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GeometryQuestion and Answers: Page 10

Question Number 218580    Answers: 1   Comments: 3

Question Number 218528    Answers: 3   Comments: 0

Question Number 218527    Answers: 1   Comments: 0

Question Number 218526    Answers: 2   Comments: 2

Question Number 218525    Answers: 1   Comments: 0

Question Number 218494    Answers: 4   Comments: 0

Question Number 218493    Answers: 2   Comments: 0

Question Number 218491    Answers: 5   Comments: 1

Question Number 218475    Answers: 5   Comments: 0

Question Number 218456    Answers: 5   Comments: 0

Question Number 218411    Answers: 2   Comments: 0

Question Number 218410    Answers: 3   Comments: 0

Question Number 218393    Answers: 1   Comments: 0

let ABC be a triangle with incenter I. prove that Ia . Ib . Ic ≤ ((abc)/8)

$$ \\ $$$$\:{let}\:{ABC}\:{be}\:{a}\:{triangle}\:{with}\:{incenter}\:{I}. \\ $$$$\:{prove}\:{that}\:{Ia}\:.\:{Ib}\:.\:{Ic}\:\:\leqslant\:\frac{{abc}}{\mathrm{8}}\:\: \\ $$$$ \\ $$

Question Number 218385    Answers: 3   Comments: 0

Question Number 218267    Answers: 1   Comments: 1

Question Number 218257    Answers: 1   Comments: 2

Question Number 218236    Answers: 1   Comments: 3

Question Number 222197    Answers: 1   Comments: 0

question 211277

$${question}\:\mathrm{211277} \\ $$

Question Number 218021    Answers: 1   Comments: 0

Question Number 218013    Answers: 1   Comments: 0

Question Number 217931    Answers: 2   Comments: 1

Given a regular triangle ABC. AG=2GC. CK=2KB. AK∩BG=M. Prove that CM⊥AK.

$$\mathrm{Given}\:\mathrm{a}\:\mathrm{regular}\:\mathrm{triangle}\:{ABC}. \\ $$$${AG}=\mathrm{2}{GC}.\:{CK}=\mathrm{2}{KB}.\:{AK}\cap{BG}={M}. \\ $$$$\mathrm{Prove}\:\mathrm{that}\:{CM}\bot{AK}. \\ $$

Question Number 217912    Answers: 0   Comments: 2

$$ \\ $$

Question Number 217694    Answers: 0   Comments: 0

Question Number 217686    Answers: 1   Comments: 3

Question Number 217631    Answers: 1   Comments: 1

Question Number 217519    Answers: 1   Comments: 1

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