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Question Number 15737 Answers: 0 Comments: 2

Sir mrW1 and Ajfour, please which advance or physics textbook pdf can i get

$$\mathrm{Sir}\:\:\:\mathrm{mrW1}\:\mathrm{and}\:\mathrm{Ajfour},\:\mathrm{please}\:\mathrm{which}\:\mathrm{advance}\:\mathrm{or}\:\mathrm{physics}\:\mathrm{textbook}\:\mathrm{pdf}\:\mathrm{can}\:\mathrm{i}\:\mathrm{get} \\ $$

Question Number 15610 Answers: 0 Comments: 3

The temperature of some 100 litres is 80°C. 10 litres water,whose temperature is 100°C is mixed in it.What will be the temperature of mixed water?

$$\mathrm{The}\:\mathrm{temperature}\:\mathrm{of}\:\mathrm{some}\:\mathrm{100}\:\mathrm{litres} \\ $$$$\mathrm{is}\:\mathrm{80}°\mathrm{C}.\:\:\mathrm{10}\:\mathrm{litres}\:\mathrm{water},\mathrm{whose}\:\mathrm{temperature} \\ $$$$\mathrm{is}\:\mathrm{100}°\mathrm{C}\:\mathrm{is}\:\mathrm{mixed}\:\mathrm{in}\:\mathrm{it}.\mathrm{What}\:\mathrm{will}\:\mathrm{be}\:\mathrm{the} \\ $$$$\mathrm{temperature}\:\mathrm{of}\:\mathrm{mixed}\:\mathrm{water}? \\ $$

Question Number 15599 Answers: 1 Comments: 0

Two paper screens A and B are separated by 100 m distance. A bullet pierces A and then B. The hole in B is 10 cm below the hole in A. If the bullet is travelling horizontally at A, calculate the velocity of the bullet at A. (Neglecting the types of frictional forces)

$$\mathrm{Two}\:\mathrm{paper}\:\mathrm{screens}\:{A}\:\mathrm{and}\:{B}\:\mathrm{are} \\ $$$$\mathrm{separated}\:\mathrm{by}\:\mathrm{100}\:\mathrm{m}\:\mathrm{distance}.\:\mathrm{A}\:\mathrm{bullet} \\ $$$$\mathrm{pierces}\:{A}\:\mathrm{and}\:\mathrm{then}\:{B}.\:\mathrm{The}\:\mathrm{hole}\:\mathrm{in}\:{B}\:\mathrm{is} \\ $$$$\mathrm{10}\:\mathrm{cm}\:\mathrm{below}\:\mathrm{the}\:\mathrm{hole}\:\mathrm{in}\:{A}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{bullet} \\ $$$$\mathrm{is}\:\mathrm{travelling}\:\mathrm{horizontally}\:\mathrm{at}\:{A},\:\mathrm{calculate} \\ $$$$\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{bullet}\:\mathrm{at}\:{A}. \\ $$$$\left(\mathrm{Neglecting}\:\mathrm{the}\:\mathrm{types}\:\mathrm{of}\:\mathrm{frictional}\right. \\ $$$$\left.\mathrm{forces}\right) \\ $$

Question Number 15591 Answers: 1 Comments: 0

A projectile projected from the ground has its direction of motion making an angle (π/4) with the horizontal at a height 40 m. Its initial velocity of projection is 50 m/s, the angle of projection is?

$$\mathrm{A}\:\mathrm{projectile}\:\mathrm{projected}\:\mathrm{from}\:\mathrm{the}\:\mathrm{ground} \\ $$$$\mathrm{has}\:\mathrm{its}\:\mathrm{direction}\:\mathrm{of}\:\mathrm{motion}\:\mathrm{making}\:\mathrm{an} \\ $$$$\mathrm{angle}\:\frac{\pi}{\mathrm{4}}\:\mathrm{with}\:\mathrm{the}\:\mathrm{horizontal}\:\mathrm{at}\:\mathrm{a}\:\mathrm{height} \\ $$$$\mathrm{40}\:\mathrm{m}.\:\mathrm{Its}\:\mathrm{initial}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{projection}\:\mathrm{is} \\ $$$$\mathrm{50}\:\mathrm{m}/\mathrm{s},\:\mathrm{the}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{projection}\:\mathrm{is}? \\ $$

