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Question Number 100295 Answers: 0 Comments: 0

a relation R is defined on the set of real numbers by xRy if and only if x−y is a multiple of 3. show that R is transitive

$${a}\:{relation}\:{R}\:{is}\:{defined}\:{on}\:{the}\:{set}\:{of}\:{real} \\ $$$${numbers}\:{by}\:{xRy}\:{if}\:{and}\:{only}\:{if}\:{x}−{y}\:{is}\:{a}\: \\ $$$${multiple}\:{of}\:\mathrm{3}.\:{show}\:{that}\:{R}\:{is}\:{transitive} \\ $$

Question Number 100240 Answers: 2 Comments: 9

Find (x,y)∈R such that; ((x+y)/(x^2 −xy+y^2 ))=(7/2) updated from (2/7)→(7/2). Sorry, it was a mistake.

$$\mathrm{Find}\:\:\left(\mathrm{x},\mathrm{y}\right)\in\mathbb{R}\:\mathrm{such}\:\:\mathrm{that}; \\ $$$$\frac{\mathrm{x}+\mathrm{y}}{\mathrm{x}^{\mathrm{2}} −\mathrm{xy}+\mathrm{y}^{\mathrm{2}} }=\frac{\mathrm{7}}{\mathrm{2}} \\ $$$$ \\ $$$${updated}\:{from}\:\frac{\mathrm{2}}{\mathrm{7}}\rightarrow\frac{\mathrm{7}}{\mathrm{2}}.\:{Sorry},\:{it}\:{was}\:{a}\:{mistake}. \\ $$

Question Number 100097 Answers: 0 Comments: 1

∫(tanx)^e^(iπ) dx

$$\int\left({tanx}\right)^{{e}^{{i}\pi} } {dx} \\ $$

Question Number 100000 Answers: 2 Comments: 1

1+(1/(32))+(1/(243))+(1/(1024))+...∞

$$\mathrm{1}+\frac{\mathrm{1}}{\mathrm{32}}+\frac{\mathrm{1}}{\mathrm{243}}+\frac{\mathrm{1}}{\mathrm{1024}}+...\infty \\ $$

Question Number 99997 Answers: 0 Comments: 2

Question Number 99995 Answers: 0 Comments: 0

(√(1(√(3(√(5(√(7(√9)))))))))...∞

$$\sqrt{\mathrm{1}\sqrt{\mathrm{3}\sqrt{\mathrm{5}\sqrt{\mathrm{7}\sqrt{\mathrm{9}}}}}}...\infty \\ $$

Question Number 99994 Answers: 1 Comments: 0

1+(1/(16))+(1/(81))+(1/(256))+.....∞

$$\mathrm{1}+\frac{\mathrm{1}}{\mathrm{16}}+\frac{\mathrm{1}}{\mathrm{81}}+\frac{\mathrm{1}}{\mathrm{256}}+.....\infty \\ $$

Question Number 99975 Answers: 1 Comments: 0

((1/2))^(((1/3))^((1/4)....∞) ) =?

$$\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\left(\frac{\mathrm{1}}{\mathrm{3}}\right)^{\frac{\mathrm{1}}{\mathrm{4}}....\infty} } =? \\ $$

Question Number 99962 Answers: 1 Comments: 0

A particle Q moves in a plane and its polar coordinate (r,θ) are described by r = at^2 and θ = (1/3)t^4 find its speed at t = 2s

$$\mathrm{A}\:\mathrm{particle}\:{Q}\:\mathrm{moves}\:\mathrm{in}\:\mathrm{a}\:\mathrm{plane}\:\mathrm{and}\:\mathrm{its}\:\mathrm{polar}\:\mathrm{coordinate}\:\left({r},\theta\right) \\ $$$$\mathrm{are}\:\mathrm{described}\:\mathrm{by}\:{r}\:=\:{at}^{\mathrm{2}} \:\mathrm{and}\:\theta\:=\:\frac{\mathrm{1}}{\mathrm{3}}{t}^{\mathrm{4}} \:\mathrm{find}\:\mathrm{its} \\ $$$$\mathrm{speed}\:\mathrm{at}\:{t}\:=\:\mathrm{2s} \\ $$

