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Question Number 26424    Answers: 0   Comments: 0

The front of a train 80m long passes a signal at a speed of 72km/hr. If the rear of the train passes the signal 5s later, Find (a) The magnitude of the acceleration of the train. (b) The speed at which the rear of the train passes the signal.

$$\mathrm{The}\:\mathrm{front}\:\mathrm{of}\:\mathrm{a}\:\mathrm{train}\:\mathrm{80m}\:\mathrm{long}\:\mathrm{passes}\:\mathrm{a}\:\mathrm{signal}\:\mathrm{at}\:\mathrm{a}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{72km}/\mathrm{hr}.\:\mathrm{If}\:\mathrm{the} \\ $$$$\mathrm{rear}\:\mathrm{of}\:\mathrm{the}\:\mathrm{train}\:\mathrm{passes}\:\mathrm{the}\:\mathrm{signal}\:\mathrm{5s}\:\mathrm{later},\:\mathrm{Find} \\ $$$$\left(\mathrm{a}\right)\:\mathrm{The}\:\mathrm{magnitude}\:\mathrm{of}\:\mathrm{the}\:\mathrm{acceleration}\:\mathrm{of}\:\mathrm{the}\:\mathrm{train}. \\ $$$$\left(\mathrm{b}\right)\:\mathrm{The}\:\mathrm{speed}\:\mathrm{at}\:\mathrm{which}\:\mathrm{the}\:\mathrm{rear}\:\mathrm{of}\:\mathrm{the}\:\mathrm{train}\:\mathrm{passes}\:\mathrm{the}\:\mathrm{signal}. \\ $$

Question Number 26382    Answers: 0   Comments: 1

Question Number 26381    Answers: 0   Comments: 9

Question Number 26380    Answers: 0   Comments: 0

Question Number 26352    Answers: 1   Comments: 0

x(x+9)=(x+3)(x+7)−10

$${x}\left({x}+\mathrm{9}\right)=\left({x}+\mathrm{3}\right)\left({x}+\mathrm{7}\right)−\mathrm{10} \\ $$

Question Number 26329    Answers: 1   Comments: 0

A small particle moving with a uniform acceleration a covers distances X and Y in the first two equal and consecutive intervals of time t. Show that a = ((Y − X)/t^2 )

$$\mathrm{A}\:\mathrm{small}\:\mathrm{particle}\:\mathrm{moving}\:\mathrm{with}\:\mathrm{a}\:\mathrm{uniform}\:\mathrm{acceleration}\:\mathrm{a}\:\mathrm{covers}\:\mathrm{distances}\: \\ $$$$\mathrm{X}\:\mathrm{and}\:\mathrm{Y}\:\mathrm{in}\:\mathrm{the}\:\mathrm{first}\:\mathrm{two}\:\mathrm{equal}\:\mathrm{and}\:\mathrm{consecutive}\:\mathrm{intervals}\:\mathrm{of}\:\mathrm{time}\:\mathrm{t}.\:\mathrm{Show}\:\mathrm{that} \\ $$$$\mathrm{a}\:=\:\frac{\mathrm{Y}\:−\:\mathrm{X}}{\mathrm{t}^{\mathrm{2}} } \\ $$

Question Number 26328    Answers: 1   Comments: 1

Three towns X, Y and Z are on a straight road and Y is the mid−way between X and Z. A motor cyclist moving with uniform acceleration passes X, Y and Z. The speed with which the motocyclist passes X and Z are 20m/s and 40m/s respectively. Find the speed with which the motorcyclist passes Y.

$$\mathrm{Three}\:\mathrm{towns}\:\mathrm{X},\:\mathrm{Y}\:\mathrm{and}\:\mathrm{Z}\:\mathrm{are}\:\mathrm{on}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{road}\:\mathrm{and}\:\mathrm{Y}\:\mathrm{is}\:\mathrm{the}\:\mathrm{mid}−\mathrm{way}\:\mathrm{between} \\ $$$$\mathrm{X}\:\mathrm{and}\:\mathrm{Z}.\:\mathrm{A}\:\mathrm{motor}\:\mathrm{cyclist}\:\mathrm{moving}\:\mathrm{with}\:\mathrm{uniform}\:\mathrm{acceleration}\:\mathrm{passes}\:\mathrm{X},\:\mathrm{Y}\:\mathrm{and}\:\mathrm{Z}.\: \\ $$$$\mathrm{The}\:\mathrm{speed}\:\mathrm{with}\:\mathrm{which}\:\mathrm{the}\:\mathrm{motocyclist}\:\mathrm{passes}\:\mathrm{X}\:\mathrm{and}\:\mathrm{Z}\:\mathrm{are}\:\mathrm{20m}/\mathrm{s}\:\mathrm{and}\:\mathrm{40m}/\mathrm{s}\: \\ $$$$\mathrm{respectively}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{with}\:\mathrm{which}\:\mathrm{the}\:\mathrm{motorcyclist}\:\mathrm{passes}\:\mathrm{Y}. \\ $$