Question Number 15539 Answers: 0 Comments: 0

Question Number 15538 Answers: 0 Comments: 0

Question Number 15485 Answers: 1 Comments: 0

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Question Number 15407 Answers: 1 Comments: 0

A ball is thrown vertically upward with velocity 20 m/s from a rail road car moving with a velocity 5 m/s horizontally. A person standing on the ground observes its motion as projectile. Find maximum height attained by the ball if point of projection is at a height 3 m from the ground.

$$\mathrm{A}\:\mathrm{ball}\:\mathrm{is}\:\mathrm{thrown}\:\mathrm{vertically}\:\mathrm{upward} \\ $$$$\mathrm{with}\:\mathrm{velocity}\:\mathrm{20}\:\mathrm{m}/\mathrm{s}\:\mathrm{from}\:\mathrm{a}\:\mathrm{rail}\:\mathrm{road} \\ $$$$\mathrm{car}\:\mathrm{moving}\:\mathrm{with}\:\mathrm{a}\:\mathrm{velocity}\:\mathrm{5}\:\mathrm{m}/\mathrm{s} \\ $$$$\mathrm{horizontally}.\:\mathrm{A}\:\mathrm{person}\:\mathrm{standing}\:\mathrm{on}\:\mathrm{the} \\ $$$$\mathrm{ground}\:\mathrm{observes}\:\mathrm{its}\:\mathrm{motion}\:\mathrm{as}\:\mathrm{projectile}. \\ $$$$\mathrm{Find}\:\mathrm{maximum}\:\mathrm{height}\:\mathrm{attained}\:\mathrm{by}\:\mathrm{the} \\ $$$$\mathrm{ball}\:\mathrm{if}\:\mathrm{point}\:\mathrm{of}\:\mathrm{projection}\:\mathrm{is}\:\mathrm{at}\:\mathrm{a}\:\mathrm{height} \\ $$$$\mathrm{3}\:\mathrm{m}\:\mathrm{from}\:\mathrm{the}\:\mathrm{ground}. \\ $$

Question Number 15405 Answers: 1 Comments: 0

A body is projected at time t = 0 from a certain point on a planet surface with a certain velocity at a certain angle with the planet′s surface (assumed horizontal). The horizontal and vertical displacement x and y in metre are related to time as x = 10(√3)t and y = 10t − 4t^2 . Find vertical component of velocity of the particle when it is at a height half of the maximum height attained.

$$\mathrm{A}\:\mathrm{body}\:\mathrm{is}\:\mathrm{projected}\:\mathrm{at}\:\mathrm{time}\:{t}\:=\:\mathrm{0}\:\mathrm{from}\:\mathrm{a} \\ $$$$\mathrm{certain}\:\mathrm{point}\:\mathrm{on}\:\mathrm{a}\:\mathrm{planet}\:\mathrm{surface}\:\mathrm{with} \\ $$$$\mathrm{a}\:\mathrm{certain}\:\mathrm{velocity}\:\mathrm{at}\:\mathrm{a}\:\mathrm{certain}\:\mathrm{angle} \\ $$$$\mathrm{with}\:\mathrm{the}\:\mathrm{planet}'\mathrm{s}\:\mathrm{surface}\:\left(\mathrm{assumed}\right. \\ $$$$\left.\mathrm{horizontal}\right).\:\mathrm{The}\:\mathrm{horizontal}\:\mathrm{and}\:\mathrm{vertical} \\ $$$$\mathrm{displacement}\:{x}\:\mathrm{and}\:{y}\:\mathrm{in}\:\mathrm{metre}\:\mathrm{are} \\ $$$$\mathrm{related}\:\mathrm{to}\:\mathrm{time}\:\mathrm{as}\:{x}\:=\:\mathrm{10}\sqrt{\mathrm{3}}{t}\:\mathrm{and} \\ $$$${y}\:=\:\mathrm{10}{t}\:−\:\mathrm{4}{t}^{\mathrm{2}} .\:\mathrm{Find}\:\mathrm{vertical}\:\mathrm{component} \\ $$$$\mathrm{of}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{particle}\:\mathrm{when}\:\mathrm{it}\:\mathrm{is}\:\mathrm{at}\:\mathrm{a} \\ $$$$\mathrm{height}\:\mathrm{half}\:\mathrm{of}\:\mathrm{the}\:\mathrm{maximum}\:\mathrm{height} \\ $$$$\mathrm{attained}. \\ $$

