Question and Answers Forum

All Questions   Topic List

OthersQuestion and Answers: Page 54

Question Number 119463    Answers: 1   Comments: 2

one cube of side length 3cm is painted by three colour say (red blue and black) opposte face same colour Now cube is cut into 27 small cube i)How many cube has three face coloured ii)How many cube two face coloured iii)How many cube has no colour in its face

$${one}\:{cube}\:{of}\:{side}\:{length}\:\mathrm{3}{cm}\:{is}\:{painted}\:{by}\:{three}\:{colour} \\ $$$${say}\:\left({red}\:{blue}\:{and}\:{black}\right)\:{opposte}\:{face}\:{same}\:{colour} \\ $$$${Now}\:{cube}\:{is}\:{cut}\:{into}\:\mathrm{27}\:{small}\:{cube} \\ $$$$\left.{i}\right){How}\:{many}\:{cube}\:{has}\:{three}\:{face}\:{coloured} \\ $$$$\left.{ii}\right){How}\:{many}\:{cube}\:{two}\:{face}\:{coloured} \\ $$$$\left.{iii}\right){How}\:{many}\:{cube}\:\:{has}\:{no}\:{colour}\:{in}\:{its}\:{face} \\ $$

Question Number 119376    Answers: 3   Comments: 2

Solve for x in the equation below ax^2 +bx + c = 0.

$${Solve}\:{for}\:\boldsymbol{{x}}\:{in}\:{the}\:{equation}\:{below} \\ $$$${ax}^{\mathrm{2}} \:+{bx}\:+\:{c}\:=\:\mathrm{0}. \\ $$

Question Number 119316    Answers: 0   Comments: 0

((Σ_(n=1) ^∞ (1/n^n ))/(Σ_(n=1) ^∞ (−1)^(n+1) (1/n^n )))

$$\frac{\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{{n}^{{n}} }}{\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left(−\mathrm{1}\right)^{{n}+\mathrm{1}} \frac{\mathrm{1}}{{n}^{{n}} }} \\ $$

Question Number 119112    Answers: 0   Comments: 2

Seems my recent post was removed by Tinkutara.

$$\boldsymbol{\mathrm{Seems}}\:\boldsymbol{\mathrm{my}}\:\boldsymbol{\mathrm{recent}}\:\boldsymbol{\mathrm{post}}\:\boldsymbol{\mathrm{was}}\:\boldsymbol{\mathrm{removed}}\:\boldsymbol{\mathrm{by}} \\ $$$$\boldsymbol{\mathrm{Tinkutara}}.\: \\ $$

Question Number 118952    Answers: 2   Comments: 0

Salut Pouvez vous m′aider avec ce devoir? Examiner si les series suivantes sont absolument convergentes ou semi−convergentes Σ_(k=0) ^n (((-1)^(k-1) )/((k+1)^2 )) Σ_(k=0) ^n (((-1)^(k-1) )/k) Etudier la convergence des series suivantes Σ_(k=1) ^n (((2k)!)/2^k ) Σ_(k=1) ^n ((1/2))^k

$$\mathrm{Salut} \\ $$$$\mathrm{Pouvez}\:\mathrm{vous}\:\mathrm{m}'\mathrm{aider}\:\mathrm{avec}\:\mathrm{ce}\:\mathrm{devoir}? \\ $$$$ \\ $$$$\mathrm{Examiner}\:\mathrm{si}\:\mathrm{les}\:\mathrm{series}\:\mathrm{suivantes}\:\mathrm{sont}\: \\ $$$$\mathrm{absolument}\:\mathrm{convergentes}\:\mathrm{ou}\: \\ $$$$\mathrm{semi}−\mathrm{convergentes} \\ $$$$ \\ $$$$\underset{\mathrm{k}=\mathrm{0}} {\overset{\mathrm{n}} {\sum}}\frac{\left(-\mathrm{1}\right)^{\mathrm{k}-\mathrm{1}} }{\left(\mathrm{k}+\mathrm{1}\right)^{\mathrm{2}} } \\ $$$$ \\ $$$$\underset{\mathrm{k}=\mathrm{0}} {\overset{\mathrm{n}} {\sum}}\frac{\left(-\mathrm{1}\right)^{\mathrm{k}-\mathrm{1}} }{\mathrm{k}} \\ $$$$ \\ $$$$\mathrm{Etudier}\:\mathrm{la}\:\mathrm{convergence}\:\mathrm{des}\:\mathrm{series}\:\mathrm{suivantes} \\ $$$$\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\frac{\left(\mathrm{2k}\right)!}{\mathrm{2}^{\mathrm{k}} } \\ $$$$\underset{\mathrm{k}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{k}} \\ $$$$ \\ $$

Question Number 118685    Answers: 0   Comments: 1

Converting decimal numbers to base 10

$$\boldsymbol{{Converting}}\:\boldsymbol{{decimal}}\:\boldsymbol{{numbers}}\:\boldsymbol{{to}}\:\boldsymbol{{base}}\:\mathrm{10} \\ $$

