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Question Number 59608 by Andrew Foxman last updated on 12/May/19
$${For}\:{your}\:{development}\:{solve}\:{this} \\ $$$$\frac{{d}^{\mathrm{2}} {r}}{{dt}^{\mathrm{2}} }=\frac{{A}}{{r}^{\mathrm{2}} \left({t}\right)}\:\:{where}\:{r}\left({t}\right)=\alpha{t}^{\beta} \\ $$