? and any suggestion on a better application to type my maths papers? thanks in advance.

$need help . When typing with microsoft word$ $i face some difficulties like when typing$ $\lim_{x \to 0} f (x) it turns to \lim_{x \to 0} f (x) and \underset{r = 0}{\sum^{n}} a_{n}$ $turns to \sum_{r = 0}^{n} a_{n} please how do i rectify this$ $problem ? and any suggestion on a better application$ $to type my maths papers ? thanks in advance .$

Question Number 83381 Answers: 0 Comments: 0

Given that the function f(x) = x^3 is differentiable in the interval (−2,2) us the mean value theorem to find the value of x for which the tangent to the curve is parrallel to the chord through the points (−2,8) and (2,8).

$Given that the function f (x) = x^{3} is$ $differentiable in the interval (- 2, 2) us the mean$ $value theorem to find the value of x for which the$ $tangent to the curve is parrallel to the chord$ $through the points (- 2, 8) and (2, 8) .$

Question Number 83297 Answers: 1 Comments: 1

Write down a series expansion for ln [((1−2x)/((1+2x)^2 ))] in ascending powers of x up to and including the term in x^4 . if x is small that terms in x^2 and higher powers are negleted show that (((1−2x)/(1+2x)))^(1/(2x)) ≅ (1 + x)e^(−3)

$Write down a series expansion for$ $\ln [\frac{1 - 2 x}{{(1 + 2 x)}^{2}}] in ascending powers of x$ $up to and including the term in x^{4} .$ $if x is small that terms in x^{2} and higher powers$ $are negleted show that {(\frac{1 - 2 x}{1 + 2 x})}^{\frac{1}{2 x}} ≅ (1 + x) e^{- 3}$

Question Number 83296 Answers: 0 Comments: 2

Obtain a maclaurin expansion for a) e^(cos x ) b) e^(cos^2 x)

$Obtain a maclaurin expansion for$ $a) e^{\cos x} b) e^{\cos^{2} x}$

Question Number 83205 Answers: 0 Comments: 2

∫_0 ^(ln2) (1/(cosh(x + ln4)))dx =

$\int_{0}^{l n 2} \frac{1}{c o s h (x + l n 4)} d x =$

Question Number 83202 Answers: 0 Comments: 4

find the first 4 terms in the maclaurin[ series expansion for ln (1 + 3x) hence show that if x^2 and higher powers of x are negleted, then (1 + 3x)^(3/x) = e^6 (1 −9x)

$find the first 4 terms in the maclaurin [$ $series expansion for \ln (1 + 3 x) hence show that$ $if x^{2} and higher powers of x are negleted,$ $then$ ${(1 + 3 x)}^{\frac{3}{x}} = e^{6} (1 - 9 x)$