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Question Number 147035    Answers: 2   Comments: 0

using residue theorem evaluate ∫_(∣z∣=3) ((zsecz)/((z−1)^2 ))dz

$${using}\:{residue}\:{theorem} \\ $$$${evaluate}\:\:\int_{\mid{z}\mid=\mathrm{3}} \frac{{zsecz}}{\left({z}−\mathrm{1}\right)^{\mathrm{2}} }{dz} \\ $$

Question Number 146996    Answers: 1   Comments: 0

∫ln(cht)dt

$$\int{ln}\left({cht}\right){dt} \\ $$

Question Number 146962    Answers: 1   Comments: 0

Question Number 146933    Answers: 0   Comments: 0

.....# advanced calculu#...... I := ∫_(−∞) ^( +∞) sin(cosh(x).cos(sinhx))dx=? ....solution .... I:=(1/2) ∫_(−∞) ^( +∞) {sin (cosh(x)+sinh(x))+sin(cosh(x)−sinh (x))} :=_(sinh(x)=((e^( x) −e^( −x) )/2)) ^(cosh(x)=((e^( x) +e^( −x) )/2)) (1/2) ∫_(−∞) ^( +∞) {sin(e^x )+sin (e^( −x) )}dx := (1/2) ∫_(−∞) ^( ∞) sin(e^( x) )dx +[(1/2)∫_(−∞) ^( +∞) sin(e^( x) )dx :: x=^(sub) −x] := ∫_(−∞) ^( +∞) sin(e^( x) ) dx =^(e^( x) =y) ∫_0 ^( ∞) ((sin(t))/t) dt ...... I:= (π/2) ..... ...m.n.1970...

$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:.....#\:{advanced}\:\:{calculu}#...... \\ $$$$\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{I}\::=\:\int_{−\infty} ^{\:+\infty} {sin}\left({cosh}\left({x}\right).{cos}\left({sinhx}\right)\right){dx}=? \\ $$$$\:\:\:\:\:....{solution}\:.... \\ $$$$\:\:\:\:\:\:\:\mathrm{I}:=\frac{\mathrm{1}}{\mathrm{2}}\:\int_{−\infty} ^{\:+\infty} \left\{{sin}\:\left({cosh}\left({x}\right)+{sinh}\left({x}\right)\right)+{sin}\left({cosh}\left({x}\right)−{sinh}\:\left({x}\right)\right)\right\} \\ $$$$\:\:\:\:\:\:\:\:\::\underset{{sinh}\left({x}\right)=\frac{{e}^{\:{x}} −{e}^{\:−{x}} }{\mathrm{2}}} {\overset{{cosh}\left({x}\right)=\frac{{e}^{\:{x}} +{e}^{\:−{x}} }{\mathrm{2}}} {=}}\:\:\frac{\mathrm{1}}{\mathrm{2}}\:\int_{−\infty} ^{\:+\infty} \left\{{sin}\left({e}^{{x}} \right)+{sin}\:\left({e}^{\:−{x}} \right)\right\}{dx} \\ $$$$\:\:\:\:\:\:\:\:\::=\:\:\frac{\mathrm{1}}{\mathrm{2}}\:\int_{−\infty} ^{\:\infty} {sin}\left({e}^{\:{x}} \right){dx}\:+\left[\frac{\mathrm{1}}{\mathrm{2}}\int_{−\infty} ^{\:+\infty} {sin}\left({e}^{\:{x}} \right){dx}\:::\:\:{x}\overset{{sub}} {=}−{x}\right] \\ $$$$\:\:\:\:\:\:\:\::=\:\int_{−\infty} ^{\:+\infty} {sin}\left({e}^{\:{x}} \:\right)\:{dx}\:\overset{{e}^{\:{x}} ={y}} {=}\:\int_{\mathrm{0}} ^{\:\infty} \frac{{sin}\left({t}\right)}{{t}}\:{dt}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:......\:\mathrm{I}:=\:\frac{\pi}{\mathrm{2}}\:..... \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:...{m}.{n}.\mathrm{1970}... \\ $$$$\: \\ $$$$ \\ $$

Question Number 146836    Answers: 0   Comments: 0

Σ_(n=1) ^∞ (1/(ϕ^( n) F_n )) =?

$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\varphi^{\:{n}} \:\mathrm{F}_{{n}} }\:=? \\ $$

Question Number 146835    Answers: 2   Comments: 0

calculate ∫_0 ^∞ (dx/((x^2 +3)^2 (x^2 +4)^2 ))

$$\mathrm{calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{\mathrm{dx}}{\left(\mathrm{x}^{\mathrm{2}} \:+\mathrm{3}\right)^{\mathrm{2}} \left(\mathrm{x}^{\mathrm{2}} \:+\mathrm{4}\right)^{\mathrm{2}} } \\ $$

Question Number 146791    Answers: 1   Comments: 0

∫(x/(1+cos^2 (x)))dx

$$\int\frac{\mathrm{x}}{\mathrm{1}+\mathrm{cos}^{\mathrm{2}} \left(\mathrm{x}\right)}\mathrm{dx} \\ $$

