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Question Number 215559 Answers: 2 Comments: 0

(√y) + (√x) = 5 (√x) ∙ (√y) = 8 (((√x) y − x (√y))/(y − x)) = ?

$$\sqrt{\mathrm{y}}\:+\:\sqrt{\mathrm{x}}\:=\:\mathrm{5} \\ $$$$\sqrt{\mathrm{x}}\:\centerdot\:\sqrt{\mathrm{y}}\:=\:\mathrm{8} \\ $$$$\frac{\sqrt{\mathrm{x}}\:\mathrm{y}\:−\:\mathrm{x}\:\sqrt{\mathrm{y}}}{\mathrm{y}\:−\:\mathrm{x}}\:=\:? \\ $$

Question Number 215550 Answers: 1 Comments: 0

Let u^((1)) ,u^((2)) s.t. { ((u_(tt) ^((1)) =((∂^2 /∂x_1 ^2 )+(∂^2 /∂x_i ^2 ))u^((1)) )),((u^((1)) (x_1 ,x_2 ,0)=𝛙(x_1 ,x_2 ))),((u^((1)) (x_1 ,x_2 ,0)=0)) :}, { ((u_(tt) ^((2)) =((∂^2 /∂x_1 ^2 )+(∂^2 /∂x_2 ^2 )+c^2 )u^((2)) )),((u^((2)) (x_1 x_2 ,0)=0)),((u_t ^((2)) (x_1 ,x_2 ,0)=𝛙(x_1 ,x_2 ))) :} prove:u^((2)) (x_1 ,x_2 ,t)=(1/(2𝛑))∫∫_(𝛏_1 ^2 +𝛏_2 ^2 ≤t^2 ) ((e^(𝛏_2 c) u^((1)) (x_1 ,x_2 ,𝛏_1 )d𝛏_1 d𝛏_2 )/( (√(t^2 −𝛏_1 ^2 −𝛏_2 ^2 ))))

Question Number 215540 Answers: 1 Comments: 0

∫_(Σ_(1≤i≤n) x_i ^2 ≤1) (Σ_(1≤i≤n) x_i ^2 )^m (Σ_(1≤i≤n) a_i x_i )^(2k) Π_(1≤i≤n) dx_i

$$\int_{\underset{\mathrm{1}\leq{i}\leq{n}} {\sum}{x}_{{i}} ^{\mathrm{2}} \leq\mathrm{1}} \left(\underset{\mathrm{1}\leq{i}\leq{n}} {\sum}{x}_{{i}} ^{\mathrm{2}} \right)^{{m}} \left(\underset{\mathrm{1}\leq{i}\leq{n}} {\sum}{a}_{{i}} {x}_{{i}} \right)^{\mathrm{2}{k}} \underset{\mathrm{1}\leq{i}\leq{n}} {\prod}{dx}_{{i}} \\ $$

Question Number 215535 Answers: 1 Comments: 0

∫_(Σ_(1≤i≤n) x_i ^2 ≤R^2 ) Σ_(1≤i≤n) x_i (∂f/∂x_i )Π_(1≤i≤n) dx_i =?

$$\int_{\underset{\mathrm{1}\leq{i}\leq{n}} {\sum}{x}_{{i}} ^{\mathrm{2}} \leq{R}^{\mathrm{2}} } \underset{\mathrm{1}\leq{i}\leq{n}} {\sum}{x}_{{i}} \frac{\partial{f}}{\partial{x}_{{i}} }\underset{\mathrm{1}\leq{i}\leq{n}} {\prod}{dx}_{{i}} =? \\ $$

Question Number 215525 Answers: 1 Comments: 0

Φ :R^2 →R^2 (x.;y)∣→(2x+3y:3y) find Φ∈L(R^2 ) find ker(Φ) and the im(Φ) f o f =?

$$\Phi\::\mathbb{R}^{\mathrm{2}} \rightarrow\mathbb{R}^{\mathrm{2}} \: \\ $$$$\:\:\:\left({x}.;{y}\right)\mid\rightarrow\left(\mathrm{2}{x}+\mathrm{3}{y}:\mathrm{3}{y}\right) \\ $$$${find} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$\Phi\in\mathscr{L}\left(\mathbb{R}^{\mathrm{2}} \right) \\ $$$${find}\:{ker}\left(\Phi\right)\:{and}\:{the}\:{im}\left(\Phi\right) \\ $$$${f}\:{o}\:{f}\:=? \\ $$$$ \\ $$