Question Number 15418 Answers: 2 Comments: 0

A grasshopper can jump a maximum horizontal distance of 40 cm. If it spends negligible time on the ground then in this case its speed along the horizontal road will be?

$$\mathrm{A}\:\mathrm{grasshopper}\:\mathrm{can}\:\mathrm{jump}\:\mathrm{a}\:\mathrm{maximum} \\ $$$$\mathrm{horizontal}\:\mathrm{distance}\:\mathrm{of}\:\mathrm{40}\:\mathrm{cm}.\:\mathrm{If}\:\mathrm{it} \\ $$$$\mathrm{spends}\:\mathrm{negligible}\:\mathrm{time}\:\mathrm{on}\:\mathrm{the}\:\mathrm{ground} \\ $$$$\mathrm{then}\:\mathrm{in}\:\mathrm{this}\:\mathrm{case}\:\mathrm{its}\:\mathrm{speed}\:\mathrm{along}\:\mathrm{the} \\ $$$$\mathrm{horizontal}\:\mathrm{road}\:\mathrm{will}\:\mathrm{be}? \\ $$

Question Number 15343 Answers: 0 Comments: 0

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Question Number 15311 Answers: 0 Comments: 0

In a toll-booth at a bridge , some cars can pass by paying a tax of Rs. 10 and some special vehicles are exempted from paying tax. The booth has to track number of vehicles and total tax collected. Define a class ′tollbooth′. It should contain two data items of type int to hold the number of cars and total tax connected. A constructor initalizes these two variable to zero. A memberfunction freecar() only increments the car total. Finally another memberfunction show() displays the two totals. Write a C++ program such that the user has to press the key ′T′ for printing number of taxable cars and total tax, ′F′ for printing number of free cars and ′Esc′ to exit.

