Question Number 122646 by mathocean1 last updated on 18/Nov/20 | ||
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$${Determinate}\:{the}\:{couples}\: \\ $$$$\left({a};\:{b}\right)\:{such}\:{that}\: \\ $$$${GCD}\left({a};{b}\right)+{LCM}\left({a};{b}\right)={a}+{b} \\ $$$${GCD}:\:{greatest}\:{common}\:{divisor} \\ $$$${LCM}:\:{least}\:{common}\:{multiple} \\ $$ | ||
Commented by mathocean1 last updated on 18/Nov/20 | ||
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$${so}\:{we}\:{have}\:{m}\:{couples}\:{sir}? \\ $$ | ||
Commented by mr W last updated on 18/Nov/20 | ||
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$${a}={p}_{\mathrm{1}} {p}_{\mathrm{2}} ...{p}_{{m}} \:{with}\:{p}={any}\:{prime}\:{number} \\ $$$${b}={p}_{\mathrm{1}} ^{{n}_{\mathrm{1}} } {p}_{\mathrm{2}} ^{{n}_{\mathrm{2}} } ...{p}_{{m}} ^{{n}_{{m}} } \\ $$$${gcd}\left({a},{b}\right)={a} \\ $$$${lcm}\left({a},{b}\right)={b} \\ $$ | ||
Commented by mr W last updated on 18/Nov/20 | ||
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$${infinite}\:{couples}! \\ $$ | ||
Commented by mathocean1 last updated on 18/Nov/20 | ||
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$${ok}\:{sir} \\ $$$$ \\ $$ | ||