Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 197052 by pete last updated on 07/Sep/23

Find all the values of sin^(−1) (√2)

$$\mathrm{Find}\:\mathrm{all}\:\mathrm{the}\:\mathrm{values}\:\mathrm{of}\:\mathrm{sin}^{−\mathrm{1}} \sqrt{\mathrm{2}} \\ $$

Answered by Frix last updated on 07/Sep/23

sin x =(√2)  x=(2n−(1/2))π±i ln (1+(√2))  You get this using  sin x =((e^(ix) −e^(−ix) )/(2i))

$$\mathrm{sin}\:{x}\:=\sqrt{\mathrm{2}} \\ $$$${x}=\left(\mathrm{2}{n}−\frac{\mathrm{1}}{\mathrm{2}}\right)\pi\pm\mathrm{i}\:\mathrm{ln}\:\left(\mathrm{1}+\sqrt{\mathrm{2}}\right) \\ $$$$\mathrm{You}\:\mathrm{get}\:\mathrm{this}\:\mathrm{using} \\ $$$$\mathrm{sin}\:{x}\:=\frac{\mathrm{e}^{\mathrm{i}{x}} −\mathrm{e}^{−\mathrm{i}{x}} }{\mathrm{2i}} \\ $$

Commented by pete last updated on 07/Sep/23

thank you sir

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com