$$\mathrm{In}\:\mathrm{a}\:\mathrm{toll}-\mathrm{booth}\:\mathrm{at}\:\mathrm{a}\:\mathrm{bridge}\:,\:\mathrm{some}\:\mathrm{cars}\:\mathrm{can}\:\mathrm{pass}\:\mathrm{by}\:\mathrm{paying}\:\mathrm{a}\:\mathrm{tax}\:\mathrm{of}\:\mathrm{Rs}.\:\mathrm{10}\:\mathrm{and} \\ $$$$\mathrm{some}\:\mathrm{special}\:\mathrm{vehicles}\:\mathrm{are}\:\mathrm{exempted}\:\mathrm{from}\:\mathrm{paying}\:\mathrm{tax}.\:\mathrm{The}\:\mathrm{booth}\:\mathrm{has}\:\mathrm{to}\:\mathrm{track}\: \\ $$$$\mathrm{number}\:\mathrm{of}\:\mathrm{vehicles}\:\mathrm{and}\:\mathrm{total}\:\mathrm{tax}\:\mathrm{collected}.\:\mathrm{Define}\:\mathrm{a}\:\mathrm{class}\:'\mathrm{tollbooth}'.\:\mathrm{It}\:\mathrm{should}\:\mathrm{contain} \\ $$$$\mathrm{two}\:\mathrm{data}\:\mathrm{items}\:\mathrm{of}\:\mathrm{type}\:\mathrm{int}\:\mathrm{to}\:\mathrm{hold}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{cars}\:\mathrm{and}\:\mathrm{total}\:\mathrm{tax}\:\mathrm{connected}. \\ $$$$\mathrm{A}\:\mathrm{constructor}\:\mathrm{initalizes}\:\mathrm{these}\:\mathrm{two}\:\mathrm{variable}\:\mathrm{to}\:\mathrm{zero}.\:\mathrm{A}\:\mathrm{memberfunction}\:\mathrm{freecar}\left(\right)\:\mathrm{only} \\ $$$$\mathrm{increments}\:\mathrm{the}\:\mathrm{car}\:\mathrm{total}.\:\mathrm{Finally}\:\mathrm{another}\:\mathrm{memberfunction}\:\mathrm{show}\left(\right)\:\mathrm{displays}\:\mathrm{the} \\ $$$$\mathrm{two}\:\mathrm{totals}. \\ $$$$\:\:\:\mathrm{Write}\:\mathrm{a}\:\mathrm{C}++\:\mathrm{program}\:\mathrm{such}\:\mathrm{that}\:\mathrm{the}\:\mathrm{user}\:\mathrm{has}\:\mathrm{to}\:\mathrm{press}\:\mathrm{the}\:\mathrm{key}\:'\mathrm{T}'\:\mathrm{for} \\ $$$$\mathrm{printing}\:\mathrm{number}\:\mathrm{of}\:\mathrm{taxable}\:\mathrm{cars}\:\mathrm{and}\:\mathrm{total}\:\mathrm{tax},\:'\mathrm{F}'\:\mathrm{for}\:\mathrm{printing}\:\mathrm{number}\:\mathrm{of}\:\:\mathrm{free} \\ $$$$\mathrm{cars}\:\mathrm{and}\:'\mathrm{Esc}'\:\mathrm{to}\:\mathrm{exit}. \\ $$

Question Number 15294 Answers: 0 Comments: 1

A straigth conductor of length L is charged with q charge. What will be the electric field in the equatorial line at a distance d ? Ans: ((2q)/(4Πε_0 d(√(L^2 +4d^2 ))))

$$\mathrm{A}\:\mathrm{straigth}\:\mathrm{conductor}\:\mathrm{of}\:\mathrm{length} \\ $$$$\mathrm{L}\:\mathrm{is}\:\mathrm{charged}\:\mathrm{with}\:\mathrm{q}\:\mathrm{charge}.\:\mathrm{What} \\ $$$$\mathrm{will}\:\mathrm{be}\:\mathrm{the}\:\mathrm{electric}\:\mathrm{field}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{equatorial}\:\mathrm{line}\:\mathrm{at}\:\mathrm{a}\:\mathrm{distance}\:\mathrm{d}\:? \\ $$$$\mathrm{Ans}:\:\frac{\mathrm{2q}}{\mathrm{4}\Pi\epsilon_{\mathrm{0}} \mathrm{d}\sqrt{\mathrm{L}^{\mathrm{2}} +\mathrm{4d}^{\mathrm{2}} }} \\ $$

Question Number 15266 Answers: 0 Comments: 0

calculate the pH of 1(N) HCl.

$$\mathrm{calculate}\:\mathrm{the}\:\mathrm{pH}\:\mathrm{of}\:\mathrm{1}\left(\mathrm{N}\right)\:\mathrm{HCl}. \\ $$