Question Number 99892 Answers: 0 Comments: 0

solve the equation xa^(1/x) +(1/x)a^x =2a Where a{−1,0,1}

$${solve}\:{the}\:{equation} \\ $$$${xa}^{\frac{\mathrm{1}}{{x}}} +\frac{\mathrm{1}}{{x}}{a}^{{x}} =\mathrm{2}{a} \\ $$$${Where}\:{a}\left\{−\mathrm{1},\mathrm{0},\mathrm{1}\right\} \\ $$

Question Number 99889 Answers: 1 Comments: 0

1+(1/2)+(1/3)+(1/4)+(1/5)+(1/6)+(1/7)+.......∞{Find the sum}

$$\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+\frac{\mathrm{1}}{\mathrm{4}}+\frac{\mathrm{1}}{\mathrm{5}}+\frac{\mathrm{1}}{\mathrm{6}}+\frac{\mathrm{1}}{\mathrm{7}}+.......\infty\left\{\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\right\} \\ $$

Question Number 99853 Answers: 2 Comments: 0

(1/1^2 )+(1/2^2 )+(1/3^2 )+(1/4^2 )+(1/6^2 )+.....∞=?

$$\frac{\mathrm{1}}{\mathrm{1}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{4}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{6}^{\mathrm{2}} }+.....\infty=? \\ $$

Question Number 99670 Answers: 0 Comments: 2

Question Number 99669 Answers: 0 Comments: 0

Question Number 99623 Answers: 1 Comments: 1

obtain the modulus and arguement of (((1−i)^4 )/((2+2(√(3i)^3 ))))

$${obtain}\:{the}\:{modulus}\:{and}\:{arguement}\:{of} \\ $$$$\frac{\left(\mathrm{1}−{i}\right)^{\mathrm{4}} }{\left(\mathrm{2}+\mathrm{2}\sqrt{\left.\mathrm{3}{i}\right)^{\mathrm{3}} }\right.} \\ $$

Question Number 99568 Answers: 1 Comments: 4

Find the value of (√(2+(√(2+(√(2+(√(2+(√(2+(√(2+))))))))))))...∞ by cos function

$${Find}\:{the}\:{value}\:{of}\:\:\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+}}}}}}...\infty\:\:\:\:\:{by}\:{cos}\:{function} \\ $$

Question Number 99485 Answers: 2 Comments: 0

∫tan^(1/5) xdx

$$\int{tan}^{\frac{\mathrm{1}}{\mathrm{5}}} {xdx} \\ $$

Question Number 99411 Answers: 0 Comments: 2

Solve the equation xa^(1/x) +(1/x)a^x =2a where,a{−1,0,1}

$${Solve}\:{the}\:{equation} \\ $$$${xa}^{\frac{\mathrm{1}}{{x}}} +\frac{\mathrm{1}}{{x}}{a}^{{x}} =\mathrm{2}{a} \\ $$$${where},{a}\left\{−\mathrm{1},\mathrm{0},\mathrm{1}\right\} \\ $$

Question Number 99368 Answers: 0 Comments: 1

please sir my problem in my solution is where?

$${please}\:{sir}\:{my}\:{problem}\:{in}\:{my}\:{solution} \\ $$$${is}\:{where}? \\ $$

Question Number 99314 Answers: 0 Comments: 2

Find[]the[]value[]of (√(1+2(√(1+3(√(1+4(√(1+5(√(1+6(√(1+7))))))))))))....∞

$${Find}\left[\right]{the}\left[\right]{value}\left[\right]{of} \\ $$$$\sqrt{\mathrm{1}+\mathrm{2}\sqrt{\mathrm{1}+\mathrm{3}\sqrt{\mathrm{1}+\mathrm{4}\sqrt{\mathrm{1}+\mathrm{5}\sqrt{\mathrm{1}+\mathrm{6}\sqrt{\mathrm{1}+\mathrm{7}}}}}}}....\infty \\ $$

Question Number 99097 Answers: 0 Comments: 1

Hello verry nice day for all of you god bless You pleas Can you use black Color shen You post Quation or Give answer is verry hard to read withe other colors

$${Hello}\: \\ $$$${verry}\:{nice}\:{day}\:{for}\:{all}\:{of}\:{you}\:{god}\:{bless}\:{You} \\ $$$${pleas}\:{Can}\:{you}\:{use}\:{black}\:{Color}\:{shen}\:{You}\:{post}\:{Quation}\: \\ $$$${or}\:{Give}\:{answer}\:{is}\:{verry}\:{hard}\:{to}\:{read}\:{withe}\:{other}\:{colors} \\ $$

