Question Number 124210 by bramlexs22 last updated on 01/Dec/20 | ||
$$\:{If}\:{x}\:+\:\sqrt{{x}}\:=\:\mathrm{2020}\: \\ $$$${then}\:{x}\:+\:\frac{\mathrm{2020}}{\:\sqrt{{x}}}\:=\:? \\ $$ | ||
Answered by malwan last updated on 01/Dec/20 | ||
$${x}\:+\:\sqrt{{x}}\:=\:\mathrm{2020}\:\left(\boldsymbol{\div}\sqrt{{x}}\right) \\ $$$$\Rightarrow\sqrt{{x}}\:+\:\mathrm{1}\:=\:\frac{\mathrm{2020}}{\:\sqrt{{x}}} \\ $$$$\therefore\:{x}\:+\:\frac{\mathrm{2020}}{\:\sqrt{{x}}}\:=\:{x}\:+\:\sqrt{{x}}\:+\:\mathrm{1}=\mathrm{2020}+\mathrm{1}=\mathrm{2021} \\ $$ | ||
Commented by MJS_new last updated on 01/Dec/20 | ||
$$\mathrm{your}\:\mathrm{behaviour}\:\mathrm{is}\:\mathrm{more}\:\mathrm{boring}\:\mathrm{than}\:\mathrm{offending} \\ $$ | ||
Commented by malwan last updated on 01/Dec/20 | ||
$${sir}\:{Mammadli} \\ $$$${you}\:{can}\:{send}\:{this}\:{comment}\:{as}\:{question} \\ $$ | ||
Answered by bramlexs22 last updated on 01/Dec/20 | ||