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Question Number 119713 Answers: 1 Comments: 3

If 3x+(1/(2x))=6 find 8x^3 +(1/(27x^3 ))

$$\mathrm{If}\:\mathrm{3x}+\frac{\mathrm{1}}{\mathrm{2x}}=\mathrm{6}\:\mathrm{find}\:\mathrm{8x}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{27x}^{\mathrm{3}} } \\ $$

Question Number 119702 Answers: 0 Comments: 0

Question Number 119706 Answers: 0 Comments: 4

hello i hop all of you doing well can somoene help me too find lecture about dilogarithmes,trilogarithmes identities god bless you

$${hello}\:{i}\:{hop}\:{all}\:{of}\:{you}\:{doing}\:{well} \\ $$$${can}\:{somoene}\:{help}\:{me}\:{too}\:{find}\:{lecture} \\ $$$${about}\:{dilogarithmes},{trilogarithmes} \\ $$$${identities}\: \\ $$$${god}\:{bless}\:{you} \\ $$

Question Number 119696 Answers: 2 Comments: 0

For a<b then ∫_a ^b (x−a)(x−b) dx equal to _

$${For}\:{a}<{b}\:{then}\:\underset{{a}} {\overset{{b}} {\int}}\:\left({x}−{a}\right)\left({x}−{b}\right)\:{dx}\: \\ $$$${equal}\:{to}\:\_ \\ $$

Question Number 119692 Answers: 3 Comments: 1

If x is real number satisfying 3x+(1/(2x))=4 , find the value of 27x^3 +(1/(8x^3 )) .

$${If}\:{x}\:{is}\:{real}\:{number}\:{satisfying} \\ $$$$\mathrm{3}{x}+\frac{\mathrm{1}}{\mathrm{2}{x}}=\mathrm{4}\:,\:{find}\:{the}\:{value}\:{of} \\ $$$$\mathrm{27}{x}^{\mathrm{3}} +\frac{\mathrm{1}}{\mathrm{8}{x}^{\mathrm{3}} }\:. \\ $$

Question Number 119685 Answers: 0 Comments: 0

Question Number 119684 Answers: 1 Comments: 2

Question Number 119681 Answers: 4 Comments: 0

∫_0 ^π (√((1+cos2x)/2)) dx ∫_0 ^∞ [ne^(−x) ]dx

$$\int_{\mathrm{0}} ^{\pi} \sqrt{\frac{\mathrm{1}+{cos}\mathrm{2}{x}}{\mathrm{2}}}\:{dx} \\ $$$$\int_{\mathrm{0}} ^{\infty} \left[{ne}^{−{x}} \right]{dx} \\ $$

Question Number 119679 Answers: 1 Comments: 0

2^1 ×2^2 ×2^3 ×...×2^n =(0.5)^(−45) n=?

$$\mathrm{2}^{\mathrm{1}} ×\mathrm{2}^{\mathrm{2}} ×\mathrm{2}^{\mathrm{3}} ×...×\mathrm{2}^{{n}} =\left(\mathrm{0}.\mathrm{5}\right)^{−\mathrm{45}} \\ $$$${n}=? \\ $$

Question Number 119661 Answers: 0 Comments: 2

point A is at the bottom of a rough plane which is inclined at an angle Θ to the horizontal. A body of mass m is projected from A along and end up a line of greatest slope (along the plane). the cofficient of friction between the body and the plane is ϕ. it then comes to rest at point B at a distance X from A. obtain the expression for (a) the workdone against friction when the body moves from A to B and back to A (ii) initial speed of the body (iii) the speed of the body on its return to A