Question Number 118594    Answers: 0   Comments: 0

Question Number 118323    Answers: 0   Comments: 0

Prove that ζ(1−s)=2^(1−s) π^(−s) cos(((sπ)/2))Γ(s)ζ(s)

$${Prove}\:{that}\: \\ $$$$\zeta\left(\mathrm{1}−{s}\right)=\mathrm{2}^{\mathrm{1}−{s}} \pi^{−{s}} {cos}\left(\frac{{s}\pi}{\mathrm{2}}\right)\Gamma\left({s}\right)\zeta\left({s}\right) \\ $$

Question Number 117990    Answers: 1   Comments: 0

(2.3.5.7.9.11.13.17......∞)×(√(6/(3.8.24.48.80.120.168.288.....∞)))

$$\left(\mathrm{2}.\mathrm{3}.\mathrm{5}.\mathrm{7}.\mathrm{9}.\mathrm{11}.\mathrm{13}.\mathrm{17}......\infty\right)×\sqrt{\frac{\mathrm{6}}{\mathrm{3}.\mathrm{8}.\mathrm{24}.\mathrm{48}.\mathrm{80}.\mathrm{120}.\mathrm{168}.\mathrm{288}.....\infty}} \\ $$

Question Number 117980    Answers: 0   Comments: 2

Where is the quiz?

$$\mathrm{Where}\:\mathrm{is}\:\mathrm{the}\:\mathrm{quiz}? \\ $$$$ \\ $$

Question Number 117645    Answers: 1   Comments: 0

Question Number 117620    Answers: 5   Comments: 0

x^4 −⌊5x^2 ⌋+4=0

$${x}^{\mathrm{4}} −\lfloor\mathrm{5}{x}^{\mathrm{2}} \rfloor+\mathrm{4}=\mathrm{0} \\ $$

Question Number 117475    Answers: 1   Comments: 0

(6/5).((24)/(23)).((54)/(53)).((96)/(95)).((150)/(149)).((216)/(215)).((294)/(293))....

$$\frac{\mathrm{6}}{\mathrm{5}}.\frac{\mathrm{24}}{\mathrm{23}}.\frac{\mathrm{54}}{\mathrm{53}}.\frac{\mathrm{96}}{\mathrm{95}}.\frac{\mathrm{150}}{\mathrm{149}}.\frac{\mathrm{216}}{\mathrm{215}}.\frac{\mathrm{294}}{\mathrm{293}}.... \\ $$

Question Number 117460    Answers: 0   Comments: 2

((2(√2))/(9801))Σ_(n=1) ^∞ (((4n)!(1103+26390n))/((n!)^4 396^(4n) ))=(1/π) (Prove that)

$$\frac{\mathrm{2}\sqrt{\mathrm{2}}}{\mathrm{9801}}\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(\mathrm{4}{n}\right)!\left(\mathrm{1103}+\mathrm{26390}{n}\right)}{\left({n}!\right)^{\mathrm{4}} \mathrm{396}^{\mathrm{4}{n}} }=\frac{\mathrm{1}}{\pi}\:\:\:\left({Prove}\:{that}\right) \\ $$

Question Number 117458    Answers: 1   Comments: 0

(4/3).((16)/(15)).((36)/(35)).((64)/(63)).((100)/(99)).((144)/(143)).((196)/(195)).((256)/(255)).((324)/(323))......∞

$$\frac{\mathrm{4}}{\mathrm{3}}.\frac{\mathrm{16}}{\mathrm{15}}.\frac{\mathrm{36}}{\mathrm{35}}.\frac{\mathrm{64}}{\mathrm{63}}.\frac{\mathrm{100}}{\mathrm{99}}.\frac{\mathrm{144}}{\mathrm{143}}.\frac{\mathrm{196}}{\mathrm{195}}.\frac{\mathrm{256}}{\mathrm{255}}.\frac{\mathrm{324}}{\mathrm{323}}......\infty \\ $$

Question Number 117391    Answers: 1   Comments: 0

(√(2/3))−(√(2/(27)))+(√(2/(75)))−(√(2/(147)))+(√(2/(243)))−(√(2/(363)))+(√(2/(507)))−(√(2/(675)))+(√(2/(867)))−._ ...

$$\sqrt{\frac{\mathrm{2}}{\mathrm{3}}}−\sqrt{\frac{\mathrm{2}}{\mathrm{27}}}+\sqrt{\frac{\mathrm{2}}{\mathrm{75}}}−\sqrt{\frac{\mathrm{2}}{\mathrm{147}}}+\sqrt{\frac{\mathrm{2}}{\mathrm{243}}}−\sqrt{\frac{\mathrm{2}}{\mathrm{363}}}+\sqrt{\frac{\mathrm{2}}{\mathrm{507}}}−\sqrt{\frac{\mathrm{2}}{\mathrm{675}}}+\sqrt{\frac{\mathrm{2}}{\mathrm{867}}}−._{} ... \\ $$

Question Number 117366    Answers: 0   Comments: 0

Σ_(n=1) ^∞ (((2n)!)/(n^(2n) n!(2n+1)))

$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(\mathrm{2}{n}\right)!}{{n}^{\mathrm{2}{n}} {n}!\left(\mathrm{2}{n}+\mathrm{1}\right)} \\ $$