Question Number 15182 Answers: 0 Comments: 0

If a piece of iron gains 10% of its mass due to partial rusting into Fe_2 O_3 the percentage of total iron that has rusted is? [Answer is 23.3]

$$\mathrm{If}\:\mathrm{a}\:\mathrm{piece}\:\mathrm{of}\:\mathrm{iron}\:\mathrm{gains}\:\mathrm{10\%}\:\mathrm{of}\:\mathrm{its}\:\mathrm{mass} \\ $$$$\mathrm{due}\:\mathrm{to}\:\mathrm{partial}\:\mathrm{rusting}\:\mathrm{into}\:\mathrm{Fe}_{\mathrm{2}} \mathrm{O}_{\mathrm{3}} \:\mathrm{the} \\ $$$$\mathrm{percentage}\:\mathrm{of}\:\mathrm{total}\:\mathrm{iron}\:\mathrm{that}\:\mathrm{has}\:\mathrm{rusted} \\ $$$$\mathrm{is}?\:\left[\mathrm{Answer}\:\mathrm{is}\:\mathrm{23}.\mathrm{3}\right] \\ $$

Question Number 15623 Answers: 1 Comments: 0

Question Number 15117 Answers: 1 Comments: 0

A Juggler is maintaining 4 balls in motion making each in term to rise to height of 20 m. Which of following position is not possible for the balls, when one ball is just leaving his hand? (1) 5 m (2) All position are possible (3) 15 m (4) 20 m

$$\mathrm{A}\:\mathrm{Juggler}\:\mathrm{is}\:\mathrm{maintaining}\:\mathrm{4}\:\mathrm{balls}\:\mathrm{in} \\ $$$$\mathrm{motion}\:\mathrm{making}\:\mathrm{each}\:\mathrm{in}\:\mathrm{term}\:\mathrm{to}\:\mathrm{rise}\:\mathrm{to} \\ $$$$\mathrm{height}\:\mathrm{of}\:\mathrm{20}\:\mathrm{m}.\:\mathrm{Which}\:\mathrm{of}\:\mathrm{following} \\ $$$$\mathrm{position}\:\mathrm{is}\:\mathrm{not}\:\mathrm{possible}\:\mathrm{for}\:\mathrm{the}\:\mathrm{balls}, \\ $$$$\mathrm{when}\:\mathrm{one}\:\mathrm{ball}\:\mathrm{is}\:\mathrm{just}\:\mathrm{leaving}\:\mathrm{his}\:\mathrm{hand}? \\ $$$$\left(\mathrm{1}\right)\:\mathrm{5}\:\mathrm{m} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{All}\:\mathrm{position}\:\mathrm{are}\:\mathrm{possible} \\ $$$$\left(\mathrm{3}\right)\:\mathrm{15}\:\mathrm{m} \\ $$$$\left(\mathrm{4}\right)\:\mathrm{20}\:\mathrm{m} \\ $$

Question Number 15116 Answers: 2 Comments: 0

A balloon ascends vertically with a constant speed for 5 seconds, when a pebble falls from it reaching the ground in 5 s. The speed of the balloon is?

$$\mathrm{A}\:\mathrm{balloon}\:\mathrm{ascends}\:\mathrm{vertically}\:\mathrm{with}\:\mathrm{a} \\ $$$$\mathrm{constant}\:\mathrm{speed}\:\mathrm{for}\:\mathrm{5}\:\mathrm{seconds},\:\mathrm{when}\:\mathrm{a} \\ $$$$\mathrm{pebble}\:\mathrm{falls}\:\mathrm{from}\:\mathrm{it}\:\mathrm{reaching}\:\mathrm{the}\:\mathrm{ground} \\ $$$$\mathrm{in}\:\mathrm{5}\:\mathrm{s}.\:\mathrm{The}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{balloon}\:\mathrm{is}? \\ $$

Question Number 15115 Answers: 1 Comments: 0

Drops are falling regularly from a water tap at a height of 9 m from the ground. The 4^(th) drop is about to fall from the tap when the 1^(st) hit the ground. Find the distance between 2^(nd) and 3^(rd) drop.

