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Question Number 122335 Answers: 0 Comments: 0
Question Number 122322 Answers: 4 Comments: 0
$$\mid{x}+\mathrm{1}\mid<\mid{x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{2}\mid \\ $$$${solve}\:{for}\:{x} \\ $$
Question Number 122318 Answers: 0 Comments: 0
Question Number 122303 Answers: 1 Comments: 3
$$\frac{{log}\mathrm{1}}{\:\sqrt{\mathrm{1}}}−\frac{{log}\mathrm{3}}{\:\sqrt{\mathrm{3}}}+\frac{{log}\mathrm{5}}{\:\sqrt{\mathrm{5}}}−\frac{{log}\mathrm{7}}{\:\sqrt{\mathrm{7}}}+..{C}=\left(\frac{\pi}{\mathrm{4}}−\frac{\gamma}{\mathrm{2}}−\frac{\mathrm{1}}{\mathrm{2}}{log}\left(\mathrm{2}\pi\right)\right)\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}}}−\frac{\mathrm{1}}{\:\sqrt{\mathrm{3}}}+..{C}\right) \\ $$$$\gamma\:=\mathscr{E}{ulerian}\:{constant} \\ $$
Question Number 122302 Answers: 3 Comments: 0
$$\int_{\mathrm{0}} ^{\infty} \frac{{dx}}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\left(\mathrm{4}+{x}^{\mathrm{2}} \right)\left(\mathrm{16}+{x}^{\mathrm{2}} \right)\left(\mathrm{64}+{x}^{\mathrm{2}} \right)} \\ $$
Question Number 122317 Answers: 0 Comments: 0
$$\mathrm{1}+\mathrm{9}\left(\frac{\mathrm{1}}{\mathrm{4}}\right)^{\mathrm{4}} +\mathrm{17}\left(\frac{\mathrm{1}.\mathrm{5}}{\mathrm{4}.\mathrm{8}}\right)^{\mathrm{4}} +\mathrm{25}\left(\frac{\mathrm{1}.\mathrm{5}.\mathrm{9}}{\mathrm{4}.\mathrm{8}.\mathrm{12}}\right)^{\mathrm{4}} +...=\frac{\pi}{\mathrm{2}\sqrt{\mathrm{2}}\left(\Gamma^{\mathrm{2}} \left(\frac{\mathrm{3}}{\mathrm{4}}\right)\right)} \\ $$
Question Number 122176 Answers: 2 Comments: 2
$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \sqrt[{\mathrm{7}}]{{tanx}}\:{dx} \\ $$
Question Number 122377 Answers: 1 Comments: 4
Question Number 122069 Answers: 1 Comments: 0
$$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{1}}{\:\sqrt[{\mathrm{97}}]{{x}^{\mathrm{96}} −{x}^{\mathrm{97}} }}{dx} \\ $$
Question Number 122023 Answers: 1 Comments: 0
$$\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{{n}} {F}_{{n}} }{\mathrm{7}^{{n}} }\:\:\:\:\:\:\left({F}_{{n}} \:{denotes}\:{Fibbonocci}\:{sequence}\right) \\ $$
Question Number 122013 Answers: 0 Comments: 6
$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{24}}} {log}\left({tan}\theta\right){d}\theta \\ $$$${Problem}\:{source}:\:{brilliant} \\ $$
Question Number 121983 Answers: 1 Comments: 2
$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {sin}^{{n}} {x}\:{dx}\:\left({In}\:{closed}\:{form}\right)\:\:\left({n}\in\mathbb{N}\right) \\ $$
Question Number 121914 Answers: 0 Comments: 1
$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \left({sin}\theta\right)^{−\frac{\mathrm{1}}{{n}}} {d}\theta \\ $$
Question Number 121739 Answers: 1 Comments: 0
