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Question Number 171005 Answers: 0 Comments: 0

The distance S metre travelled in time t seconds by an object released from rest and allow to fall freely under the force of gravity is given by s(t)=4.5t^2 . find a) the average speed of the object during the time interval from 2 to 2.5 seconds. b) the instantaneous velocity of the object after 4 seconds. Mastermind

$${The}\:{distance}\:{S}\:{metre}\:{travelled}\:{in}\:{time} \\ $$$${t}\:{seconds}\:{by}\:{an}\:{object}\:{released}\:{from} \\ $$$${rest}\:{and}\:{allow}\:{to}\:{fall}\:{freely}\:{under}\:{the} \\ $$$${force}\:{of}\:{gravity}\:{is}\:{given}\:{by}\:{s}\left({t}\right)=\mathrm{4}.\mathrm{5}{t}^{\mathrm{2}} . \\ $$$${find}\: \\ $$$$\left.{a}\right)\:{the}\:{average}\:{speed}\:{of}\:{the}\:{object} \\ $$$${during}\:{the}\:{time}\:{interval}\:{from}\:\mathrm{2}\:{to} \\ $$$$\mathrm{2}.\mathrm{5}\:{seconds}. \\ $$$$\left.{b}\right)\:{the}\:{instantaneous}\:{velocity}\:{of}\:{the} \\ $$$${object}\:{after}\:\mathrm{4}\:{seconds}. \\ $$$$ \\ $$$${Mastermind} \\ $$

Question Number 170997 Answers: 1 Comments: 0

Find the equation of the tangent to the curve x^2 +y^2 −4x+6y−12=0 at the point (2, 3). Mastermind

$${Find}\:{the}\:{equation}\:{of}\:{the}\:{tangent}\:{to}\:{the} \\ $$$${curve}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{4}{x}+\mathrm{6}{y}−\mathrm{12}=\mathrm{0}\:{at}\:{the} \\ $$$${point}\:\left(\mathrm{2},\:\mathrm{3}\right). \\ $$$$ \\ $$$${Mastermind} \\ $$

Question Number 170996 Answers: 1 Comments: 0

Find the volume of the solid obtained by rotating about x−axis of the curve y=(√x) on the interval [0, 2]. Mastermind

$${Find}\:{the}\:{volume}\:{of}\:{the}\:{solid}\:{obtained} \\ $$$${by}\:{rotating}\:{about}\:{x}−{axis}\:{of}\:{the}\:{curve} \\ $$$${y}=\sqrt{{x}}\:{on}\:{the}\:{interval}\:\left[\mathrm{0},\:\mathrm{2}\right]. \\ $$$$ \\ $$$${Mastermind} \\ $$

Question Number 170995 Answers: 0 Comments: 1

Approximate sin46° by “differentials” Mastermind

$${Approximate}\:{sin}\mathrm{46}°\:{by}\:``{differentials}'' \\ $$$$ \\ $$$${Mastermind} \\ $$

Question Number 170994 Answers: 1 Comments: 0

Show that the function h(x)=x^5 −2x is an odd function Mastermind

$$\mathrm{Show}\:\mathrm{that}\:\mathrm{the}\:\mathrm{function}\:\mathrm{h}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{5}} −\mathrm{2x} \\ $$$$\mathrm{is}\:\mathrm{an}\:\mathrm{odd}\:\mathrm{function} \\ $$$$ \\ $$$$\mathrm{Mastermind} \\ $$

Question Number 170986 Answers: 1 Comments: 2

Question Number 170950 Answers: 0 Comments: 2

e^x =ln(x), Make x the subject of the formula moreover find the value of x

$$\mathrm{e}^{\mathrm{x}} =\mathrm{ln}\left(\mathrm{x}\right),\:\mathrm{Make}\:\mathrm{x}\:\mathrm{the}\:\mathrm{subject}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{formula} \\ $$$$\mathrm{moreover}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x} \\ $$