Question Number 26320    Answers: 2   Comments: 3

solve x^2 −1=2^x

$$\mathrm{solve}\:{x}^{\mathrm{2}} −\mathrm{1}=\mathrm{2}^{{x}} \\ $$

Question Number 26312    Answers: 0   Comments: 6

Question Number 26298    Answers: 0   Comments: 2

y=sin^4 x y′=? differential

$${y}=\mathrm{sin}\:^{\mathrm{4}} {x} \\ $$$${y}'=?\:{differential} \\ $$

Question Number 26354    Answers: 1   Comments: 0

Question Number 26262    Answers: 1   Comments: 0

(x+5) (x−2)=17−x find the value of x

$$\left(\mathrm{x}+\mathrm{5}\right)\:\left(\mathrm{x}−\mathrm{2}\right)=\mathrm{17}−\mathrm{x}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x} \\ $$

Question Number 26246    Answers: 0   Comments: 0

If normal plasma is 7.4 and normal CO_2 is 1.2mm, what is the normal (H_2 CO_3 ^− )

$$\mathrm{If}\:\:\mathrm{normal}\:\mathrm{plasma}\:\mathrm{is}\:\mathrm{7}.\mathrm{4}\:\mathrm{and}\:\mathrm{normal}\:\:\mathrm{CO}_{\mathrm{2}} \:\mathrm{is}\:\mathrm{1}.\mathrm{2mm},\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{normal}\:\left(\mathrm{H}_{\mathrm{2}} \mathrm{CO}_{\mathrm{3}} ^{−} \right) \\ $$

Question Number 26174    Answers: 0   Comments: 0

Question Number 26166    Answers: 0   Comments: 0

Question Number 26156    Answers: 1   Comments: 0

a two digit number is 3 more than 4 times the sum of its digits. if 18 is added to this number .the sum is equal to number obtained by interchanging the digits.find the number

$${a}\:{two}\:{digit}\:{number}\:{is}\:\mathrm{3}\:{more}\:{than} \\ $$$$\mathrm{4}\:{times}\:{the}\:{sum}\:{of}\:{its}\:{digits}.\:{if} \\ $$$$\mathrm{18}\:{is}\:{added}\:{to}\:{this}\:{number}\:.{the}\: \\ $$$${sum}\:{is}\:{equal}\:{to}\:{number}\:{obtained} \\ $$$${by}\:{interchanging}\:{the}\:{digits}.{find}\:{the}\:{number} \\ $$

Question Number 26113    Answers: 1   Comments: 0

Question Number 26087    Answers: 0   Comments: 2

Given f(x) = (1 − x + x^2 − x^3 + ... − x^(2015) + x^(2016) )^2 Find the sum of all odd coeffisiens! Ex. f(x) = (x^2 + x + 1)^2 = 1x^4 + 2x^3 + 3x^2 + 2x + 1 The sum of odd coeffisien is 1 + 3 = 4

$$\mathrm{Given} \\ $$$${f}\left({x}\right)\:=\:\left(\mathrm{1}\:−\:{x}\:+\:{x}^{\mathrm{2}} \:−\:{x}^{\mathrm{3}} \:+\:...\:−\:{x}^{\mathrm{2015}} \:+\:{x}^{\mathrm{2016}} \right)^{\mathrm{2}} \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{all}\:\mathrm{odd}\:\mathrm{coeffisiens}! \\ $$$$ \\ $$$$\mathrm{Ex}.\:{f}\left({x}\right)\:=\:\left({x}^{\mathrm{2}} \:+\:{x}\:+\:\mathrm{1}\right)^{\mathrm{2}} \:=\:\mathrm{1}{x}^{\mathrm{4}} \:+\:\mathrm{2}{x}^{\mathrm{3}} \:+\:\mathrm{3}{x}^{\mathrm{2}} \:+\:\mathrm{2}{x}\:+\:\mathrm{1} \\ $$$$\mathrm{The}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{odd}\:\mathrm{coeffisien}\:\mathrm{is}\:\mathrm{1}\:+\:\mathrm{3}\:=\:\mathrm{4} \\ $$

Question Number 26078    Answers: 1   Comments: 0

x^2 −x−42 factorise

$$\mathrm{x}^{\mathrm{2}} −\mathrm{x}−\mathrm{42}\:\mathrm{factorise} \\ $$

Question Number 26058    Answers: 0   Comments: 0

Question Number 26047    Answers: 2   Comments: 6

Question Number 26046    Answers: 1   Comments: 0

x^3 + (1/x^3 )=18 find the valu of x+(1/x)

$${x}^{\mathrm{3}} +\:\frac{\mathrm{1}}{{x}^{\mathrm{3}} }=\mathrm{18}\:\:\mathrm{find}\:\mathrm{the}\:\mathrm{valu}\:\mathrm{of}\:{x}+\frac{\mathrm{1}}{{x}} \\ $$

Question Number 26031    Answers: 0   Comments: 0

calculate the number of protons which would have a charge of one coulomb charge(Proton Charge=1.6×10^(−19) C).

$${calculate}\:{the}\:{number}\:{of}\:{protons}\:{which}\:{would}\:{have}\:{a}\:{charge}\:{of}\:{one}\:{coulomb}\:{charge}\left({Proton}\:{Charge}=\mathrm{1}.\mathrm{6}×\mathrm{10}^{−\mathrm{19}} {C}\right). \\ $$

Question Number 26019    Answers: 0   Comments: 0

Question Number 25998    Answers: 1   Comments: 1

Question Number 26009    Answers: 1   Comments: 0

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