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LogarithmsQuestion and Answers: Page 7
Question Number 154989 Answers: 2 Comments: 0
$${x}_{\mathrm{1}} \:{and}\:{x}_{\mathrm{2}} \:{is}\:{root}\:\mathrm{log}_{\mathrm{2}} {x}^{\left(\mathrm{1}+^{\mathrm{2}} \mathrm{log}\:{x}\right)} =\mathrm{2},\:{the}\:{value} \\ $$$${is}\:{x}_{\mathrm{1}} +{x}_{\mathrm{2}} =\:... \\ $$$${a}.\:\mathrm{2}\frac{\mathrm{1}}{\mathrm{4}} \\ $$$${b}.\:\mathrm{2}\frac{\mathrm{1}}{\mathrm{2}} \\ $$$${c}.\:\mathrm{4}\frac{\mathrm{1}}{\mathrm{4}} \\ $$$${d}.\:\mathrm{4}\frac{\mathrm{1}}{\mathrm{2}} \\ $$$${e}.\:\mathrm{6}\frac{\mathrm{1}}{\mathrm{4}} \\ $$
Question Number 154573 Answers: 2 Comments: 1
Question Number 154334 Answers: 3 Comments: 1
$${the}\:{n}^{{th}} \:{term}\:{of} \\ $$$$\mathrm{1}\:,\:\mathrm{2},\:\mathrm{6},\:\mathrm{24},\:\mathrm{120}\:........\:{is}? \\ $$
Question Number 153958 Answers: 4 Comments: 0
Question Number 153959 Answers: 1 Comments: 0
Question Number 153950 Answers: 1 Comments: 0
Question Number 153840 Answers: 1 Comments: 0
$$\:\:\:\:\mathrm{log}\:_{{e}} \left({x}\right)+\mathrm{log}\:_{{x}} \left({e}\right)+\mathrm{log}\:_{\left(\frac{{e}}{{x}}\right)} \left({x}\right)=\frac{\mathrm{5}}{\mathrm{2}} \\ $$$$\:{x}=? \\ $$
Question Number 153681 Answers: 1 Comments: 0
$$\:\:\mathrm{24}^{\mathrm{log}\:_{\mathrm{10}} \left({x}\right)} −\mathrm{26}^{\mathrm{log}\:_{\mathrm{10}} \left({x}\right)} =\mathrm{1} \\ $$$$\:{x}=? \\ $$
Question Number 153109 Answers: 0 Comments: 1
$$\int\frac{\mathrm{dx}}{\mathrm{x}^{\mathrm{2}} +\mathrm{2x}+\mathrm{2}\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{2x}−\mathrm{4}}} \\ $$
Question Number 152976 Answers: 0 Comments: 0
Question Number 151895 Answers: 0 Comments: 0
Question Number 150641 Answers: 2 Comments: 1
$$\mathrm{1}+\sqrt{\mathrm{3}^{\mathrm{x}} }=\mathrm{2}^{\mathrm{x}} \\ $$$$\mathrm{x}=? \\ $$
Question Number 148494 Answers: 1 Comments: 0
$$\:\:\:\frac{\left(\mathrm{3}+\mathrm{2}\sqrt{\mathrm{2}}\right)^{\mathrm{2008}} }{\left(\mathrm{7}+\mathrm{5}\sqrt{\mathrm{2}}\right)^{\mathrm{1338}} }\:+\:\left(\mathrm{3}−\mathrm{2}\sqrt{\mathrm{2}}\right)\:=\:\mathrm{log}\:_{\mathrm{2}} \left(\mathrm{x}\right) \\ $$$$\:\mathrm{x}=?\: \\ $$
Question Number 148257 Answers: 2 Comments: 0
Question Number 148312 Answers: 1 Comments: 0
$${calculer}\:{la}\:{differentielle}\:{de}\: \\ $$$${y}={log}\left({x}\right) \\ $$$${teste}:\:{sachant}\:{que}\:{log}\left(\mathrm{35}\right)=\mathrm{1},\mathrm{54407}, \\ $$$${calculer}\:{log}\left(\mathrm{3501}\right) \\ $$$${NB}:\:{on}\:{rappelle}\:{que}\:\frac{\mathrm{1}}{{log}\left(\mathrm{10}\right)}={log}\left({e}\right)=\mathrm{0},\mathrm{43429}.. \\ $$
Question Number 148242 Answers: 2 Comments: 0
Question Number 147507 Answers: 1 Comments: 2
Question Number 147188 Answers: 0 Comments: 0
$${find}\:{the}\:{remainder}\:{when}\: \\ $$$$\mathrm{10}^{\mathrm{10}^{{n}} } \:{divides}\:\mathrm{7} \\ $$$$ \\ $$
Question Number 147108 Answers: 2 Comments: 0
Question Number 146849 Answers: 1 Comments: 1
Question Number 145829 Answers: 1 Comments: 0
Question Number 145437 Answers: 0 Comments: 0
$${original}\:{length}\:{of}\:{the}\:{iron}\:{rod}=\mathrm{175}.\mathrm{65} \\ $$$$\%\:{increase}=\mathrm{6}\frac{\mathrm{1}}{\mathrm{3}}\%×\mathrm{175}.\mathrm{65} \\ $$$$=\frac{\mathrm{19}}{\mathrm{3}}×\frac{\mathrm{1}}{\mathrm{100}}×\mathrm{175}.\mathrm{65} \\ $$$$=\frac{\mathrm{19}×\mathrm{175}.\mathrm{65}}{\mathrm{3}×\mathrm{100}}=\frac{\mathrm{3337}.\mathrm{35}}{\mathrm{300}}=\mathrm{11}.\mathrm{1245} \\ $$$${new}\:{length}={original}\:{length}+{increased}\:{length} \\ $$$$=\mathrm{175}.\mathrm{65}+\mathrm{11}.\mathrm{1245} \\ $$$$=\mathrm{186}.\mathrm{7745}{cm} \\ $$$${solution}\:{by}\:{CASIO}..... \\ $$$$ \\ $$
Question Number 145108 Answers: 1 Comments: 0
Question Number 145071 Answers: 1 Comments: 0
$$\mathrm{log}\:_{\left(\frac{\mathrm{x}}{\mathrm{2}}\right)} \left(\mathrm{x}+\mathrm{2}\right)\:=\:\mathrm{1}+\:\mathrm{log}\:_{\mathrm{x}} \left(\mathrm{4}−\mathrm{x}\right) \\ $$$$\:\mathrm{x}=? \\ $$
Question Number 145067 Answers: 1 Comments: 0
$$\:\mathrm{log}\:_{\mathrm{3}} \left({x}+\mathrm{1}\right)\:=\mathrm{log}\:_{\mathrm{4}} \left({x}+\mathrm{8}\right) \\ $$$$\:{x}=? \\ $$
Question Number 144504 Answers: 0 Comments: 0
$${for}\:{what}\:{values}\:{of}\:{b}\:{is} \\ $$$${ln}\left({a}−{b}\right){ln}\left({a}+{b}\right)\leqslant{ln}^{\mathrm{2}} {a} \\ $$$${Note}:\:\mathrm{0}\leqslant{b}<{a} \\ $$
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