Question Number 170948 Answers: 0 Comments: 3

A^x^x +Bx^x +C=R, Make x the subject of the formular

$$\mathrm{A}^{\mathrm{x}^{\mathrm{x}} } +\mathrm{Bx}^{\mathrm{x}} +\mathrm{C}=\mathrm{R},\:\mathrm{Make}\:\mathrm{x}\:\mathrm{the}\:\mathrm{subject} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{formular} \\ $$

Question Number 170946 Answers: 1 Comments: 0

Solve for x : 3^x =2x+2 Mastermind

$$\mathrm{Solve}\:\mathrm{for}\:\mathrm{x}\:: \\ $$$$\mathrm{3}^{\mathrm{x}} =\mathrm{2x}+\mathrm{2} \\ $$$$ \\ $$$$\mathrm{Mastermind} \\ $$

Question Number 170910 Answers: 0 Comments: 0

Question Number 170906 Answers: 2 Comments: 0

Question Number 170781 Answers: 2 Comments: 0

(√((2−x))) = (2−x)^2 solve for x

$$\sqrt{\left(\mathrm{2}−\mathrm{x}\right)}\:\:\:=\:\:\left(\mathrm{2}−\mathrm{x}\right)^{\mathrm{2}} \:\:\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{for}}\:\:\:\:\:\:\boldsymbol{\mathrm{x}} \\ $$

Question Number 170780 Answers: 1 Comments: 0

Question Number 170743 Answers: 0 Comments: 0

2. Uma soluca^ o tampao foi preparada misturarando 200ml NH_(3 ) 0,6 moles e 300ml de uma solucao de NH_3 Cl 0,2 moles P^(kh) =9,24 e log 2=0,3 a) Qual e o P^h desta solucao tampa^ o supondo-se um volume de 500ml? b)Qual sera o P^h depois de ser adicionado 0,2 molar de ion [H^− ] Dados n(CH_3 -CH_2 COOH)=0,02mok/l=0,02M Ka=1,3∙10^(−5) n(CH_3 −CH_2 -COONa)=0,015mol/l=0,015M V=1l log 2=0,3 log 0,11 P^h =? 1°Passo 2°Passo P^(ka) =−log Ka P^h =P^(ka) +log(([Base])/([Acido])) P^(ka) =−log 1,3∙10^(−5) ? P^h =4,89+log(([0,02])/([0,015])) P^(ka) =(−5+0,11) P^h =4,89+log1,3 P^(ka) =5−11 P^h =4,89+0,11 P^(ka) =4,49 P^h =5 3°Passo P^h =P^h +log(([Basica])/([Acida])) P^h =4,89+log(([0,02])/([0,025])) P^h =4,89+log0,8 P^h =4,89+0,096 P^h =4,986≈5

Question Number 170673 Answers: 0 Comments: 2

Question Number 170659 Answers: 0 Comments: 0

c≥0 (U_n )_(n≥1) U_1 =1 U_(n+1) =(√(U_n +cn)) show that U_n ≤α(√n) determine α

$${c}\geqslant\mathrm{0}\:\left({U}_{{n}} \right)_{{n}\geqslant\mathrm{1}} \:\:\:{U}_{\mathrm{1}} =\mathrm{1} \\ $$$${U}_{{n}+\mathrm{1}} =\sqrt{{U}_{{n}} +{cn}} \\ $$$${show}\:{that}\:{U}_{{n}} \leqslant\alpha\sqrt{{n}} \\ $$$${determine}\:\alpha \\ $$

Question Number 170650 Answers: 1 Comments: 0

Tom bought a computer for 15% off from the list price of P dollars. If the sales tax was 8%, how much did he pay for the computer including sales tax?

$$ \\ $$Tom bought a computer for 15% off from the list price of P dollars. If the sales tax was 8%, how much did he pay for the computer including sales tax?

Question Number 170576 Answers: 0 Comments: 2