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Question Number 212017    Answers: 0   Comments: 0

Question Number 212016    Answers: 0   Comments: 0

Question Number 212015    Answers: 0   Comments: 0

f(arcsin (y/x))=xy (dy/dx)=?

$${f}\left(\mathrm{arcsin}\:\frac{{y}}{{x}}\right)={xy}\:\:\:\:\:\:\frac{{dy}}{{dx}}=? \\ $$$$\:\:\:\: \\ $$

Question Number 212011    Answers: 0   Comments: 2

Determiner: R1 R2 R3 pour b=12cm EF // MN ; EF Tangent aux cercles: C1(R1) C2(R2) ; EF=a MN=b MN: tangent au cercle C2 OM=ON=((3a)/2) ∡MON=2x

$$\boldsymbol{\mathrm{D}}\mathrm{eterminer}:\:\:\boldsymbol{\mathrm{R}}\mathrm{1}\:\:\:\boldsymbol{\mathrm{R}}\mathrm{2}\:\:\:\boldsymbol{\mathrm{R}}\mathrm{3} \\ $$$$\boldsymbol{\mathrm{pour}}\:\:\:\boldsymbol{\mathrm{b}}=\mathrm{12}\boldsymbol{\mathrm{cm}}\:\:\:\: \\ $$$$\boldsymbol{\mathrm{EF}}\://\:\boldsymbol{\mathrm{MN}}\:;\:\:\boldsymbol{\mathrm{EF}}\:\boldsymbol{\mathrm{Tangent}}\:\boldsymbol{\mathrm{aux}}\:\boldsymbol{\mathrm{cercles}}:\: \\ $$$$\:\:\boldsymbol{\mathrm{C}}\mathrm{1}\left(\boldsymbol{\mathrm{R}}\mathrm{1}\right)\:\:\:\boldsymbol{\mathrm{C}}\mathrm{2}\left(\boldsymbol{\mathrm{R}}\mathrm{2}\right)\:\:;\:\:\:\boldsymbol{\mathrm{EF}}=\boldsymbol{\mathrm{a}}\:\:\:\:\:\:\boldsymbol{\mathrm{MN}}=\boldsymbol{\mathrm{b}} \\ $$$$\boldsymbol{\mathrm{MN}}:\:\boldsymbol{\mathrm{tangent}}\:\boldsymbol{\mathrm{au}}\:\boldsymbol{\mathrm{cercle}}\:\boldsymbol{\mathrm{C}}\mathrm{2} \\ $$$$\boldsymbol{\mathrm{OM}}=\boldsymbol{\mathrm{ON}}=\frac{\mathrm{3}\boldsymbol{\mathrm{a}}}{\mathrm{2}}\:\:\:\:\:\:\:\:\measuredangle\mathrm{MON}=\mathrm{2}\boldsymbol{\mathrm{x}}\:\:\: \\ $$$$ \\ $$

Question Number 212007    Answers: 1   Comments: 0

∫sin(x) ((tan(x)))^(1/3) .dx

$$\:\:\:\:\int\boldsymbol{{sin}}\left(\boldsymbol{{x}}\right)\:\sqrt[{\mathrm{3}}]{\boldsymbol{{tan}}\left(\boldsymbol{{x}}\right)}\:.\boldsymbol{{dx}} \\ $$

Question Number 212006    Answers: 1   Comments: 0

Question Number 212002    Answers: 0   Comments: 0

Question Number 212001    Answers: 1   Comments: 0

prove that: Σ_(k∈Z) (( (−1)^k )/( x + kπ)) = (1/(sin(x))) −−−−−−−−−

$$ \\ $$$$\:\:\:\:{prove}\:\:{that}: \\ $$$$ \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\underset{{k}\in\mathbb{Z}} {\sum}\:\frac{\:\left(−\mathrm{1}\right)^{{k}} }{\:{x}\:+\:{k}\pi}\:=\:\frac{\mathrm{1}}{{sin}\left({x}\right)}\:\:\: \\ $$$$\:\:\:\:\:\:\:\:−−−−−−−−− \\ $$

