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Question Number 146230 Answers: 1 Comments: 0

(1/(cos^2 (x))) - 1 + (1/(cos(x))) = 1 ⇒ x=?

$$\frac{\mathrm{1}}{{cos}^{\mathrm{2}} \left({x}\right)}\:-\:\mathrm{1}\:+\:\frac{\mathrm{1}}{{cos}\left({x}\right)}\:=\:\mathrm{1}\:\Rightarrow\:{x}=? \\ $$

Question Number 146227 Answers: 2 Comments: 0

tg^2 (x) - (1/(cos(x))) = 1 ⇒ x=?

$${tg}^{\mathrm{2}} \left({x}\right)\:-\:\frac{\mathrm{1}}{{cos}\left({x}\right)}\:=\:\mathrm{1}\:\Rightarrow\:{x}=? \\ $$

Question Number 146224 Answers: 2 Comments: 0

Question Number 146202 Answers: 3 Comments: 0

∫((lnx)/(x−1))dx=....??? La primitive

$$\int\frac{{lnx}}{{x}−\mathrm{1}}{dx}=....??? \\ $$$${La}\:{primitive} \\ $$

Question Number 146201 Answers: 1 Comments: 0

Solve for natural numbers the equation: 3x^2 + 15y^2 = 5z^2 + t^2

$${Solve}\:{for}\:{natural}\:{numbers}\:{the}\:{equation}: \\ $$$$\mathrm{3}{x}^{\mathrm{2}} \:+\:\mathrm{15}{y}^{\mathrm{2}} \:=\:\mathrm{5}{z}^{\mathrm{2}} \:+\:{t}^{\mathrm{2}} \\ $$

Question Number 146215 Answers: 3 Comments: 0

∫ (dx/(x(√(x^2 −4)))) = ?

$$\int\:\frac{{dx}}{{x}\sqrt{{x}^{\mathrm{2}} −\mathrm{4}}}\:=\:? \\ $$

Question Number 146196 Answers: 2 Comments: 0

calculate ∫_0 ^∞ (dx/((2x+1)^4 (x+3)^5 ))

$$\mathrm{calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{\mathrm{dx}}{\left(\mathrm{2x}+\mathrm{1}\right)^{\mathrm{4}} \left(\mathrm{x}+\mathrm{3}\right)^{\mathrm{5}} } \\ $$

Question Number 146197 Answers: 2 Comments: 0

calculate ∫_(−∞) ^(+∞) (dx/((x^2 −x+1)^3 ))

$$\mathrm{calculate}\:\int_{−\infty} ^{+\infty} \:\frac{\mathrm{dx}}{\left(\mathrm{x}^{\mathrm{2}} −\mathrm{x}+\mathrm{1}\right)^{\mathrm{3}} } \\ $$

Question Number 146194 Answers: 1 Comments: 0

calculate Σ_(n=1) ^∞ (1/(n^3 5^n ))

$$\mathrm{calculate}\:\sum_{\mathrm{n}=\mathrm{1}} ^{\infty} \:\frac{\mathrm{1}}{\mathrm{n}^{\mathrm{3}} \mathrm{5}^{\mathrm{n}} } \\ $$

Question Number 146193 Answers: 2 Comments: 0

solve y^(′′) −y^′ + y=xe^(−x)

$$\mathrm{solve}\:\mathrm{y}^{''} \:−\mathrm{y}^{'} \:+\:\mathrm{y}=\mathrm{xe}^{−\mathrm{x}} \\ $$

Question Number 146183 Answers: 1 Comments: 1

Question Number 146181 Answers: 4 Comments: 0

Σ_(n=0) ^∞ (1/(2^( n) (n+1 ) ( n + 2 ))) =?

$$ \\ $$$$\:\:\:\:\:\:\:\:\underset{{n}=\mathrm{0}} {\overset{\infty} {\sum}}\frac{\mathrm{1}}{\mathrm{2}^{\:{n}} \:\left({n}+\mathrm{1}\:\right)\:\left(\:{n}\:+\:\mathrm{2}\:\right)}\:=? \\ $$