Question Number 146790    Answers: 1   Comments: 0

∫(1/x) e^(−(1/x^2 )) dx

$$\int\frac{\mathrm{1}}{\mathrm{x}}\:\mathrm{e}^{−\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{2}} }} \mathrm{dx} \\ $$

Question Number 146767    Answers: 1   Comments: 0

Σ_(n=0) ^∞ (((−1)^n )/(n+1))(1+(1/3)+...+(1/(2n+1)))=?

$$\underset{\mathrm{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{\mathrm{n}} }{\mathrm{n}+\mathrm{1}}\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{3}}+...+\frac{\mathrm{1}}{\mathrm{2n}+\mathrm{1}}\right)=? \\ $$

Question Number 146756    Answers: 2   Comments: 0

∫_( 0) ^( 1) t^2 + 1 dt

$$ \\ $$$$ \\ $$$$\underset{\:\mathrm{0}} {\overset{\:\mathrm{1}} {\int}}\:{t}^{\mathrm{2}} \:+\:\mathrm{1}\:{dt} \\ $$

Question Number 146752    Answers: 1   Comments: 0

∫_( 0) ^( 1) t^2 + (1/2)t −6dx

$$ \\ $$$$\underset{\:\mathrm{0}} {\overset{\:\mathrm{1}} {\int}}\:{t}^{\mathrm{2}} +\:\frac{\mathrm{1}}{\mathrm{2}}{t}\:−\mathrm{6}{dx}\:\: \\ $$

Question Number 146736    Answers: 1   Comments: 0

1: S:= Σ_(n=1) ^∞ (((−1)^( n−1) )/(n.2^( n) )) =? 2: A:= Σ(((−1)^( n−1) )/(n^2 . 2^( n) )) =?

$$ \\ $$$$\:\:\:\:\:\:\mathrm{1}:\:\:\:\:\mathrm{S}:=\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{\:{n}−\mathrm{1}} }{{n}.\mathrm{2}^{\:{n}} }\:=? \\ $$$$\:\:\:\:\:\:\mathrm{2}:\:\:\:\:\mathrm{A}:=\:\Sigma\frac{\left(−\mathrm{1}\right)^{\:{n}−\mathrm{1}} }{{n}^{\mathrm{2}} .\:\mathrm{2}^{\:{n}} }\:=? \\ $$

Question Number 146735    Answers: 2   Comments: 0

Σ_(n=1) ^∞ ((1+(1/2)+(1/3)+...+(1/n))/((n+1)(n+2)))=?

$$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{2}}+\frac{\mathrm{1}}{\mathrm{3}}+...+\frac{\mathrm{1}}{\mathrm{n}}}{\left(\mathrm{n}+\mathrm{1}\right)\left(\mathrm{n}+\mathrm{2}\right)}=? \\ $$

Question Number 146697    Answers: 0   Comments: 0

∀t≥−1,F(t)=(2/π)∫_0 ^(π/2) (√(1+tcos^2 ϕ))dϕ 1) Show that ∀t≤−1 F(t)=(√(1+t))F(−(1/(1+t))) 2) show that if 0≤t_1 , 0≤F(t_2 )−F(t_1 )≤((t_2 −t_1 )/4)

$$\forall{t}\geqslant−\mathrm{1},{F}\left({t}\right)=\frac{\mathrm{2}}{\pi}\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \sqrt{\mathrm{1}+{tcos}^{\mathrm{2}} \varphi}{d}\varphi \\ $$$$\left.\mathrm{1}\right)\:{Show}\:{that}\:\forall{t}\leqslant−\mathrm{1}\:{F}\left({t}\right)=\sqrt{\mathrm{1}+{t}}{F}\left(−\frac{\mathrm{1}}{\mathrm{1}+{t}}\right) \\ $$$$\left.\mathrm{2}\right)\:{show}\:{that}\:{if}\:\mathrm{0}\leqslant{t}_{\mathrm{1}} \:, \\ $$$$\mathrm{0}\leqslant{F}\left({t}_{\mathrm{2}} \right)−{F}\left({t}_{\mathrm{1}} \right)\leqslant\frac{{t}_{\mathrm{2}} −{t}_{\mathrm{1}} }{\mathrm{4}} \\ $$

Question Number 146669    Answers: 1   Comments: 0

∫_0 ^π (a−e^(−ix) )^n (a−e^(ix) )^n cos(nx)dx

$$\int_{\mathrm{0}} ^{\pi} \left(\mathrm{a}−\mathrm{e}^{−\mathrm{ix}} \right)^{\mathrm{n}} \left(\mathrm{a}−\mathrm{e}^{\mathrm{ix}} \right)^{\mathrm{n}} \mathrm{cos}\left(\mathrm{nx}\right)\mathrm{dx} \\ $$