Question Number 212024    Answers: 2   Comments: 0

Question Number 212023    Answers: 3   Comments: 0

Question Number 211995    Answers: 1   Comments: 2

∫(√)tanx dx

$$\int\sqrt{}{tanx}\:{dx} \\ $$

Question Number 211992    Answers: 1   Comments: 2

Question Number 211989    Answers: 1   Comments: 0

Question Number 211987    Answers: 0   Comments: 2

Question Number 211986    Answers: 2   Comments: 0

Question Number 211979    Answers: 1   Comments: 0

Question Number 211961    Answers: 2   Comments: 0

if 7^(sin^(2 ) x) + 7^(cos^2 x) = 8 find x

$$\:\:\:\boldsymbol{{if}}\:\:\:\mathrm{7}^{\boldsymbol{{sin}}^{\mathrm{2}\:} \boldsymbol{{x}}} +\:\mathrm{7}^{\boldsymbol{{cos}}^{\mathrm{2}} \boldsymbol{{x}}} =\:\mathrm{8}\:\boldsymbol{{find}}\:\boldsymbol{{x}} \\ $$

Question Number 211956    Answers: 1   Comments: 0

Question Number 211954    Answers: 1   Comments: 0

x,y are rational numbers where x≠0, y≠0, x≠y, then is it possible: x^5 +y^5 =2x^2 y^2 ?

$$\:{x},{y}\:{are}\:{rational}\:{numbers}\:{where} \\ $$$$\:{x}\neq\mathrm{0},\:{y}\neq\mathrm{0},\:{x}\neq{y},\:{then}\:{is}\:{it}\: \\ $$$$\:{possible}:\:\:{x}^{\mathrm{5}} +{y}^{\mathrm{5}} =\mathrm{2}{x}^{\mathrm{2}} {y}^{\mathrm{2}} \:? \\ $$

Question Number 211953    Answers: 1   Comments: 2

Question Number 211949    Answers: 1   Comments: 0

Question Number 211946    Answers: 2   Comments: 0

Question Number 211944    Answers: 1   Comments: 0

f(x)=(((√(1+x))−(√(1−x)))/( (√(1+x))+(√(1−x)))) f^′ (x)=?

$$ \\ $$$${f}\left({x}\right)=\frac{\sqrt{\mathrm{1}+{x}}−\sqrt{\mathrm{1}−{x}}}{\:\sqrt{\mathrm{1}+{x}}+\sqrt{\mathrm{1}−{x}}}\:\:\:\:{f}^{'} \left({x}\right)=? \\ $$$$ \\ $$$$ \\ $$

Question Number 211943    Answers: 2   Comments: 1

2^(m−1) =1+mn m, n ∈Z

$$\mathrm{2}^{{m}−\mathrm{1}} =\mathrm{1}+{mn} \\ $$$${m},\:{n}\:\in\mathbb{Z} \\ $$

Question Number 211932    Answers: 0   Comments: 4

determiner R1 R2 et R3 segment de longueur a est tangent aux cercles 1et 2. MN//EF; EF=a; OM=ON=((3a)/2). (length a is tangent to cirles C1 (radius R1)and circldC2(radius R2)).

$$\mathrm{determiner}\:\:\:\:\boldsymbol{\mathrm{R}}\mathrm{1}\:\:\:\:\boldsymbol{\mathrm{R}}\mathrm{2}\:\mathrm{et}\:\boldsymbol{\mathrm{R}}\mathrm{3} \\ $$$$\mathrm{segment}\:\mathrm{de}\:\mathrm{longueur}\:\boldsymbol{\mathrm{a}}\:\boldsymbol{\mathrm{est}}\:\boldsymbol{\mathrm{tangent}}\:\boldsymbol{\mathrm{aux}} \\ $$$$\boldsymbol{\mathrm{cercles}}\:\mathrm{1}\boldsymbol{\mathrm{et}}\:\mathrm{2}. \\ $$$$\:\boldsymbol{\mathrm{MN}}//\boldsymbol{\mathrm{EF}};\:\:\boldsymbol{\mathrm{EF}}=\boldsymbol{\mathrm{a}};\:\:\mathrm{OM}=\mathrm{ON}=\frac{\mathrm{3}\boldsymbol{\mathrm{a}}}{\mathrm{2}}. \\ $$$$\left(\mathrm{length}\:\boldsymbol{\mathrm{a}}\:\mathrm{is}\:\mathrm{tangent}\:\mathrm{to}\:\mathrm{cirles}\:\mathrm{C1}\:\left(\mathrm{radius}\:\mathrm{R1}\right)\mathrm{and}\:\mathrm{circldC2}\left(\mathrm{radius}\:\mathrm{R2}\right)\right). \\ $$

Question Number 211920    Answers: 1   Comments: 0

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