$${point}\:{A}\:{is}\:{at}\:{the}\:{bottom}\:{of}\:{a}\:{rough}\: \\ $$$${plane}\:{which}\:{is}\:{inclined}\:{at}\:{an}\:{angle}\: \\ $$$$\Theta\:{to}\:{the}\:{horizontal}.\:{A}\:{body}\:{of}\:{mass}\: \\ $$$${m}\:{is}\:{projected}\:{from}\:{A}\:{along}\:{and}\:{end}\: \\ $$$${up}\:{a}\:{line}\:{of}\:{greatest}\:{slope}\:\left({along}\:{the}\right. \\ $$$$\left.{plane}\right).\:{the}\:{cofficient}\:{of}\:{friction}\:{between} \\ $$$${the}\:{body}\:{and}\:{the}\:{plane}\:{is}\:\varphi.\:{it}\:{then}\: \\ $$$${comes}\:{to}\:{rest}\:{at}\:{point}\:{B}\:{at}\:{a}\:{distance}\:{X}\: \\ $$$${from}\:{A}.\:{obtain}\:{the}\:{expression}\:{for} \\ $$$$\left({a}\right)\:{the}\:{workdone}\:{against}\:{friction} \\ $$$${when}\:{the}\:{body}\:{moves}\:{from}\:{A}\:{to}\:{B} \\ $$$${and}\:{back}\:{to}\:{A} \\ $$$$\left({ii}\right)\:{initial}\:{speed}\:{of}\:{the}\:{body} \\ $$$$\left({iii}\right)\:{the}\:{speed}\:{of}\:{the}\:{body}\:{on}\:{its}\: \\ $$$${return}\:{to}\:{A} \\ $$

Question Number 119659 Answers: 2 Comments: 0

∫_0 ^1 [(4x−1)f(12x^2 −6x)]dx=?

$$\int_{\mathrm{0}} ^{\mathrm{1}} \left[\left(\mathrm{4}{x}−\mathrm{1}\right){f}\left(\mathrm{12}{x}^{\mathrm{2}} −\mathrm{6}{x}\right)\right]{dx}=? \\ $$

Question Number 119657 Answers: 1 Comments: 2

Suppose that the greatest common divisor of the positive integers a,b and c is 1 and ((ab)/(a−b)) = c . Prove that a−b is a perfect square

$${Suppose}\:{that}\:{the}\:{greatest}\:{common}\:{divisor}\:{of} \\ $$$${the}\:{positive}\:{integers}\:{a},{b}\:{and}\:{c}\:{is}\:\mathrm{1}\:{and} \\ $$$$\frac{{ab}}{{a}−{b}}\:=\:{c}\:.\:{Prove}\:{that}\:{a}−{b}\:{is}\:{a} \\ $$$${perfect}\:{square} \\ $$

Question Number 119648 Answers: 1 Comments: 1

Particles of mass m_1 and m_2 (m_2 >m_1 ) are connected by a light inextensible string passing over a smooth fixed pulley. initially both masses hang vertically with mass m_(2 ) at a height X above the floor. if the system is released from rest. with what speed will mass m_2 hit the floor and the mass m_1 will rise a further distance of [(((m_2 −m_1 )x)/(m_1 +m_2 ))] after this occur.

$${Particles}\:{of}\:{mass}\:{m}_{\mathrm{1}} \:{and}\:{m}_{\mathrm{2}} \:\left({m}_{\mathrm{2}} >{m}_{\mathrm{1}} \right) \\ $$$${are}\:{connected}\:{by}\:{a}\:{light}\:{inextensible} \\ $$$${string}\:{passing}\:{over}\:{a}\:{smooth}\:{fixed}\: \\ $$$${pulley}.\:{initially}\:{both}\:{masses}\:{hang} \\ $$$${vertically}\:{with}\:{mass}\:{m}_{\mathrm{2}\:} {at}\:{a}\:{height} \\ $$$${X}\:{above}\:{the}\:{floor}.\:{if}\:{the}\:{system}\:{is}\: \\ $$$${released}\:{from}\:{rest}.\:{with}\:{what}\:{speed} \\ $$$${will}\:{mass}\:{m}_{\mathrm{2}} \:{hit}\:{the}\:{floor}\:{and}\:{the} \\ $$$${mass}\:{m}_{\mathrm{1}} \:{will}\:{rise}\:{a}\:{further}\:{distance}\:{of}\: \\ $$$$\left[\frac{\left({m}_{\mathrm{2}} −{m}_{\mathrm{1}} \right){x}}{{m}_{\mathrm{1}} +{m}_{\mathrm{2}} }\right]\:{after}\:{this}\:{occur}. \\ $$

