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LogarithmsQuestion and Answers: Page 5

Question Number 172076 Answers: 2 Comments: 0

solve log(64(2^(x^2 −40x) )^(1/(24)) )=0

$${solve} \\ $$$${log}\left(\mathrm{64}\sqrt[{\mathrm{24}}]{\mathrm{2}^{{x}^{\mathrm{2}} −\mathrm{40}{x}} }\right)=\mathrm{0} \\ $$

Question Number 172085 Answers: 1 Comments: 0

solve (3^(x^3 −72x+39) −9(√3))×log(7−x)=0

$${solve} \\ $$$$\left(\mathrm{3}^{{x}^{\mathrm{3}} −\mathrm{72}{x}+\mathrm{39}} −\mathrm{9}\sqrt{\mathrm{3}}\right)×{log}\left(\mathrm{7}−{x}\right)=\mathrm{0} \\ $$

Question Number 172074 Answers: 1 Comments: 0

solve: 5^(logx) =50−x^(log5)

$${solve}: \\ $$$$\mathrm{5}^{{logx}} =\mathrm{50}−{x}^{{log}\mathrm{5}} \\ $$

Question Number 172086 Answers: 1 Comments: 5

solve 2^x^2 −40x=0

$${solve} \\ $$$$\mathrm{2}^{{x}^{\mathrm{2}} } −\mathrm{40}{x}=\mathrm{0} \\ $$

Question Number 172028 Answers: 1 Comments: 0

solve: ((log_2 (9−2^(x)) )/(log_2 2^((3−x)) ))=log_2 2

$${solve}: \\ $$$$\frac{{log}_{\mathrm{2}} \left(\mathrm{9}−\mathrm{2}^{\left.{x}\right)} \right.}{{log}_{\mathrm{2}} \mathrm{2}^{\left(\mathrm{3}−{x}\right)} }={log}_{\mathrm{2}} \mathrm{2} \\ $$

Question Number 171990 Answers: 1 Comments: 0

solve: log_7 2 + log_(49) x =log_7 (√3)

$${solve}: \\ $$$${log}_{\mathrm{7}} \mathrm{2}\:+\:{log}_{\mathrm{49}} {x}\:={log}_{\mathrm{7}} \sqrt{\mathrm{3}} \\ $$

Question Number 171477 Answers: 0 Comments: 0

Question Number 171331 Answers: 0 Comments: 0

Question Number 171284 Answers: 2 Comments: 0

g(x)=−x^2 +1−ln∣x∣ Study the variations of the function g and draw up its table of variations

$${g}\left({x}\right)=−{x}^{\mathrm{2}} +\mathrm{1}−{ln}\mid{x}\mid \\ $$Study the variations of the function g and draw up its table of variations

Question Number 171031 Answers: 1 Comments: 0

Question Number 176748 Answers: 2 Comments: 0

log_4 (√(8−x))=1−log_4 x solve for x

$${log}_{\mathrm{4}} \sqrt{\mathrm{8}−{x}}=\mathrm{1}−{log}_{\mathrm{4}} {x} \\ $$$${solve}\:{for}\:{x} \\ $$

Question Number 170843 Answers: 1 Comments: 0

Question Number 170958 Answers: 1 Comments: 0

log _5 (x+3)=log _6 (x+14)

$$\:\:\:\:\:\:\mathrm{log}\:_{\mathrm{5}} \left({x}+\mathrm{3}\right)=\mathrm{log}\:_{\mathrm{6}} \left({x}+\mathrm{14}\right) \\ $$

Question Number 170776 Answers: 0 Comments: 2

Question Number 170677 Answers: 0 Comments: 0

Question Number 170669 Answers: 0 Comments: 2

Question Number 170661 Answers: 0 Comments: 2

log^3 (√)x = (√(logx)) solve for X

$$\boldsymbol{\mathrm{log}}\:^{\mathrm{3}} \sqrt{}\boldsymbol{\mathrm{x}}\:\:\:=\:\:\:\sqrt{\boldsymbol{\mathrm{logx}}} \\ $$$$\boldsymbol{\mathrm{solve}}\:\:\boldsymbol{\mathrm{for}}\:\:\:\:\:\:\boldsymbol{{X}} \\ $$$$ \\ $$

Question Number 170327 Answers: 1 Comments: 0

Question Number 170020 Answers: 0 Comments: 0

log _((x+(1/4))) (2) < log _x (4)

$$\:\:\:\:\mathrm{log}\:_{\left({x}+\frac{\mathrm{1}}{\mathrm{4}}\right)} \left(\mathrm{2}\right)\:<\:\mathrm{log}\:_{{x}} \left(\mathrm{4}\right) \\ $$

Question Number 169918 Answers: 3 Comments: 0

A={z∈C: 2<∣z∣<4} fine log(A) where log is complex logaritmique

$${A}=\left\{\boldsymbol{{z}}\in\mathbb{C}:\:\mathrm{2}<\mid\boldsymbol{{z}}\mid<\mathrm{4}\right\} \\ $$$$\boldsymbol{{fine}}\:\boldsymbol{{log}}\left(\boldsymbol{{A}}\right) \\ $$$$\boldsymbol{{where}}\:\boldsymbol{{log}}\:\boldsymbol{{is}}\:\boldsymbol{{complex}}\:\boldsymbol{{logaritmique}} \\ $$

Question Number 169878 Answers: 2 Comments: 0

Question Number 169798 Answers: 0 Comments: 2

log_e (e^2 x^(lnx) )=log_e (x^3 ) faind x=?

$${log}_{{e}} \left({e}^{\mathrm{2}} {x}^{{lnx}} \right)={log}_{{e}} \left({x}^{\mathrm{3}} \right) \\ $$$${faind}\:\:{x}=? \\ $$

Question Number 168383 Answers: 2 Comments: 1

Question Number 167418 Answers: 0 Comments: 0

x^y =z (z)^(1/y) =x log_x (z)=y

$${x}^{{y}} ={z} \\ $$$$\sqrt[{{y}}]{{z}}={x} \\ $$$$\mathrm{log}_{{x}} \left({z}\right)={y} \\ $$

Question Number 167243 Answers: 1 Comments: 0

log _3 (x^2 −2)< log _3 ((3/2)∣x∣−1)

$$\:\:\:\:\:\:\mathrm{log}\:_{\mathrm{3}} \left({x}^{\mathrm{2}} −\mathrm{2}\right)<\:\mathrm{log}\:_{\mathrm{3}} \left(\frac{\mathrm{3}}{\mathrm{2}}\mid{x}\mid−\mathrm{1}\right)\: \\ $$

Question Number 167215 Answers: 2 Comments: 0

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