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Question Number 169347 Answers: 4 Comments: 0
$${Differentiate}\:{wrt}\:{x} \\ $$$${y}={sin}^{−\mathrm{1}} \left(\mathrm{2}{x}+\mathrm{1}\right) \\ $$$$ \\ $$$${Mastermind} \\ $$
Question Number 169346 Answers: 0 Comments: 0
$${Show}\:{that}\:{substituting}\:{y}={vx}, \\ $$$${x}+{y}\frac{{dy}}{{dx}}={x}\frac{{dy}}{{dx}}−{y}\:{to}\:{a}\:{separable} \\ $$$${equation}\:{for}\:{v}\:{and}\:{x}\:{and}\:{its}\: \\ $$$${solution}\:{is}\:{log}_{{e}} \left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right)=\mathrm{2}{tan}^{−\mathrm{1}} \left(\frac{{y}}{{x}}\right) \\ $$$$+{C} \\ $$$$ \\ $$$${Mastermind} \\ $$$$\: \\ $$
Question Number 169342 Answers: 1 Comments: 0
$${Obtain}\:{the}\:{differential}\:{equation} \\ $$$${associated}\:{with}\:{the}\:{primitive} \\ $$$${y}\:=\:{Ae}^{\mathrm{2}{x}} +{Be}^{{x}} +{C} \\ $$$$ \\ $$$${Mastermind} \\ $$
Question Number 169333 Answers: 0 Comments: 3
$${Show}\:{that}\:{if}\:{y}={C}_{\mathrm{1}} {sinx}\:+\:{C}_{\mathrm{2}} {x}\:{then} \\ $$$$\left(\mathrm{1}+{xcotx}\right)\frac{{d}^{\mathrm{2}} {y}}{{dx}^{\mathrm{2}} }−{x}\frac{{dy}}{{dx}}+{y}=\mathrm{0} \\ $$$$ \\ $$$${Mastermind} \\ $$
Question Number 169315 Answers: 1 Comments: 1
$${lim}_{{x}\rightarrow\infty} \left(\frac{\mathrm{1}+\sqrt{{x}+\mathrm{2}}}{\mathrm{1}−\sqrt{{x}+\mathrm{2}}}\right) \\ $$$$ \\ $$$${Mastermind} \\ $$
Question Number 169305 Answers: 4 Comments: 2
$${Differentiate}\:{the}\:{following}\:{wrt}\:{x} \\ $$$$\left.\mathrm{1}\right)\:{y}={x}^{{x}} \\ $$$$\left.\mathrm{2}\right)\:{y}={sin}^{−\mathrm{1}} \left(\mathrm{2}{x}+\mathrm{1}\right) \\ $$$$ \\ $$$${Mastermind} \\ $$
Question Number 169303 Answers: 1 Comments: 1
$${Given}\:{that}: \\ $$$${x}\:{cos}\:{y}={sin}\left({x}+{y}\right),\:{find}\:\frac{{dy}}{{dx}} \\ $$$$ \\ $$$${Mastermind} \\ $$
Question Number 169200 Answers: 2 Comments: 0
Question Number 169142 Answers: 2 Comments: 1
Question Number 168982 Answers: 1 Comments: 1
Question Number 168952 Answers: 1 Comments: 0
Question Number 168942 Answers: 0 Comments: 2
Question Number 168910 Answers: 0 Comments: 3
$${Resolve} \\ $$$$\left.\mathrm{1}\right)\:\left({x}−{y}\right){ydx}−{x}^{\mathrm{2}} {dy}=\mathrm{0} \\ $$$$\left.\mathrm{2}\right)\left(\mathrm{2}{x}−{y}\right){dx}+\left(\mathrm{4}{x}−\mathrm{2}{y}+\mathrm{3}\right){dy}=\mathrm{0} \\ $$
Question Number 168909 Answers: 0 Comments: 1
$${Resolve}\: \\ $$$$\left(\mathrm{1}−{x}^{\mathrm{2}} {y}\right){dx}+\left({x}^{\mathrm{2}} {y}−{x}^{\mathrm{3}} \right){dy}=\mathrm{0}\:;\:\mu=\mu\left({x}\right) \\ $$
Question Number 168868 Answers: 0 Comments: 0
Question Number 168842 Answers: 0 Comments: 0
Question Number 168841 Answers: 0 Comments: 0
Question Number 168744 Answers: 3 Comments: 0
$${Resolve} \\ $$$$\left.\mathrm{1}\right)\:\int\frac{\sqrt{\mathrm{1}+\mathrm{cos}\:{x}}}{\mathrm{sin}\:{x}}{dx} \\ $$$$\left.\mathrm{2}\right)\:\int\frac{{dx}}{\mathrm{1}+\sqrt[{\mathrm{3}}]{{x}+\mathrm{1}}} \\ $$$$\left.\mathrm{3}\right)\:\int\frac{{x}\mathrm{tan}\:{x}}{\mathrm{cos}\:^{\mathrm{4}} {x}}{dx} \\ $$$$\left.\mathrm{4}\right)\:\int\frac{{dx}}{\mathrm{1}+\sqrt{{x}}+\sqrt{\mathrm{1}+{x}}} \\ $$
Question Number 168742 Answers: 1 Comments: 0
$${Resolve} \\ $$$${y}={xy}'+{a}\sqrt{\mathrm{1}+\left(\mathrm{y}'\right)^{\mathrm{2}} } \\ $$
Question Number 168723 Answers: 0 Comments: 2
$${Resolve}\: \\ $$$$\left({x}+\mathrm{5}\right)^{\mathrm{5}} {y}^{''} =\mathrm{1} \\ $$
Question Number 168722 Answers: 0 Comments: 1
$${Resolve}\: \\ $$$${x}^{\mathrm{2}} {y}^{''} +{xy}^{'} +{y}=\mathrm{1} \\ $$
Question Number 168679 Answers: 2 Comments: 0
Question Number 168617 Answers: 0 Comments: 2
Question Number 168616 Answers: 1 Comments: 0
Question Number 168613 Answers: 3 Comments: 1
$${Resolve}\: \\ $$$$\left.\mathrm{1}\right)\:{x}\frac{{dy}}{{dx}}−{y}={y}^{\mathrm{3}} \\ $$$$\left.\mathrm{2}\right)\:\left({x}−{y}\right){ydx}−{x}^{\mathrm{2}} {dy}=\mathrm{0} \\ $$$$\left.\mathrm{3}\right)\:\left(\mathrm{2}{x}−{y}\right){dx}+\left(\mathrm{4}{x}−\mathrm{2}{y}+\mathrm{3}\right){dy}=\mathrm{0} \\ $$
Question Number 168608 Answers: 2 Comments: 0
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