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Question Number 43461 Answers: 0 Comments: 1

found something (others have found before) which I thought might be of interest, especially for Sir Tanmay Chaudhury: take any polynome of degree 4 with 2 real inflection points y=ax^4 +bx^3 +cx^2 +dx+e y′′=12ax^2 +6bx+2c=0 has got 2 real solutions x_1 and x_2 the line connecting the inflection points intersects the curve in 2 more points P and Q, their x−values are p and q let p<x_1 <x_2 <q ⇒ ((x_2 −x_1 )/(x_1 −p))=((x_2 −x_1 )/(q−x_2 ))=(1/2)+((√5)/2) which is the Golden Ratio

$$\mathrm{found}\:\mathrm{something}\:\left(\mathrm{others}\:\mathrm{have}\:\mathrm{found}\:\mathrm{before}\right) \\ $$$$\mathrm{which}\:\mathrm{I}\:\mathrm{thought}\:\mathrm{might}\:\mathrm{be}\:\mathrm{of}\:\mathrm{interest}, \\ $$$$\mathrm{especially}\:\mathrm{for}\:\mathrm{Sir}\:\mathrm{Tanmay}\:\mathrm{Chaudhury}: \\ $$$$\mathrm{take}\:\mathrm{any}\:\mathrm{polynome}\:\mathrm{of}\:\mathrm{degree}\:\mathrm{4}\:\mathrm{with}\:\mathrm{2}\:\mathrm{real} \\ $$$$\mathrm{inflection}\:\mathrm{points} \\ $$$${y}={ax}^{\mathrm{4}} +{bx}^{\mathrm{3}} +{cx}^{\mathrm{2}} +{dx}+{e} \\ $$$${y}''=\mathrm{12}{ax}^{\mathrm{2}} +\mathrm{6}{bx}+\mathrm{2}{c}=\mathrm{0}\:\mathrm{has}\:\mathrm{got}\:\mathrm{2}\:\mathrm{real}\:\mathrm{solutions} \\ $$$${x}_{\mathrm{1}} \:\mathrm{and}\:{x}_{\mathrm{2}} \\ $$$$\mathrm{the}\:\mathrm{line}\:\mathrm{connecting}\:\mathrm{the}\:\mathrm{inflection}\:\mathrm{points} \\ $$$$\mathrm{intersects}\:\mathrm{the}\:\mathrm{curve}\:\mathrm{in}\:\mathrm{2}\:\mathrm{more}\:\mathrm{points} \\ $$$${P}\:\mathrm{and}\:{Q},\:\mathrm{their}\:{x}−\mathrm{values}\:\mathrm{are}\:{p}\:\mathrm{and}\:{q} \\ $$$$\mathrm{let}\:{p}<{x}_{\mathrm{1}} <{x}_{\mathrm{2}} <{q} \\ $$$$\Rightarrow\:\frac{{x}_{\mathrm{2}} −{x}_{\mathrm{1}} }{{x}_{\mathrm{1}} −{p}}=\frac{{x}_{\mathrm{2}} −{x}_{\mathrm{1}} }{{q}−{x}_{\mathrm{2}} }=\frac{\mathrm{1}}{\mathrm{2}}+\frac{\sqrt{\mathrm{5}}}{\mathrm{2}}\:\mathrm{which}\:\mathrm{is}\:\mathrm{the}\:\mathrm{Golden}\:\mathrm{Ratio} \\ $$

Question Number 43360 Answers: 0 Comments: 9

Question Number 43338 Answers: 1 Comments: 1

Question Number 43264 Answers: 2 Comments: 1

Question Number 43263 Answers: 2 Comments: 0

Question Number 43205 Answers: 1 Comments: 0

Question Number 43135 Answers: 1 Comments: 4

Construct a triangle ΔABC with ∠B=50° AC=6 cm AB+BC=8 cm see also Q42942.

$${Construct}\:{a}\:{triangle}\:\Delta{ABC}\:{with} \\ $$$$\angle{B}=\mathrm{50}° \\ $$$${AC}=\mathrm{6}\:{cm} \\ $$$${AB}+{BC}=\mathrm{8}\:{cm} \\ $$$$ \\ $$$${see}\:{also}\:{Q}\mathrm{42942}. \\ $$

Question Number 42948 Answers: 1 Comments: 5

Question Number 42942 Answers: 2 Comments: 0

Question Number 42592 Answers: 1 Comments: 0

Question Number 42583 Answers: 0 Comments: 6

Question Number 42352 Answers: 1 Comments: 0

Question Number 42154 Answers: 0 Comments: 5

Question Number 42112 Answers: 1 Comments: 1

Question Number 42045 Answers: 0 Comments: 2

i have some thing to say...in this platform several people/students/others post questions..others take promt action to solve the problems.. after the problem got solved..the person/students who post questions never attend or see the answer even do not clarify whether the answer is right or wrong...or whether he/she got understood the method...so pls show your courtsey otherwise your problem remain a problem and nobody bother to solve it...Than you all

$${i}\:{have}\:{some}\:{thing}\:{to}\:{say}...{in}\:{this}\:{platform}\:\:{several} \\ $$$${people}/{students}/{others}\:{post}\:{questions}..{others} \\ $$$${take}\:{promt}\:{action}\:{to}\:{solve}\:{the}\:{problems}.. \\ $$$${after}\:{the}\:{problem}\:{got}\:{solved}..{the}\:{person}/{students} \\ $$$${who}\:{post}\:{questions}\:{never}\:{attend}\:{or}\:{see}\:{the}\:{answer} \\ $$$${even}\:{do}\:{not}\:{clarify}\:{whether}\:{the}\:{answer}\:{is}\:{right} \\ $$$${or}\:{wrong}...{or}\:{whether}\:{he}/{she}\:{got}\:{understood}\:{the} \\ $$$${method}...{so}\:{pls}\:{show}\:{your}\:{courtsey}\:{otherwise} \\ $$$${your}\:{problem}\:{remain}\:{a}\:{problem}\:{and}\:{nobody}\:{bother} \\ $$$${to}\:{solve}\:{it}...{Than}\:{you}\:{all} \\ $$

Question Number 42310 Answers: 1 Comments: 1