$$\mathrm{Drops}\:\mathrm{are}\:\mathrm{falling}\:\mathrm{regularly}\:\mathrm{from}\:\mathrm{a}\:\mathrm{water} \\ $$$$\mathrm{tap}\:\mathrm{at}\:\mathrm{a}\:\mathrm{height}\:\mathrm{of}\:\mathrm{9}\:\mathrm{m}\:\mathrm{from}\:\mathrm{the}\:\mathrm{ground}. \\ $$$$\mathrm{The}\:\mathrm{4}^{\mathrm{th}} \:\mathrm{drop}\:\mathrm{is}\:\mathrm{about}\:\mathrm{to}\:\mathrm{fall}\:\mathrm{from}\:\mathrm{the} \\ $$$$\mathrm{tap}\:\mathrm{when}\:\mathrm{the}\:\mathrm{1}^{\mathrm{st}} \:\mathrm{hit}\:\mathrm{the}\:\mathrm{ground}.\:\mathrm{Find} \\ $$$$\mathrm{the}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{2}^{\mathrm{nd}} \:\mathrm{and}\:\mathrm{3}^{\mathrm{rd}} \:\mathrm{drop}. \\ $$

Question Number 15102 Answers: 2 Comments: 1

Small steel balls falls from rest through the opening at A, at the steady rate of n balls per second. Find the vertical separation h of two consecutive balls when the lower one has dropped d meters.

$$\mathrm{Small}\:\mathrm{steel}\:\mathrm{balls}\:\mathrm{falls}\:\mathrm{from}\:\mathrm{rest}\:\mathrm{through} \\ $$$$\mathrm{the}\:\mathrm{opening}\:\mathrm{at}\:{A},\:\mathrm{at}\:\mathrm{the}\:\mathrm{steady}\:\mathrm{rate}\:\mathrm{of} \\ $$$${n}\:\mathrm{balls}\:\mathrm{per}\:\mathrm{second}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{vertical} \\ $$$$\mathrm{separation}\:{h}\:\mathrm{of}\:\mathrm{two}\:\mathrm{consecutive}\:\mathrm{balls} \\ $$$$\mathrm{when}\:\mathrm{the}\:\mathrm{lower}\:\mathrm{one}\:\mathrm{has}\:\mathrm{dropped}\:{d} \\ $$$$\mathrm{meters}. \\ $$

Question Number 15100 Answers: 1 Comments: 2

A car A is travelling with a speed of 72 km/h on a straight horizontal road. It is followed by another car B which is moving with a velocity of 36 km/h. When the distance between them is 25 km, the car A is given a deceleration of 2 ms^(−2) . After how much time will B catch up with A?

$$\mathrm{A}\:\mathrm{car}\:{A}\:\mathrm{is}\:\mathrm{travelling}\:\mathrm{with}\:\mathrm{a}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{72} \\ $$$$\mathrm{km}/\mathrm{h}\:\mathrm{on}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{horizontal}\:\mathrm{road}.\:\mathrm{It} \\ $$$$\mathrm{is}\:\mathrm{followed}\:\mathrm{by}\:\mathrm{another}\:\mathrm{car}\:{B}\:\mathrm{which}\:\mathrm{is} \\ $$$$\mathrm{moving}\:\mathrm{with}\:\mathrm{a}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{36}\:\mathrm{km}/\mathrm{h}. \\ $$$$\mathrm{When}\:\mathrm{the}\:\mathrm{distance}\:\mathrm{between}\:\mathrm{them}\:\mathrm{is}\:\mathrm{25} \\ $$$$\mathrm{km},\:\mathrm{the}\:\mathrm{car}\:{A}\:\mathrm{is}\:\mathrm{given}\:\mathrm{a}\:\mathrm{deceleration}\:\mathrm{of} \\ $$$$\mathrm{2}\:\mathrm{ms}^{−\mathrm{2}} .\:\mathrm{After}\:\mathrm{how}\:\mathrm{much}\:\mathrm{time}\:\mathrm{will}\:{B} \\ $$$$\mathrm{catch}\:\mathrm{up}\:\mathrm{with}\:{A}? \\ $$

