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Let two roots of the equation x^2 +2mx+m^2 −2m+3=0 is α, β(For α<β), (2) Find (α−β)^2 Using m. (3) If β−α=2, Solve for m. If you don′t solve it, I will force you to solve.

$$\mathrm{Let}\:\mathrm{two}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation}\:{x}^{\mathrm{2}} +\mathrm{2}{mx}+{m}^{\mathrm{2}} −\mathrm{2}{m}+\mathrm{3}=\mathrm{0}\:\mathrm{is}\:\alpha,\:\beta\left(\mathrm{For}\:\alpha<\beta\right), \\ $$$$\left(\mathrm{2}\right)\:\mathrm{Find}\:\left(\alpha−\beta\right)^{\mathrm{2}} \:\mathrm{Using}\:{m}. \\ $$$$\left(\mathrm{3}\right)\:\mathrm{If}\:\beta−\alpha=\mathrm{2},\:\mathrm{Solve}\:\mathrm{for}\:{m}. \\ $$$$\mathrm{If}\:\mathrm{you}\:\mathrm{don}'\mathrm{t}\:\mathrm{solve}\:\mathrm{it},\:\mathrm{I}\:\mathrm{will}\:\mathrm{force}\:\mathrm{you}\:\mathrm{to}\:\mathrm{solve}. \\ $$

Question Number 215167 Answers: 1 Comments: 0

If the quadratic equation x^2 −2x−m+1=0 has two different positive real roots α, β, Determine the range of m (For example, 0<m<3) or I will force you to determine

$$\mathrm{If}\:\mathrm{the}\:\mathrm{quadratic}\:\mathrm{equation}\:{x}^{\mathrm{2}} −\mathrm{2}{x}−{m}+\mathrm{1}=\mathrm{0}\:\mathrm{has}\:\mathrm{two}\:\mathrm{different}\:\mathrm{positive}\:\mathrm{real}\:\mathrm{roots}\:\alpha,\:\beta, \\ $$$$\mathrm{Determine}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:{m}\:\left(\mathrm{For}\:\mathrm{example},\:\mathrm{0}<{m}<\mathrm{3}\right)\:\mathrm{or}\:\mathrm{I}\:\mathrm{will}\:\mathrm{force}\:\mathrm{you}\:\mathrm{to}\:\mathrm{determine} \\ $$

Question Number 215166 Answers: 1 Comments: 0

If the quadratic equation 3x^2 +8x+2k=0 has two different negative real roots, Determine the range of k (For example, 0<k<3) or I will force you to determine

$$\mathrm{If}\:\mathrm{the}\:\mathrm{quadratic}\:\mathrm{equation}\:\mathrm{3}{x}^{\mathrm{2}} +\mathrm{8}{x}+\mathrm{2}{k}=\mathrm{0}\:\mathrm{has}\:\mathrm{two}\:\mathrm{different}\:\mathrm{negative}\:\mathrm{real}\:\mathrm{roots}, \\ $$$$\mathrm{Determine}\:\mathrm{the}\:\mathrm{range}\:\mathrm{of}\:{k}\:\left(\mathrm{For}\:\mathrm{example},\:\mathrm{0}<{k}<\mathrm{3}\right)\:\mathrm{or}\:\mathrm{I}\:\mathrm{will}\:\mathrm{force}\:\mathrm{you}\:\mathrm{to}\:\mathrm{determine} \\ $$

Question Number 215164 Answers: 1 Comments: 0

Let the two roots of the quadratic equation x^2 −12x+k=0 is α, α^2 , Then solve for α and k or I will force you to solve

$$\mathrm{Let}\:\mathrm{the}\:\mathrm{two}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{quadratic}\:\mathrm{equation}\:{x}^{\mathrm{2}} −\mathrm{12}{x}+{k}=\mathrm{0}\:\mathrm{is}\:\alpha,\:\alpha^{\mathrm{2}} , \\ $$$$\mathrm{Then}\:\mathrm{solve}\:\mathrm{for}\:\alpha\:\mathrm{and}\:{k}\:\mathrm{or}\:\mathrm{I}\:\mathrm{will}\:\mathrm{force}\:\mathrm{you}\:\mathrm{to}\:\mathrm{solve} \\ $$

Question Number 215161 Answers: 1 Comments: 4

∫(((x^8 +16x^7 −2x^4 −3)e^x )/((1+x^4 )^(2/3) ))dx

$$ \\ $$$$\:\:\:\:\:\:\int\frac{\left({x}^{\mathrm{8}} +\mathrm{16}{x}^{\mathrm{7}} −\mathrm{2}{x}^{\mathrm{4}} −\mathrm{3}\right){e}^{{x}} }{\left(\mathrm{1}+{x}^{\mathrm{4}} \right)^{\mathrm{2}/\mathrm{3}} }{dx} \\ $$$$ \\ $$

Question Number 215147 Answers: 2 Comments: 0