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GeometryQuestion and Answers: Page 53

Question Number 160839    Answers: 2   Comments: 1

Question Number 160719    Answers: 1   Comments: 2

Question Number 160618    Answers: 1   Comments: 0

Question Number 160608    Answers: 0   Comments: 6

$$ \\ $$$$ \\ $$

Question Number 160553    Answers: 0   Comments: 0

Question Number 160504    Answers: 1   Comments: 2

Question Number 160420    Answers: 0   Comments: 0

Question Number 160353    Answers: 1   Comments: 0

Question Number 160325    Answers: 1   Comments: 3

Question Number 160205    Answers: 3   Comments: 0

Question Number 160014    Answers: 1   Comments: 2

Question Number 159999    Answers: 1   Comments: 0

Question Number 159911    Answers: 1   Comments: 0

Question Number 159864    Answers: 2   Comments: 0

Question Number 159829    Answers: 0   Comments: 2

((y/b))^(2/3) +((x/a))^(2/3) =1 find the length of the line

$$\left(\frac{\boldsymbol{\mathrm{y}}}{\boldsymbol{\mathrm{b}}}\right)^{\frac{\mathrm{2}}{\mathrm{3}}} +\left(\frac{\boldsymbol{\mathrm{x}}}{\boldsymbol{\mathrm{a}}}\right)^{\frac{\mathrm{2}}{\mathrm{3}}} =\mathrm{1}\:\: \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{length}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{line}} \\ $$

Question Number 159828    Answers: 0   Comments: 6

Question Number 159784    Answers: 0   Comments: 1

Question Number 159763    Answers: 0   Comments: 4

Question Number 159742    Answers: 1   Comments: 0

Find the perimeter of the figure which is bounded with the curves y^3 =x^2 and y=(√(2−x^2 ))

$$\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{perimeter}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{figure}}\:\boldsymbol{\mathrm{which}}\:\boldsymbol{\mathrm{is}} \\ $$$$\boldsymbol{\mathrm{bounded}}\:\boldsymbol{\mathrm{with}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{curves}}\:\boldsymbol{\mathrm{y}}^{\mathrm{3}} =\boldsymbol{\mathrm{x}}^{\mathrm{2}} \:\boldsymbol{\mathrm{and}}\:\boldsymbol{\mathrm{y}}=\sqrt{\mathrm{2}−\boldsymbol{\mathrm{x}}^{\mathrm{2}} } \\ $$

Question Number 159606    Answers: 2   Comments: 1

Question Number 159392    Answers: 1   Comments: 1

Question Number 159005    Answers: 2   Comments: 0

Question Number 158964    Answers: 0   Comments: 1

Question Number 158924    Answers: 1   Comments: 3

Question Number 158893    Answers: 1   Comments: 0

Question Number 158749    Answers: 2   Comments: 1

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