Question Number 117365    Answers: 1   Comments: 1

Express ((1/2))! in terms of infinite series

$${Express}\:\left(\frac{\mathrm{1}}{\mathrm{2}}\right)!\:\:{in}\:{terms}\:{of}\:{infinite}\:{series} \\ $$

Question Number 117258    Answers: 1   Comments: 0

(4/3).(9/8).((49)/(48)).((121)/(120)).((169)/(168)).((289)/(288)).((529)/(528)).((831)/(830)).....∞

$$\frac{\mathrm{4}}{\mathrm{3}}.\frac{\mathrm{9}}{\mathrm{8}}.\frac{\mathrm{49}}{\mathrm{48}}.\frac{\mathrm{121}}{\mathrm{120}}.\frac{\mathrm{169}}{\mathrm{168}}.\frac{\mathrm{289}}{\mathrm{288}}.\frac{\mathrm{529}}{\mathrm{528}}.\frac{\mathrm{831}}{\mathrm{830}}.....\infty \\ $$

Question Number 117207    Answers: 0   Comments: 2

Can anyone recommend a pdf for learning hypergeometric functions?

$$\boldsymbol{\mathrm{C}}\mathrm{an}\:\mathrm{anyone}\:\mathrm{recommend}\:\mathrm{a}\:\mathrm{pdf}\:\mathrm{for} \\ $$$$\mathrm{learning}\:\mathrm{hypergeometric}\:\mathrm{functions}? \\ $$

Question Number 117286    Answers: 2   Comments: 0

A person wants to invite his 6 friends in a Dinner party. He has 3 person to send letter to them.In how many ways he can invite his 6 friends?

$${A}\:{person}\:{wants}\:{to}\:{invite}\:{his}\:\mathrm{6}\:{friends}\:{in}\:{a}\:{Dinner}\:{party}. \\ $$$${He}\:{has}\:\mathrm{3}\:{person}\:{to}\:{send}\:{letter}\:{to}\:{them}.{In}\:{how}\:{many}\:{ways} \\ $$$${he}\:{can}\:{invite}\:{his}\:\mathrm{6}\:{friends}? \\ $$

Question Number 117205    Answers: 0   Comments: 0

∫_0 ^( 2π) ((cos^2 3x)/(1−2a∙cosx+a^2 ))dx − ? (a∈C/{−1; 1}) I need a solution through complex analysis

$$\int_{\mathrm{0}} ^{\:\mathrm{2}\pi} \frac{\boldsymbol{{cos}}^{\mathrm{2}} \mathrm{3}\boldsymbol{{x}}}{\mathrm{1}−\mathrm{2}\boldsymbol{{a}}\centerdot\boldsymbol{{cosx}}+\boldsymbol{{a}}^{\mathrm{2}} }\boldsymbol{{dx}}\:−\:?\:\left(\boldsymbol{{a}}\in\boldsymbol{{C}}/\left\{−\mathrm{1};\:\mathrm{1}\right\}\right) \\ $$$$\boldsymbol{{I}}\:\boldsymbol{{need}}\:\boldsymbol{{a}}\:\boldsymbol{{solution}}\:\boldsymbol{{through}}\:\boldsymbol{{complex}}\:\boldsymbol{{analysis}} \\ $$

Question Number 116965    Answers: 1   Comments: 0

Σ_(k=1) ^∞ (−1)^(k+1) ((sin(kθ))/(kθ))

$$\underset{{k}=\mathrm{1}} {\overset{\infty} {\sum}}\left(−\mathrm{1}\right)^{{k}+\mathrm{1}} \:\frac{{sin}\left({k}\theta\right)}{{k}\theta} \\ $$

Question Number 116902    Answers: 0   Comments: 0

Question Number 116822    Answers: 3   Comments: 1

what the value of (√i) =?

$$\:\mathrm{what}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\sqrt{{i}}\:=? \\ $$

Question Number 116685    Answers: 1   Comments: 0

Given the equality: 1+3+5+...+(2p+1)=(p+1)^(2 ) p ∈ N^∗ Show this equality is true when we replace p by p+1

$$\mathrm{Given}\:\mathrm{the}\:\mathrm{equality}: \\ $$$$\mathrm{1}+\mathrm{3}+\mathrm{5}+...+\left(\mathrm{2p}+\mathrm{1}\right)=\left(\mathrm{p}+\mathrm{1}\right)^{\mathrm{2}\:} \:\:\:\mathrm{p}\:\in\:\mathbb{N}^{\ast} \\ $$$$ \\ $$$$\mathrm{Show}\:\mathrm{this}\:\mathrm{equality}\:\mathrm{is}\:\mathrm{true}\:\mathrm{when} \\ $$$$\mathrm{we}\:\mathrm{replace}\:\mathrm{p}\:\mathrm{by}\:\mathrm{p}+\mathrm{1} \\ $$

  Pg 49      Pg 50      Pg 51      Pg 52      Pg 53      Pg 54      Pg 55      Pg 56      Pg 57      Pg 58   

Terms of Service

Privacy Policy

Contact: info@tinkutara.com