$$\frac{\mathrm{1}^{\mathrm{13}} }{{e}^{\mathrm{2}\pi} −\mathrm{1}}+\frac{\mathrm{2}^{\mathrm{13}} }{{e}^{\mathrm{4}\pi} −\mathrm{1}}+\frac{\mathrm{3}^{\mathrm{13}} }{{e}^{\mathrm{6}\pi} −\mathrm{1}}+.... \\ $$
Question Number 121697 Answers: 3 Comments: 0
$$\:\mathbb{Q}.\:\mathbb{FACTORIZE}− \\ $$$$\:\left(\mathrm{1}\right)\:\mathrm{9x}^{\mathrm{2}} +\mathrm{12xy}+\mathrm{4y}^{\mathrm{2}} \\ $$$$\:\left(\mathrm{2}\right)\:\mathrm{25x}^{\mathrm{2}} −\mathrm{20xy}+\mathrm{16y}^{\mathrm{2}} \\ $$$$\:\left(\mathrm{3}\right)\:\mathrm{36x}^{\mathrm{2}} +\mathrm{42xy}+\mathrm{49y}^{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\:\:\:\bigstar\bigstar\mathbb{VISHAL}\bigstar\bigstar \\ $$
Question Number 121678 Answers: 0 Comments: 0
Question Number 121677 Answers: 2 Comments: 1
Question Number 121659 Answers: 2 Comments: 4
$$\int_{\mathrm{0}} ^{\infty} \frac{{dx}}{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)\left(\mathrm{1}+{a}^{\mathrm{2}} {x}^{\mathrm{2}} \right)\left(\mathrm{1}+{a}^{\mathrm{4}} {x}^{\mathrm{2}} \right)\left(\mathrm{1}+{a}^{\mathrm{6}} {x}^{\mathrm{2}} \right).....} \\ $$$$ \\ $$
Question Number 121655 Answers: 2 Comments: 2
Question Number 121653 Answers: 0 Comments: 5
$$\frac{{log}\mathrm{1}}{\:\sqrt{\mathrm{1}}}−\frac{{log}\mathrm{3}}{\:\sqrt{\mathrm{3}}}+\frac{{log}\mathrm{5}}{\:\sqrt{\mathrm{5}}}−\frac{{log}\mathrm{7}}{\:\sqrt{\mathrm{7}}}+.... \\ $$
Question Number 121454 Answers: 1 Comments: 2
$$\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1}^{\mathrm{2}} }+\frac{\mathrm{1}}{\mathrm{2}^{\mathrm{2}} }+...+\frac{\mathrm{1}}{\left(\mathrm{1}.\mathrm{2}\right)^{\mathrm{2}} }+\frac{\mathrm{1}}{\left(\mathrm{2}.\mathrm{3}\right)^{\mathrm{2}} }+...+\frac{\mathrm{1}}{\left(\mathrm{1}.\mathrm{2}.\mathrm{3}\right)^{\mathrm{2}} }+\frac{\mathrm{1}}{\left(\mathrm{2}.\mathrm{3}.\mathrm{4}\right)^{\mathrm{2}} }+...+\frac{\mathrm{1}}{\left(\mathrm{1}.\mathrm{2}.\mathrm{3}.\mathrm{4}\right)^{\mathrm{2}} }+..... \\ $$$$ \\ $$$${Or} \\ $$$$\mathrm{1}+\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{{n}^{\mathrm{2}} }+\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\left({n}\left({n}+\mathrm{1}\right)\right)^{\mathrm{2}} }+\overset{\infty} {\sum}\frac{\mathrm{1}}{\left({n}\left({n}+\mathrm{1}\right)\left({n}+\mathrm{2}\right)\right)^{\mathrm{2}} }+..... \\ $$
Question Number 121326 Answers: 1 Comments: 3
$$\frac{\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{{n}^{\mathrm{2}} +\mathrm{1}}}{\underset{{n}=\mathrm{2}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{{n}^{\mathrm{2}} −\mathrm{1}}} \\ $$
Question Number 121229 Answers: 1 Comments: 0
Question Number 121217 Answers: 0 Comments: 0
Question Number 121215 Answers: 0 Comments: 0
Question Number 121085 Answers: 3 Comments: 1
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