Question Number 146180 Answers: 0 Comments: 0

theorem: statement: The right bisectors of the sides of a triangle are congruent.

$$\mathrm{theorem}:\:\:\:\mathrm{statement}:\:\mathrm{The}\:\mathrm{right}\:\mathrm{bisectors}\:\mathrm{of}\:\mathrm{the}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{are}\:\mathrm{congruent}. \\ $$

Question Number 146176 Answers: 0 Comments: 0

Question Number 146174 Answers: 0 Comments: 0

calculer lim_(x→1) (x−1)Σ_(n≥0) (1/n^x )

$${calculer}\:{lim}_{{x}\rightarrow\mathrm{1}} \left({x}−\mathrm{1}\right)\underset{{n}\geqslant\mathrm{0}} {\sum}\frac{\mathrm{1}}{{n}^{{x}} } \\ $$

Question Number 146173 Answers: 0 Comments: 0

prove that w = ((N!)/(n_1 ! n_2 !))

$$\mathrm{prove}\:\mathrm{that}\:\:\:\:\:\:\mathrm{w}\:=\:\frac{\mathrm{N}!}{\mathrm{n}_{\mathrm{1}} !\:\mathrm{n}_{\mathrm{2}} !} \\ $$

Question Number 146172 Answers: 0 Comments: 0

Is there any book where the topic “ inverse trigonometric function” has given in full details ?

$$\mathrm{Is}\:\mathrm{there}\:\mathrm{any}\:\mathrm{book}\:\mathrm{where}\:\mathrm{the}\:\mathrm{topic}\:``\:\boldsymbol{\mathrm{inverse}} \\ $$$$\boldsymbol{\mathrm{trigonometric}}\:\boldsymbol{\mathrm{function}}''\:\mathrm{has}\:\mathrm{given}\:\mathrm{in}\:\mathrm{full}\: \\ $$$$\mathrm{details}\:? \\ $$

Question Number 146170 Answers: 2 Comments: 0

lim_(x→2) (x^2 −4)tan ((π/x))=?

$$\:\:\:\:\:\:\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\left({x}^{\mathrm{2}} −\mathrm{4}\right)\mathrm{tan}\:\left(\frac{\pi}{{x}}\right)=? \\ $$

Question Number 146164 Answers: 1 Comments: 0

calulate :: S : = Σ_(n=1) ^∞ (( H_((n/2) ) )/( 2^( n) )) =? .......m.n.

$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{calulate}\::: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{S}\::\:=\:\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\:\mathrm{H}_{\frac{{n}}{\mathrm{2}}\:} }{\:\mathrm{2}^{\:{n}} }\:=? \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:.......{m}.{n}. \\ $$

Question Number 146158 Answers: 1 Comments: 1

Question Number 146157 Answers: 3 Comments: 0

Question Number 146156 Answers: 0 Comments: 0

Question Number 146155 Answers: 0 Comments: 2

lim_(n→∞) (Arcsin(x))^( n) =0 ∴ x ∈ ? Q : mr liberty

$$ \\ $$$$\:\:\:\:\:\:{lim}_{{n}\rightarrow\infty} \:\left({Arcsin}\left({x}\right)\right)^{\:{n}} =\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\therefore\:\:\:\:\:\:\:{x}\:\in\:?\: \\ $$$$\:\:\:\:\:\:{Q}\::\:{mr}\:{liberty} \\ $$$$\:\:\:\:\:\:\:\:\:\:\: \\ $$

Question Number 146154 Answers: 0 Comments: 0

Question Number 146146 Answers: 0 Comments: 1

to admin tinku tara. why can't i post in hebrew ?

$$ \\ $$to admin tinku tara. why can't i post in hebrew ?

Question Number 146141 Answers: 0 Comments: 4

An incident ray is reflected normally by a plane mirror onto a screen where it forms a bright spot. The mirror and screen are parallel and 1m apart. If the mirror is rotated through 5°, calculate the displacement of the spot

$$ \\ $$An incident ray is reflected normally by a plane mirror onto a screen where it forms a bright spot. The mirror and screen are parallel and 1m apart. If the mirror is rotated through 5°, calculate the displacement of the spot

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