Question Number 209957 by Jubr last updated on 26/Jul/24 | ||
If x, y are contain in natural numbers and x² + y² = 613² Find the values of x + y = ? | ||
Answered by Frix last updated on 27/Jul/24 | ||
$$\mathrm{35}^{\mathrm{2}} +\mathrm{612}^{\mathrm{2}} =\mathrm{613}^{\mathrm{2}} \:\:\:\:\:{x}+{y}=\mathrm{647} \\ $$$$\mathrm{0}^{\mathrm{2}} +\mathrm{613}^{\mathrm{2}} =\mathrm{613}^{\mathrm{2}} \:\:\:\:\:\:\:\:{x}+{y}=\mathrm{613} \\ $$ | ||
Commented by Jubr last updated on 28/Jul/24 | ||
$${Thanks}\:{sir} \\ $$ | ||