Question Number 119647 Answers: 1 Comments: 0

Question Number 119646 Answers: 0 Comments: 1

Question Number 119645 Answers: 1 Comments: 1

A particle of mass m_1 lies on a smooth horizontal table and its connected to a freely hanging particle of mass m_2 by a light inextensible string passing over a smooth fixed pulley situated at the edge of the table. obtain the expression for the time taken for mass m_(1 ) to reach the edge of the table.

$${A}\:{particle}\:{of}\:{mass}\:{m}_{\mathrm{1}} \:{lies}\:{on}\:{a}\:{smooth} \\ $$$${horizontal}\:{table}\:{and}\:{its}\:{connected}\:{to} \\ $$$${a}\:{freely}\:{hanging}\:{particle}\:{of}\:{mass}\:{m}_{\mathrm{2}} \\ $$$${by}\:{a}\:{light}\:{inextensible}\:{string}\:{passing} \\ $$$${over}\:{a}\:{smooth}\:{fixed}\:{pulley}\:{situated} \\ $$$${at}\:{the}\:{edge}\:{of}\:{the}\:{table}.\:{obtain}\:{the} \\ $$$${expression}\:{for}\:{the}\:{time}\:{taken}\:{for} \\ $$$${mass}\:{m}_{\mathrm{1}\:} {to}\:{reach}\:{the}\:{edge}\:{of}\:{the}\:{table}. \\ $$

Question Number 119644 Answers: 5 Comments: 0

(1) ∫ x^5 (√(x^3 +1)) dx (2) (dy/dx) = (3x−2y+1)^2

$$\:\left(\mathrm{1}\right)\:\int\:{x}^{\mathrm{5}} \:\sqrt{{x}^{\mathrm{3}} +\mathrm{1}}\:{dx}\: \\ $$$$\left(\mathrm{2}\right)\:\frac{{dy}}{{dx}}\:=\:\left(\mathrm{3}{x}−\mathrm{2}{y}+\mathrm{1}\right)^{\mathrm{2}} \\ $$

Question Number 119636 Answers: 1 Comments: 0

Test wheather convergent Σ_(n = 1) ^∞ ((3n − 1)/(7^n + 2n))

$$\mathrm{Test}\:\mathrm{wheather}\:\mathrm{convergent} \\ $$$$\:\:\:\underset{\mathrm{n}\:\:=\:\:\mathrm{1}} {\overset{\infty} {\sum}}\:\:\frac{\mathrm{3n}\:\:−\:\:\mathrm{1}}{\mathrm{7}^{\mathrm{n}} \:\:+\:\:\mathrm{2n}} \\ $$

Question Number 119635 Answers: 1 Comments: 0

If a function f:R→R satisfies the relation f(x+1)+f(x−1)=(√3)f(x) for all x∈R then a period of f is (A) 10 (B) 12 (C) 6 (D) 4

$$\mathrm{If}\:\mathrm{a}\:\mathrm{function}\:{f}:\mathbb{R}\rightarrow\mathbb{R}\:\mathrm{satisfies}\:\mathrm{the}\:\mathrm{relation} \\ $$$$\:\:\:\:\:\:\:{f}\left(\mathrm{x}+\mathrm{1}\right)+{f}\left(\mathrm{x}−\mathrm{1}\right)=\sqrt{\mathrm{3}}{f}\left(\mathrm{x}\right)\:\mathrm{for}\:\mathrm{all}\:\mathrm{x}\in\mathbb{R} \\ $$$$\mathrm{then}\:\mathrm{a}\:\mathrm{period}\:\mathrm{of}\:{f}\:\mathrm{is} \\ $$$$\left(\mathrm{A}\right)\:\mathrm{10}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{B}\right)\:\mathrm{12}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{C}\right)\:\mathrm{6}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{D}\right)\:\mathrm{4} \\ $$