Question Number 146619    Answers: 1   Comments: 0

solve :: ( x ∈ R ) [ x ] = [ x^( 2) − x −6 ] note:: [x ] := max { q ∈ Z ∣ q ≤ x }

$$ \\ $$$$\:\:\:\:{solve}\:::\:\:\:\left(\:{x}\:\in\:\mathbb{R}\:\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left[\:{x}\:\right]\:=\:\left[\:{x}^{\:\mathrm{2}} −\:{x}\:−\mathrm{6}\:\right] \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:{note}::\:\:\:\left[{x}\:\right]\::=\:{max}\:\left\{\:{q}\:\in\:\mathbb{Z}\:\mid\:{q}\:\leqslant\:{x}\:\right\} \\ $$

Question Number 146597    Answers: 5   Comments: 0

∫ ((cos 5x+cos 4x)/(1−2cos 3x)) dx =? ∫ ((√(tan x))/(sin 2x)) dx =? ∫ (dx/( (√(cos^3 x sin^5 x)))) =?

$$\:\:\:\:\int\:\frac{\mathrm{cos}\:\mathrm{5x}+\mathrm{cos}\:\mathrm{4x}}{\mathrm{1}−\mathrm{2cos}\:\mathrm{3x}}\:\mathrm{dx}\:=?\: \\ $$$$\:\:\int\:\frac{\sqrt{\mathrm{tan}\:\mathrm{x}}}{\mathrm{sin}\:\mathrm{2x}}\:\mathrm{dx}\:=? \\ $$$$\:\:\int\:\frac{\mathrm{dx}}{\:\sqrt{\mathrm{cos}\:^{\mathrm{3}} \mathrm{x}\:\mathrm{sin}\:^{\mathrm{5}} \mathrm{x}}}\:=? \\ $$

Question Number 146584    Answers: 0   Comments: 0

......nice ... ... ... calculus...... Ω= ∫_0 ^( 4) x^( 2) d (⌊x+⌊x +⌊x+⌊x⌋⌋⌋)=?

$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:......{nice}\:...\:...\:...\:{calculus}...... \\ $$$$\: \\ $$$$\Omega=\:\int_{\mathrm{0}} ^{\:\mathrm{4}} {x}^{\:\mathrm{2}} \:{d}\:\left(\lfloor{x}+\lfloor{x}\:+\lfloor{x}+\lfloor{x}\rfloor\rfloor\rfloor\right)=?\: \\ $$$$ \\ $$

Question Number 146582    Answers: 1   Comments: 0

∫ tan^4 x cos^2 x dx =?

$$\:\:\:\int\:\mathrm{tan}\:^{\mathrm{4}} \mathrm{x}\:\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}\:\mathrm{dx}\:=? \\ $$

Question Number 146577    Answers: 2   Comments: 1

Question Number 146455    Answers: 1   Comments: 0

Given that F(x) = ∫_0 ^x (t^2 /( (√(t^2 +1))))dt Show that F(x) is an increasing function

$$\mathrm{Given}\:\mathrm{that}\:\:{F}\left({x}\right)\:=\:\int_{\mathrm{0}} ^{{x}} \frac{{t}^{\mathrm{2}} }{\:\sqrt{{t}^{\mathrm{2}} +\mathrm{1}}}{dt}\: \\ $$$$\:\mathrm{Show}\:\mathrm{that}\:{F}\left({x}\right)\:\mathrm{is}\:\mathrm{an}\:\mathrm{increasing}\:\mathrm{function} \\ $$

Question Number 146429    Answers: 1   Comments: 1

Σ_(n=1) ^∞ (n∙ln((2n+1)/(2n−1))−1)=?

$$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left(\mathrm{n}\centerdot\mathrm{ln}\frac{\mathrm{2n}+\mathrm{1}}{\mathrm{2n}−\mathrm{1}}−\mathrm{1}\right)=? \\ $$

Question Number 146361    Answers: 2   Comments: 0

find ∫(1/(x^n +1))dx for n∈N

$${find}\:\int\frac{\mathrm{1}}{{x}^{{n}} +\mathrm{1}}{dx}\:{for}\:{n}\in{N} \\ $$

Question Number 146307    Answers: 1   Comments: 0

S_n =Σ_(k=1) ^n (( 1)/(k (k+2)k+4))) lim_( n→∞) ( S_( n) ) = ?

$$ \\ $$$$\:\:\:\:\:\:\:\mathrm{S}_{{n}} \:=\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{\:\mathrm{1}}{\left.{k}\:\left({k}+\mathrm{2}\right){k}+\mathrm{4}\right)} \\ $$$$\:\:\:\:\:\:\:\:{lim}_{\:{n}\rightarrow\infty} \:\left(\:\:\mathrm{S}_{\:{n}} \:\right)\:=\:? \\ $$

Question Number 146290    Answers: 0   Comments: 5

Question Number 146181    Answers: 4   Comments: 0

Σ_(n=0) ^∞ (1/(2^( n) (n+1 ) ( n + 2 ))) =?

$$ \\ $$$$\:\:\:\:\:\:\:\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\mathrm{2}^{\:{n}} \:\left({n}+\mathrm{1}\:\right)\:\left(\:{n}\:+\:\mathrm{2}\:\right)}\:=? \\ $$

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