Question Number 120 by novrya last updated on 25/Jan/15 | ||
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$${Evaluate}\:\int{tan}\:\theta\:{d}\theta \\ $$ | ||
Answered by ssahoo last updated on 06/Dec/14 | ||
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$$\int\mathrm{tan}\:\theta\:\:{d}\theta \\ $$$$=\int\frac{\mathrm{sin}\:\theta}{\mathrm{cos}\:\theta}{d}\theta \\ $$$$\mathrm{substituting}\:\mathrm{cos}\:\theta={y} \\ $$$$−\mathrm{sin}\:\theta{d}\theta={dy} \\ $$$$\int\frac{\mathrm{sin}\:\theta}{\mathrm{cos}\:\theta}{d}\theta=\int−\:\frac{{dy}}{{y}} \\ $$$$=−\mathrm{ln}\:\mid{y}\mid+{C} \\ $$$$=−\mathrm{ln}\:\mid\mathrm{cos}\:\theta\mid+{C} \\ $$ | ||