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Question Number 209957 by Jubr last updated on 26/Jul/24

If x, y are contain in natural numbers  and  x² + y² = 613²   Find the values of x + y = ?

If x, y are contain in natural numbers and x² + y² = 613² Find the values of x + y = ?

Answered by Frix last updated on 27/Jul/24

35^2 +612^2 =613^2      x+y=647  0^2 +613^2 =613^2         x+y=613

$$\mathrm{35}^{\mathrm{2}} +\mathrm{612}^{\mathrm{2}} =\mathrm{613}^{\mathrm{2}} \:\:\:\:\:{x}+{y}=\mathrm{647} \\ $$$$\mathrm{0}^{\mathrm{2}} +\mathrm{613}^{\mathrm{2}} =\mathrm{613}^{\mathrm{2}} \:\:\:\:\:\:\:\:{x}+{y}=\mathrm{613} \\ $$

Commented by Jubr last updated on 28/Jul/24

Thanks sir

$${Thanks}\:{sir} \\ $$

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