Question Number 119634 Answers: 2 Comments: 0

Q1 If f:R→R is defined by f(x)=[x]+[x+(1/2)]+[x+(2/3)]−3x+5 where [x] is the integral part of x, then a period of f is (A) 1 (B) 2/3 (C) 1/2 (D) 1/3 Q2 Let a<c<b such that c−a=b−c. If f:R→R is a function satisfying the relation f(x+a)+f(x+b)=f(x+c) for all x∈R then a period of f is (A) (b−a) (B) 2(b−a) (C) 3(b−a) (D) 4(b−a)

Question Number 119629 Answers: 1 Comments: 0

Question Number 119618 Answers: 1 Comments: 0

Question Number 119611 Answers: 0 Comments: 0

Question Number 119600 Answers: 2 Comments: 0

Find gcd of x^4 +x^3 −4x^2 +x+5 and x^3 +x^2 −9x−9

$${Find}\:{gcd}\:{of}\:{x}^{\mathrm{4}} +{x}^{\mathrm{3}} −\mathrm{4}{x}^{\mathrm{2}} +{x}+\mathrm{5}\: \\ $$$${and}\:{x}^{\mathrm{3}} +{x}^{\mathrm{2}} −\mathrm{9}{x}−\mathrm{9} \\ $$

Question Number 119588 Answers: 1 Comments: 0

Question Number 119580 Answers: 3 Comments: 0

Given k ∈ N. 1) justify these relations: 3^(2k) +1≡2[8] and 3^(2k+1) +1≡4[8]. 2) Given (E): 2^n −3^m =1. n and m are unknowed. • Show that if m is even , (E) does not have solution. ■ Deduct from the first question 1) that the couple (2;1) is the only solution of (E).

$$\mathrm{Given}\:\mathrm{k}\:\in\:\mathbb{N}. \\ $$$$\left.\mathrm{1}\right)\:\mathrm{justify}\:\mathrm{these}\:\mathrm{relations}: \\ $$$$\mathrm{3}^{\mathrm{2k}} +\mathrm{1}\equiv\mathrm{2}\left[\mathrm{8}\right]\:\mathrm{and}\:\mathrm{3}^{\mathrm{2k}+\mathrm{1}} +\mathrm{1}\equiv\mathrm{4}\left[\mathrm{8}\right]. \\ $$$$\left.\mathrm{2}\right)\:\mathrm{Given}\:\left(\mathrm{E}\right):\:\mathrm{2}^{\mathrm{n}} −\mathrm{3}^{\mathrm{m}} =\mathrm{1}.\:\mathrm{n}\:\mathrm{and}\:\mathrm{m}\:\mathrm{are}\:\mathrm{unknowed}. \\ $$$$\bullet\:\mathrm{Show}\:\mathrm{that}\:\mathrm{if}\:\mathrm{m}\:\mathrm{is}\:\mathrm{even}\:,\:\left(\mathrm{E}\right)\:\mathrm{does}\:\mathrm{not}\:\mathrm{have}\: \\ $$$$\mathrm{solution}. \\ $$$$\left.\blacksquare\:\mathrm{Deduct}\:\mathrm{from}\:\mathrm{the}\:\mathrm{first}\:\mathrm{question}\:\mathrm{1}\right)\:\mathrm{that}\:\mathrm{the} \\ $$$$\mathrm{couple}\:\left(\mathrm{2};\mathrm{1}\right)\:\mathrm{is}\:\mathrm{the}\:\mathrm{only}\:\mathrm{solution}\:\mathrm{of}\:\left(\mathrm{E}\right). \\ $$

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