Question Number 155174 by Fridunatjan08 last updated on 26/Sep/21 | ||
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$${Find}\:{n}\:{if}: \\ $$$$\mathrm{133}^{\mathrm{5}} +\mathrm{110}^{\mathrm{5}} +\mathrm{84}^{\mathrm{5}} +\mathrm{27}^{\mathrm{5}} ={n}^{\mathrm{5}} \\ $$ | ||
Answered by MJS_new last updated on 26/Sep/21 | ||
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$$\mathrm{144} \\ $$ | ||
Commented by Fridunatjan08 last updated on 02/Oct/21 | ||
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$${please}\:{sir}\:{show}\:{me}\:{the}\:{steps}. \\ $$ | ||
Answered by Skabetix last updated on 26/Sep/21 | ||
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$$\left(\mathrm{133}^{\mathrm{5}} +\mathrm{110}^{\mathrm{5}} +\mathrm{84}^{\mathrm{5}} +\mathrm{27}^{\mathrm{5}} \right)^{\left(\mathrm{1}/\mathrm{5}\right)} ={n}=\mathrm{144} \\ $$ | ||