Question Number 98953 Answers: 2 Comments: 0

Given f(x)=sin^2 x find the expansion of f(x) up to the n^(th) term.

$$\mathcal{G}\mathrm{iven}\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{sin}^{\mathrm{2}} \mathrm{x}\:\mathrm{find}\:\mathrm{the}\:\mathrm{expansion}\:\mathrm{of}\:\mathrm{f}\left(\mathrm{x}\right) \\ $$$$\mathrm{up}\:\mathrm{to}\:\mathrm{the}\:\mathrm{n}^{\mathrm{th}} \:\mathrm{term}. \\ $$

Question Number 98924 Answers: 0 Comments: 0

Prove that if a+ bi is a root to pz^2 + qz + r = 0 , where a,b,p,q,r ∈R then a−bi is also a root to that equation.

$$\mathrm{Prove}\:\mathrm{that}\:\mathrm{if}\:{a}+\:{bi}\:\mathrm{is}\:\mathrm{a}\:\mathrm{root}\:\mathrm{to} \\ $$$$\:{pz}^{\mathrm{2}} \:+\:{qz}\:+\:{r}\:=\:\mathrm{0}\:,\:\mathrm{where}\:{a},{b},{p},{q},{r}\:\in\mathbb{R} \\ $$$$\mathrm{then}\:{a}−{bi}\:\mathrm{is}\:\mathrm{also}\:\mathrm{a}\:\mathrm{root}\:\mathrm{to}\:\mathrm{that}\:\mathrm{equation}. \\ $$

Question Number 98887 Answers: 0 Comments: 0

Question Number 98673 Answers: 2 Comments: 0

find a_n in terms of n (I can′t find it...) a_1 =1; a_2 =4 a_3 =a_2 ×4×((2^2 −1)/2^2 ) a_4 =a_3 ×4×((2^2 −1)/2^2 )×((3^2 −1)/3^2 ) a_5 =a_4 ×4×((2^2 −1)/2^2 )×((3^2 −1)/3^2 )×((4^2 −1)/4^2 ) ... n≥2: a_(n+1) =4a_n Π_(k=2) ^n ((k^2 −1)/k^2 )

$$\mathrm{find}\:{a}_{{n}} \:\mathrm{in}\:\mathrm{terms}\:\mathrm{of}\:{n} \\ $$$$\left(\mathrm{I}\:\mathrm{can}'\mathrm{t}\:\mathrm{find}\:\mathrm{it}...\right) \\ $$$${a}_{\mathrm{1}} =\mathrm{1};\:{a}_{\mathrm{2}} =\mathrm{4} \\ $$$${a}_{\mathrm{3}} ={a}_{\mathrm{2}} ×\mathrm{4}×\frac{\mathrm{2}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}^{\mathrm{2}} } \\ $$$${a}_{\mathrm{4}} ={a}_{\mathrm{3}} ×\mathrm{4}×\frac{\mathrm{2}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }×\frac{\mathrm{3}^{\mathrm{2}} −\mathrm{1}}{\mathrm{3}^{\mathrm{2}} } \\ $$$${a}_{\mathrm{5}} ={a}_{\mathrm{4}} ×\mathrm{4}×\frac{\mathrm{2}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }×\frac{\mathrm{3}^{\mathrm{2}} −\mathrm{1}}{\mathrm{3}^{\mathrm{2}} }×\frac{\mathrm{4}^{\mathrm{2}} −\mathrm{1}}{\mathrm{4}^{\mathrm{2}} } \\ $$$$... \\ $$$${n}\geqslant\mathrm{2}:\:{a}_{{n}+\mathrm{1}} =\mathrm{4}{a}_{{n}} \underset{{k}=\mathrm{2}} {\overset{{n}} {\prod}}\frac{{k}^{\mathrm{2}} −\mathrm{1}}{{k}^{\mathrm{2}} } \\ $$

Question Number 98640 Answers: 0 Comments: 1

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