Question Number 215523 Answers: 2 Comments: 2

Two friends set off by train at dawn to visit each other. The two friends caught sight of each other through the window as the trains passed in opposite direction on adjacent tracks− it was 12^(oo) hours. The friends helplessly reached their destinations. If the first of them reached their destination at 16^(oo) and the second at 21^(oo) , what time did dawn break on that day ? Help me, please

$$ \\ $$$$\:\:\:\mathcal{T}{wo}\:{friends}\:{set}\:{off}\:\:{by}\:{train}\:{at}\:{dawn}\:{to}\:{visit} \\ $$$$\:\:\:{each}\:{other}.\:{The}\:{two}\:{friends}\:{caught}\:{sight}\:{of} \\ $$$$\:\:\:{each}\:{other}\:{through}\:{the}\:{window}\:{as}\:{the}\:{trains}\: \\ $$$$\:\:\:{passed}\:{in}\:{opposite}\:{direction}\:{on}\:{adjacent}\:{tracks}− \\ $$$$\:\:\:{it}\:{was}\:\mathrm{12}^{{oo}} \:{hours}.\:{The}\:{friends}\:{helplessly}\:{reached}\: \\ $$$$\:\:\:{their}\:{destinations}.\:{If}\:{the}\:{first}\:{of}\:{them}\:{reached}\: \\ $$$$\:\:\:{their}\:{destination}\:{at}\:\mathrm{16}^{{oo}} \:{and}\:{the}\:{second}\:{at}\:\mathrm{21}^{{oo}} , \\ $$$$\:\:\:{what}\:{time}\:{did}\:{dawn}\:{break}\:{on}\:{that}\:{day}\:? \\ $$$$\:\:\:{Help}\:{me},\:{please} \\ $$

Question Number 215520 Answers: 2 Comments: 0

Prove that { ((x = ((7 cos t − 2)/(2 − cos t)))),((y = ((4(√3) sin t)/(2 − cos t)))) :} is a circle.

$$\mathrm{Prove}\:\mathrm{that}\:\begin{cases}{{x}\:=\:\frac{\mathrm{7}\:\mathrm{cos}\:{t}\:−\:\mathrm{2}}{\mathrm{2}\:−\:\mathrm{cos}\:{t}}}\\{{y}\:=\:\frac{\mathrm{4}\sqrt{\mathrm{3}}\:\mathrm{sin}\:{t}}{\mathrm{2}\:−\:\mathrm{cos}\:{t}}}\end{cases}\:\mathrm{is}\:\mathrm{a}\:\mathrm{circle}. \\ $$

Question Number 215519 Answers: 1 Comments: 0

Find ((y/x))^(log_(x/y) (y/x) ) below: 2x^2 + xy − 3y^2 = 0

$$ \\ $$$$\:\:\:\:\:\:\:\boldsymbol{\mathrm{Find}}\:\left(\frac{\boldsymbol{\mathrm{y}}}{\boldsymbol{\mathrm{x}}}\right)^{\boldsymbol{\mathrm{log}}_{\frac{\boldsymbol{\mathrm{x}}}{\boldsymbol{\mathrm{y}}}} \frac{\boldsymbol{\mathrm{y}}}{\boldsymbol{\mathrm{x}}}\:} \boldsymbol{\mathrm{below}}: \\ $$$$ \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{2}\boldsymbol{\mathrm{x}}^{\mathrm{2}} \:+\:\boldsymbol{\mathrm{xy}}\:−\:\mathrm{3}\boldsymbol{\mathrm{y}}^{\mathrm{2}} \:=\:\mathrm{0} \\ $$$$ \\ $$

Question Number 215504 Answers: 1 Comments: 0

simplify a−{b^(c−b) +⟨(b^(c−b) )^2 +((a/2))^2 ⟩+(a/2)}+c^(ab−c) −c^(a−c)

$$\mathrm{simplify}\:{a}−\left\{{b}^{{c}−{b}} +\langle\left({b}^{{c}−{b}} \right)^{\mathrm{2}} +\left(\frac{{a}}{\mathrm{2}}\right)^{\mathrm{2}} \rangle+\frac{{a}}{\mathrm{2}}\right\}+{c}^{{ab}−{c}} −{c}^{{a}−{c}} \\ $$

Question Number 215527 Answers: 1 Comments: 0

t_(33) ′ab+t_(00) ′ab=? Clearing up defintions: t_(33) ′a=(a−(√(36)))×3 t_(00) ′a=(a−(√(36)))×0 t′a=a−(√(36)) t′a= “transformation” of a