Question Number 15052 Answers: 2 Comments: 4

Gravitational potential of a ring of radius R and mass M on the axis at a distance x from the center is given by v(x) = − ((GM)/(√(R^2 + x^2 ))) Nm/kg Using the above expression find the gravitational potential of the disc of mass M and radius R on the axis at a distance x from the center of the disc.

$$\mathrm{Gravitational}\:\mathrm{potential}\:\mathrm{of}\:\mathrm{a}\:\mathrm{ring}\:\mathrm{of} \\ $$$$\mathrm{radius}\:{R}\:\mathrm{and}\:\mathrm{mass}\:{M}\:\mathrm{on}\:\mathrm{the}\:\mathrm{axis}\:\mathrm{at}\:\mathrm{a} \\ $$$$\mathrm{distance}\:{x}\:\mathrm{from}\:\mathrm{the}\:\mathrm{center}\:\mathrm{is}\:\mathrm{given}\:\mathrm{by} \\ $$$${v}\left({x}\right)\:=\:−\:\frac{{GM}}{\sqrt{{R}^{\mathrm{2}} \:+\:{x}^{\mathrm{2}} }}\:\mathrm{Nm}/\mathrm{kg} \\ $$$$\mathrm{Using}\:\mathrm{the}\:\mathrm{above}\:\mathrm{expression}\:\mathrm{find}\:\mathrm{the} \\ $$$$\mathrm{gravitational}\:\mathrm{potential}\:\mathrm{of}\:\mathrm{the}\:\mathrm{disc}\:\mathrm{of} \\ $$$$\mathrm{mass}\:{M}\:\mathrm{and}\:\mathrm{radius}\:{R}\:\mathrm{on}\:\mathrm{the}\:\mathrm{axis}\:\mathrm{at}\:\mathrm{a} \\ $$$$\mathrm{distance}\:{x}\:\mathrm{from}\:\mathrm{the}\:\mathrm{center}\:\mathrm{of}\:\mathrm{the}\:\mathrm{disc}. \\ $$

Question Number 15019 Answers: 0 Comments: 0

1.00 Mol of a monoatomic gas initially at 3.00 × 10^2 K and occupying 2.00 × 10^(−3 ) m^3 is heated to 3.25 × 10^2 K and the final volume is 4.00 × 10^(−3) m^3 . Assuming ideal behaviour , Calculate the entropy change for the system.

$$\mathrm{1}.\mathrm{00}\:\mathrm{Mol}\:\mathrm{of}\:\mathrm{a}\:\mathrm{monoatomic}\:\mathrm{gas}\:\mathrm{initially}\:\mathrm{at}\:\mathrm{3}.\mathrm{00}\:×\:\mathrm{10}^{\mathrm{2}} \mathrm{K}\:\mathrm{and}\:\mathrm{occupying}\:\: \\ $$$$\mathrm{2}.\mathrm{00}\:×\:\mathrm{10}^{−\mathrm{3}\:} \mathrm{m}^{\mathrm{3}} \:\mathrm{is}\:\mathrm{heated}\:\mathrm{to}\:\mathrm{3}.\mathrm{25}\:×\:\mathrm{10}^{\mathrm{2}} \mathrm{K}\:\mathrm{and}\:\mathrm{the}\:\mathrm{final}\:\mathrm{volume}\:\mathrm{is}\:\mathrm{4}.\mathrm{00}\:×\:\mathrm{10}^{−\mathrm{3}} \mathrm{m}^{\mathrm{3}} .\: \\ $$$$\mathrm{Assuming}\:\mathrm{ideal}\:\mathrm{behaviour}\:,\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{entropy}\:\mathrm{change}\:\mathrm{for}\:\mathrm{the}\:\mathrm{system}. \\ $$

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