Question Number 217075 by maths_plus last updated on 28/Feb/25 | ||
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$$ \\ $$Help me please... $\vv{AB}$ and $\vv{CD}$ are two vectors, and $\vv{AB}$ is not the zero vector. Prove that if the vectors $\vv{AB}$ and $\vv{CD}$ are colinear, then there exists a real number \( k \) such that \( \vv{CD} = k \vv{AB} \). (don't use coordinates !) | ||
Commented by maths_plus last updated on 28/Feb/25 | ||
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$$\mathrm{why}\:\mathrm{they}\:\mathrm{banned}\:\mathrm{this}\:\mathrm{post}\:? \\ $$ | ||
Commented by MathematicalUser2357 last updated on 01/Mar/25 | ||
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$$\mathrm{No},\:\mathrm{someone}\:\mathrm{flagged}\:\mathrm{this}\:\mathrm{post}\:\mathrm{as}\:\mathrm{inappropriate}. \\ $$ | ||
Commented by Tinku Tara last updated on 01/Mar/25 | ||
This is not inappropriate. This post has no issue. | ||