Previous in Differential Equation Next in Differential Equation | ||
Question Number 6505 by nburiburu last updated on 29/Jun/16 | ||
$${Find}\:{general}\:{solution}\:{for} \\ $$$${y}'\:+{P}\left({x}\right)\centerdot{y}^{\mathrm{2}} ={Q}\left({x}\right) \\ $$$$ \\ $$ | ||